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Strassen's Matrix Multiplication Sibel KIRMIZIGÜL.

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Presentation on theme: "Strassen's Matrix Multiplication Sibel KIRMIZIGÜL."— Presentation transcript:

1 Strassen's Matrix Multiplication Sibel KIRMIZIGÜL

2 Basic Matrix Multiplication Suppose we want to multiply two matrices of size N x N: for example A x B = C. C 11 = a 11 b 11 + a 12 b 21 C 12 = a 11 b 12 + a 12 b 22 C 21 = a 21 b 11 + a 22 b 21 C 22 = a 21 b 12 + a 22 b 22 2x2 matrix multiplication can be accomplished in 8 multiplication.(2 log 2 8 =2 3 )

3 Basic Matrix Multiplication void matrix_mult (){ for (i = 1; i <= N; i++) { for (j = 1; j <= N; j++) { compute C i,j ; } }} algorithm Time analysis

4 Strassens’s Matrix Multiplication Strassen showed that 2x2 matrix multiplication can be accomplished in 7 multiplication and 18 additions or subtractions..(2 log 2 7 =2 2.807 ) This reduce can be done by Divide and Conquer Approach.

5 Divide-and-Conquer Divide-and conquer is a general algorithm design paradigm: Divide: divide the input data S in two or more disjoint subsets S 1, S 2, … Recur: solve the subproblems recursively Conquer: combine the solutions for S 1, S 2, …, into a solution for S The base case for the recursion are subproblems of constant size Analysis can be done using recurrence equations

6 Divide and Conquer Matrix Multiply A  B = R A0A0 A1A1 A2A2 A3A3 B0B0 B1B1 B2B2 B3B3 A 0  B 0 +A 1  B 2 A 0  B 1 +A 1  B 3 A 2  B 0 +A 3  B 2 A 2  B 1 +A 3  B 3  = Divide matrices into sub-matrices: A 0, A 1, A 2 etc Use blocked matrix multiply equations Recursively multiply sub-matrices

7 Divide and Conquer Matrix Multiply  = a0a0 b0b0 a 0  b 0 A  B = R Terminate recursion with a simple base case

8 Strassens’s Matrix Multiplication P 1 = (A 11 + A 22 )(B 11 +B 22 ) P 2 = (A 21 + A 22 ) * B 11 P 3 = A 11 * (B 12 - B 22 ) P 4 = A 22 * (B 21 - B 11 ) P 5 = (A 11 + A 12 ) * B 22 P 6 = (A 21 - A 11 ) * (B 11 + B 12 ) P 7 = (A 12 - A 22 ) * (B 21 + B 22 ) C 11 = P 1 + P 4 - P 5 + P 7 C 12 = P 3 + P 5 C 21 = P 2 + P 4 C 22 = P 1 + P 3 - P 2 + P 6

9 C 11 = P 1 + P 4 - P 5 + P 7 = (A 11 + A 22 )(B 11 +B 22 ) + A 22 * (B 21 - B 11 ) - (A 11 + A 12 ) * B 22 + (A 12 - A 22 ) * (B 21 + B 22 ) = A 11 B 11 + A 11 B 22 + A 22 B 11 + A 22 B 22 + A 22 B 21 – A 22 B 11 - A 11 B 22 -A 12 B 22 + A 12 B 21 + A 12 B 22 – A 22 B 21 – A 22 B 22 = A 11 B 11 + A 12 B 21 Comparison

10 Strassen Algorithm void matmul(int *A, int *B, int *R, int n) { if (n == 1) { (*R) += (*A) * (*B); } else { matmul(A, B, R, n/4); matmul(A, B+(n/4), R+(n/4), n/4); matmul(A+2*(n/4), B, R+2*(n/4), n/4); matmul(A+2*(n/4), B+(n/4), R+3*(n/4), n/4); matmul(A+(n/4), B+2*(n/4), R, n/4); matmul(A+(n/4), B+3*(n/4), R+(n/4), n/4); matmul(A+3*(n/4), B+2*(n/4), R+2*(n/4), n/4); matmul(A+3*(n/4), B+3*(n/4), R+3*(n/4), n/4); } Divide matrices in sub-matrices and recursively multiply sub-matrices

11 Time Analysis


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