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Published byGiles Hart Modified over 4 years ago

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**Chapter 6: Polynomials and Polynomial Functions Section 6**

Chapter 6: Polynomials and Polynomial Functions Section 6.3: Dividing Polynomials Content Objectives: Students will demonstrate application of polynomial division by solving problems using long and synthetic division. Language Objectives: Students will demonstrate the understanding of how to write rational expressions in polynomial form and fraction form.

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**In arithmetic long division, you follow these steps: divide, multiply, subtract, and bring down.**

Follow these same steps to use long division to divide polynomials. Polynomial long division is a method for dividing a polynomial by another polynomials of a lower degree. It is very similar to dividing numbers.

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**Example 1: Using Long Division to Divide a Polynomial**

(–y^2 + 2y^3 + 25) ÷ (y – 3) Step 1: Write the dividend in standard form, including terms with a coefficient of 0. 2y^3 – y^2 + 0y + 25 Step 2: Write division in the same way you would when dividing numbers.

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Examples: Divide x^2 + 2x by x – 5 d) (9x^3 18x^2 – x +2) ÷ (3x + 1)

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Page 321: Quick check #1 Divide x^2 3x + 1 by x - 4

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**Example: Determine if x + 2 is a factor of each polynomial.**

a)x^2 + 10x + 16 b) x^3 + 7x^2 5x - 6

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**Synthetic division is a shorthand method of**

dividing a polynomial by a linear binomial by using only the coefficients. For synthetic division to work, the polynomial must be written in standard form, using 0 as a coefficient for any missing terms, and the divisor must be in the form (x – a).

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**Answer is always one degree less than the dividend due to dividing by a linear term.**

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**Use synthetic division to divide**

5x^3 6x^2 + 4x -1 by x – 3 2x^3 + 3x^2 - 17x -30 by x + 2 Then completely factor the dividend Page 322 Quick Check #3 x^3 + 4x^2 + x- 6 ÷ x + 1

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**Use synthetic division to divide**

X^3 2x^2 - 5x + 6 by x + 2 Then completely factor the dividend. We know when the remainder = 0 the divisor is a factor of the polynomial in the dividend. X + 2 is a factor of x^3 2x^2 - 5x+ 6 If we evaluate f(a) or f(-2) = (-2)^3-2(-2)^2-5(-2)+6 = 0 This is called the Remainder Theorem.

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Theorem: If a polynomial, p(x), is divided by x a, where "a" is a constant, then the remainder is p(a). Find the remainder if a = 4 For P(x) = x^4 5x^2+ 4x + 12 P(-4)= ? Use remainder theorem to find the remainder for the divisor x + 1 for p(x) = 2x^4 + 6x^3 5x^2-60

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**Text Assignment: Pg. 1-23, 27-33, 37-55 [odds]**

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