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Proofs of Theorems and Glossary of Terms Menu Theorem 4 Three angles in any triangle add up to 180°. Theorem 6 Each exterior angle of a triangle is equal.

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Presentation on theme: "Proofs of Theorems and Glossary of Terms Menu Theorem 4 Three angles in any triangle add up to 180°. Theorem 6 Each exterior angle of a triangle is equal."— Presentation transcript:

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2 Proofs of Theorems and Glossary of Terms

3 Menu Theorem 4 Three angles in any triangle add up to 180°. Theorem 6 Each exterior angle of a triangle is equal to the sum of the two interior opposite angles Theorem 9 In a parallelogram opposite sides are equal and opposite angle are equal Theorem 19 The angle at the centre of the circle standing on a given arc is twice the angle at any point of the circle standing on the same arc. Theorem 14 Theorem of Pythagoras : In a right angle triangle, the square of the hypotenuse is the sum of the squares of the other two sides Just Click on the Proof Required Go to JC Constructions

4 Proof:  3 +  4 +  5 = 180 0 Straight line  1 =  4 and  2 = 55 Alternate angles  3 +  1 +  2 = 180 0  1 +  2 +  3 = 180 0 Q.E.D. 45 Given: Given:Triangle 12 3 Construction: Construction:Draw line through  3 parallel to the base Theorem 4: Three angles in any triangle add up to 180°C. To Prove: To Prove:  1 +  2 +  3 = 180 0 Menu Constructions Quit Use mouse clicks to see proof

5 0 180 90 45 135 Theorem 6: Theorem 6: Each exterior angle of a triangle is equal to the sum of the two interior opposite angles To Prove: To Prove:  1 =  3 +  4 Proof:  1 +  2 = 180 0 ………….. Straight line  2 +  3 +  4 = 180 0 ………….. Theorem 2.  1 +  2 =  2 +  3 +  4  1 =  3 +  4 Q.E.D. 1 2 3 4 Menu Constructions Quit Use mouse clicks to see proof

6 2 3 1 4 Given: Given:Parallelogram abcd cb ad Construction: Construction: Draw the diagonal |ac| Theorem 9: In a parallelogram opposite sides are equal and opposite angle are equal To Prove: To Prove:|ab| = |cd| and |ad| = |bc|  abc =  adc and  abc =  adc Proof:In the triangle abc and the triangle adc  1 =  4 …….. Alternate angles |ac| = |ac| …… Common  2 =  3 ……… Alternate angles  ……… ASA = ASA.  The triangle abc is congruent to the triangle adc  ……… ASA = ASA.  |ab| = |cd| and |ad| = |bc|  abc =  adc and  abc =  adc Q.E.D Menu Constructions Quit Use mouse clicks to see proof

7 Given: Given:Triangle abc Proof:** Area of large sq. = area of small sq. + 4(area )) (a + b) 2 = c 2 + 4(½ab) a2 a2 + 2ab +b 2 = c 2 + 2ab a2 a2 + b2 b2 = c2c2 Q.E.D. a b c a b c a b c a b c Construction: Construction:Three right angled triangles as shown Theorem 14: Theorem of Pythagoras : In a right angle triangle, the square of the hypotenuse is the sum of the squares of the other two sides To Prove: To Prove:a 2 + b 2 = c 2 Menu Constructions Quit Use mouse clicks to see proof

8 Theorem 19: Theorem 19: The angle at the centre of the circle standing on a given arc is twice the angle at any point of the circle standing on the same arc. To Prove:|  boc | = 2 |  bac | To Prove: |  boc | = 2 |  bac | Construction: Construction: Join a to o and extend to r r Proof:In the triangle aob a b c o 1 3 2 4 5 | oa| = | ob | …… Radii  |  2 | = |  3 | …… Theorem 4 |  1 | = |  2 | + |  3 | …… Theorem 3 |  1 | = |  2 | + |  3 | …… Theorem 3  |  1 | = |  2 | + |  2 |  |  1 | = 2|  2 |  Similarly |  4 | = 2|  5 |  |  boc | = 2 |  bac | Q.E.D Menu Constructions Quit Use mouse clicks to see proof


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