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Starting from rest, how high can you raise a 10.0 kg object in 3.50 s if you pull upward with a force of 115 N ?

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Presentation on theme: "Starting from rest, how high can you raise a 10.0 kg object in 3.50 s if you pull upward with a force of 115 N ?"— Presentation transcript:

1 Starting from rest, how high can you raise a 10.0 kg object in 3.50 s if you pull upward with a force of 115 N ?

2 SOLUTION : Starting from rest, how high can you raise a 10.0 kg object in 3.50 s if you pull upward with a force of 115 N ? CH2 W FAFA F A - W = F NET Find a:Find W:Find d: d = ? v i = 0 t = 3.5 a = ____ Find NET: F NET = maF A - W = F NET F = ma d = v i t + 1 / 2 at 2 = 10(9.8) = 98.0 N = F NET = 17.0 N 17 = 10 a a = 1.70 m/s =.5(1.7)(3.5) 2 = 10.4 m

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4 W FfFf W - F f = F NET Find F f :Find W:Find NET: F NET = maW - F f = F NET F = ma = 60(9.8) = 588 N F f = 150 = 150 N = 60 (2.5) F f = 438 N

5 W T W = 2T Find W:Find T: W = 2 TF = ma = 30(9.8) = 294 N T = 147 N 294 = 2T T

6 W W = F N F f = F A Find W: Find  : F f =  F N F = ma = 84.6(9.8) = 829 N  = =  (829) FNFN FAFA FfFf

7 W FNFN W = F N F A - F f = F NET Find F f : F f =  F N =.22(9.8m) = 2.16m F A - F f = F NET FAFA FfFf m = 8m 122 = 10.2m m = 12.0 kg

8 W W = F f F N = F A Find W:Find F A : Same as F N F f =  F N F = ma = 2(9.8) = 19.6 N 19.6 =.255F N FfFf FAFA FNFN F N = 76.9 N PHYSICS 

9 W W = F N F A - F f = F NET Find m:Find F f : F f =  F N F = ma 38= m(9.8) = 3.88 kg = 6.65 N =.175(38) FNFN FAFA FfFf Find NET: F A - F f = F NET = F NET = 18.4 N Find a: F = ma 18.4 = 3.88a = 4.74 m/s 2 CH2 Find v f : t = 7 v i = 2.45 v f = ? a = ____ 4.74 v f - v i a = ____ t v f = _______ 7 = 35.6 m/s

10 W W = F N F f = F A Find W: Find  : F f =  F N F = ma = 25(9.8) = 245 N  = =  (245) FNFN FAFA FfFf

11 W T T - W = F NET Find T:Find W:Find NET: F NET = maT - W = F NET F = ma =.5(9.8) = 4.9 N T =.625 =.625 N =.5 (1.25) T = 5.53 N

12 W FNFN W = F N F A - F f = F NET Find NET: = 1.94(2.25) = 4.37 N F A - F f = F NET FAFA FfFf 7.63 =  (19)  =.402 Find m: F = ma 19 = m(9.8) = 1.94 kg Find F f : F f =  F N 12 - F f = 4.37 = 7.63 N F = ma Find  :

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