1. Algebra 1
Coin Word Problems

2. Stan’s pocket is filled with nickels and dimes
Stan’s pocket is filled with nickels and dimes. He has 6 more dimes than nickels. All together Stan has $1.20 in coins. How many nickels and dimes does he have?
-Let’s start with the sentence “He has 6 more dimes than nickels.”
-Ask yourself “Which coin does he have more of?”
-The answer is dimes.
d = n Quantity Equation

3. All together Stan has $1.20 in coins.
Each coin has a different value.
Each nickel is worth 5 cents. Thus 5n is the amount all his nickels are worth.
Each dime is worth 10 cents. Thus 10d is the amount all his dimes are worth.
$1.20 is worth 120 cents…
5n + 10d = The value equation.

4. Substitute and solve 10d + 5n = 120 and d = (n + 6)
10(n + 6) + 5n = 120
10n n = 120
15n + 60 = 120
15n = 60
n = 4

5. Complete the Problem He has 4 nickels. d = n + 6 d = 4 + 6 d = 10
Stan has 4 nickels and 6 dimes.

6. Check 10 dimes is worth 10(.10) = $1.00
4 nickels is worth 4(.05) = $0.20
Total = $1.20

7. 4) She gave the sitter 6 more nickels than dimes.
She has more…
Nickels.
n = d Quantity Equation.
She has 3 times as many quarters as dimes.
Quarters.
q =3d Quantity Equation.

8. All together Mrs. Ryan paid the babysitter $7.50.
Total nickel value in cents… 5n
Total dime value in cents…
10d
Total quarter value in cents…
25q
5n + 10d + 25q = 750

9. Substitute and Solve n = d + 6 q = 3d 5n + 10d + 25q = 750
5(d + 6) + 10d + 25(3d) = 750
5d d + 75d = 750
90d + 30 = 750
90d = 720
d = 8
She paid 8 dimes.

10. Solve for Nickels and Quarters
q = 3d
q = 3(8)
q =24

11. Check 8 dimes is worth 8($0.10) = $0.80
14 nickels is worth 14($0.05) = $0.70
24 quarters is worth 24($0.25) = $6.00
Total = $7.50