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CHAPTER 2 2.4 Continuity Exponential Growth and Decay Law of Natural Growth(k>0) & (Law of natural decay (k<0)): dy/dt = ky The solution of the initial-value.

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Presentation on theme: "CHAPTER 2 2.4 Continuity Exponential Growth and Decay Law of Natural Growth(k>0) & (Law of natural decay (k<0)): dy/dt = ky The solution of the initial-value."— Presentation transcript:

1 CHAPTER 2 2.4 Continuity Exponential Growth and Decay Law of Natural Growth(k>0) & (Law of natural decay (k<0)): dy/dt = ky The solution of the initial-value problem dy/dt = ky, y(0) = y o is y(t) = y o e kt. Population Growth: In the context of population growth, we can write dP/dt = kP or (1/p)(dP/dt) = k, where (1/p)(dP/dt) is the growth rate divided by the population size,and it is called the relative growth rate.

2 CHAPTER 2 2.4 Continuity Example: A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 100 cells. a) Find the relative growth rate. b) Find an expression for the number of cells after t hours. c) Find the number of cells after 10 hours. d) When will the population reach 10,000 cells?

3 CHAPTER 2 2.4 Continuity Example: A bacteria culture grows with constant relative growth rate. The count was 400 after 2 hours and 25,600 after 6 hours. a) What was the initial population of the culture? b) Find an expression for the population after t hours. c) In what period of time does the population double? d) When will the population reach 100,000?

4 Radioactive Decay: Radioactive substances decay by spontaneously emitting radiation. If m(t) is the mass remaining from an initial mass m o of the substance after time t, then the relative decay rate –(1/m)(dm/dt) has been found experimentally to be constant. It follows that dm/dt = k m where k is a negative constant. The mass decays exponentially: m(t) = m o e k t. Physicists express the rate of decay in terms of half-life, the time required for half of any given quantity to decay.

5 CHAPTER 2 2.4 Continuity Example: Polonium-210 has a half-life of 140 days. a) If a sample has a mass of 200 mg, find a formula for the mass that remains after t days. b) Find the mass after 100 days. c) When will the mass be reduced to 10 mg? d) Sketch the graph of the mass function.

6 CHAPTER 2 2.4 Continuity Example: After 3 days a sample of radon-222 decayed to 58% of its original amount. a) What is the half-life of radon-222? b) How long would it take the sample to decay to 10% of its original amount?

7 CHAPTER 2 2.4 Continuity Continuously Compound Interest: Example: How long will it take an investment to double in value if the interest rate is 6% compounded continuously? Example: If $500 is borrowed at 14% interest, find the amounts due at the end of 2 years if the interest is compounded: i) annually, ii) quarterly, iii) monthly, iv) daily, v) hourly, vi) continuously.


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