Presentation on theme: "Polynomials Functions Review (2)"— Presentation transcript:
1 Polynomials Functions Review (2) Division Algorithm and Long Division of Polynomials
2 Example Set No.1Find the quotient and remainder for each division problem.Be sure that the dividend and the divisor are written in descending order.Account for each term in the dividend – physically write any missing term with a coefficient of 0.Rewrite the division problem in “long division” form
3 The result is the first term of the quotient. For the first step, divide the leading term of the divisor into the leading term of the dividend.The result is the first term of the quotient.Multiply this result by the divisor and subtract from the dividend.Remember that you are subtracting the entire product from the dividend.
4 Now divide the leading term of the divisor into the leading term of the current remainder. This is the next term of the quotient.Multiply this result by the divisor and subtract from the current remainder in the dividend.
5 Since the degree of the divisor is greater than the degree of the current remainder, the division is complete.
6 You can also write the result of the division in the form: Check your work
23 The Remainder TheoremWhen a polynomial is divided by x – a, then the remainder must either be 0 or a constant.Consider the division algorithm for dividing the polynomial function f (x) by x – a.Evaluating f (a), we have
24 The Remainder Theorem tells us that synthetic substitution can be used to not only evaluate a function, but also to perform polynomial division when a polynomial is divided by a divisor in the form x – a .When we interpret the process of synthetic substitution as the result of polynomial division, we typically refer to the process as synthetic division.The divisor in synthetic division MUST be of the form x – a. If a polynomial is divided by x + a, you must be thinking of the divisor as x – (– a).
25 Check the result with your calculator. Coefficients of the quotient, which is one degree less than the dividend. These are listed in descending order.Remainder.
26 Check the result with your calculator. Coefficients of the quotient, which is one degree less than the dividend. These are listed in descending order.Remainder.
27 SolutionIn the previous Example set, we found two zeros of this polynomial function, x = 2 and x = ‒1.Since we need to write a complete factorization of this polynomial function, we will examine a procedure that utilizes repeated steps of synthetic division to find this factorization.
28 From Example Set No.2, we have the following synthetic division: Now perform synthetic division again, using ‒1 on the quotient from above.
29 We now know that the polynomial will factor into the product of two linear factors and a quadratic factor.
30 Now find the zeros of the quadratic factor by a method of your choice.
31 Verify the zeros with your calculator. Viewing window: [‒5,3] by [‒8,6]