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6.4 Special Parallelograms Standard: 7.0 & 12.0.

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Presentation on theme: "6.4 Special Parallelograms Standard: 7.0 & 12.0."— Presentation transcript:

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3 6.4 Special Parallelograms Standard: 7.0 & 12.0

4 Properties of Special Parallelograms Types of parallelograms: rhombuses, rectangles and squares. A rhombus is a parallelogram with four congruent sides A rectangle is a parallelogram with four right angles. A square is a parallelogram with four congruent sides and four right angles.

5 Ex. 1: Using properties of special parallelograms Rhombus Theorem 6-9 Each diagonal bisect two angles of the rhombus. Theorem 6-10 The diagonals of a rhombus are perpendicular.

6 Ex. 2: Using properties of special parallelograms Rectangle Theorem 6-11 Diagonals of a rectangle are congruent.

7 Ex. 3: Using properties of a Rhombus In the diagram at the right, PQRS is a rhombus. What is the value of y? All four sides of a rhombus are ≅, so RS = PS. 5y – 6 = 2y + 3 5y = 2y + 9Add 6 to each side. 3y = 9Subtract 2y from each side. y = 3Divide each side by 3.

8 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given

9 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given

10 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given 3. Diagonals bisect each other.

11 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given 3. Diagonals bisect each other. 4. Diagonals bisect each other.

12 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given 3. Diagonals bisect each other. 4. Diagonals bisect each other. 5. SSS congruence post.

13 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given 3. Diagonals bisect each other. 4. Diagonals bisect each other. 5. SSS 6. CPCTC

14 Ex. 4: Proving Theorem 6.10 Given: ABCD is a rhombus Prove: AC  BD Statements: 1. ABCD is a rhombus 2. AB ≅ CB  AX ≅ CX  BX ≅ DX 5. ∆AXB ≅ ∆CXB 6.  AXB ≅  CXB  AC  BD Reasons: 1. Given 2. Given 3. Diagonals bisect each other. 4. Diagonals bisect each other. 5. SSS 6. CPCTC 7. Congruent Adjacent  s


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