Presentation is loading. Please wait.

Presentation is loading. Please wait.

S TOICHIOMETRY B OARD R ELAY. R OLES : Player 1 : set up problem and work through first conversion factor Player 2 : work through second conversion factor.

Similar presentations


Presentation on theme: "S TOICHIOMETRY B OARD R ELAY. R OLES : Player 1 : set up problem and work through first conversion factor Player 2 : work through second conversion factor."— Presentation transcript:

1 S TOICHIOMETRY B OARD R ELAY

2 R OLES : Player 1 : set up problem and work through first conversion factor Player 2 : work through second conversion factor (if there is one) Player 3 : work through third conversion factor (if there is one) Player 4 : check work and solve If there is no 4 th person in your group, All students will check work and solve.

3 W RITE AND BALANCE THE FOLLOWING REACTION : Solutions of sodium carbonate and barium nitrate react. Predict the products.

4 1 Na 2 CO Ba(NO 3 ) 2  1 BaCO NaNO 3 Solutions of sodium carbonate and barium nitrate react. Predict the products.

5 Given 0.50 moles of barium nitrate, how many moles of sodium nitrate are formed?

6 1 Na 2 CO Ba(NO 3 ) 2  1 BaCO NaNO mol Ba(NO 3 ) 2 2 mol NaNO 3 = 1 mole NaNO 3 1 mol Ba(NO 3 ) 2

7 What mass of barium carbonate will form if 25.0g of sodium carbonate reacts with excess barium nitrate?

8 1 Na 2 CO Ba(NO 3 ) 2  1 BaCO NaNO g Na 2 CO 3 1 mole Na 2 CO 3 1 mol BaCO g BaCO 3 106g Na 2 CO 3 1 mol Na 2 CO 3 1 mol BaCO 3 = 46.5g BaCO 3

9 What mass of sodium nitrate will form if 3.2 x formula units barium nitrate reacts with excess sodium carbonate?

10 1 Na 2 CO Ba(NO 3 ) 2  1 BaCO NaNO x f.u. Ba(NO 3 ) 2 1 mole Ba(NO 3 ) 2 2 mol NaNO 3 85g 6.02 x f.u. Ba(NO 3 ) 2 1 mol Ba(NO 3 ) 2 1 mol = 903.7g NaNO 3

11 W RITE AND BALANCE THE FOLLOWING REACTION : Lithium and nitrogen gas react. Predict the products.

12 6 Li + 1 N 2  2 Li 3 N Lithium and nitrogen gas react. Predict the products.

13 What mass of lithium is needed to react with 15.0g of nitrogen?

14 6 Li + 1 N 2  2 Li 3 N 15.0g N 2 1 mol N 2 6 mol Li6.9g Li 28.0g N 2 1 mol N 2 1 mol Li = 22.2g Li

15 What mass of lithium is needed to form 12.2g of lithium nitride?

16 6 Li + 1 N 2  2 Li 3 N 12.2g Li 3 N1 mol Li 3 N 6 mol Li6.9g Li 34.7g Li 3 N 2 mol Li 3 N 1 mol Li = 7.3g Li

17 How many atoms of Lithium react with 2.8 x molecules of nitrogen?

18 6 Li + 1 N 2  2 Li 3 N 2.8 x m/c N 2 1 mol N 2 6 mol Li 6.02 x at Li 6.02 x m/c N 2 1 mol N 2 1 mol Li = 4.7 x atoms Li

19 W RITE AND BALANCE THE FOLLOWING REACTION : Solutions of magnesium sulfate and aluminum nitrate are mixed. Predict the products.

20 3 MgSO Al(NO 3 ) 3  3 Mg(NO 3 ) Al 2 (SO 4 ) 3 Solutions of magnesium sulfate and aluminum nitrate are mixed. Predict the products.

21 How many grams of magnesium sulfate are needed to react with 0.75 moles of aluminum nitrate?

22 3 MgSO Al(NO 3 ) 3  3 Mg(NO 3 ) Al 2 (SO 4 ) mol Al(NO 3 ) 3 3 moles MgSO g MgSO 4 2 moles Al(NO 3 ) 3 1 mol MgSO 4 = 135.5g MgSO 4

23 What mass of aluminum sulfate will form if 12.0g of aluminum nitrate react with 20.5g of magnesium sulfate? Identify the limiting reactant and excess reactant.

24 3 MgSO Al(NO 3 ) 3  3 Mg(NO 3 ) Al 2 (SO 4 ) g Al(NO 3 ) 3 1 mol Al(NO 3 ) 3 1 mol Al 2 (SO 4 ) g Al 2 (SO 4 ) g Al(NO 3 ) 3 2 mol Al(NO 3 ) 3 1 mol Al 2 (SO 4 ) 3 = 9.6g Al 2 (SO 4 ) g MgSO 4 1 mol MgSO 4 1 mol Al 2 (SO 4 ) g Al 2 (SO 4 ) g MgSO 4 3 mol MgSO 4 1 mol Al 2 (SO 4 ) 3 = 19.4g Al 2 (SO 4 ) 3 L.R. = Al(NO 3 ) 3 E.R. = MgSO 4

25 W RITE AND BALANCE THE FOLLOWING REACTION : Write and balance the equation for the combustion of dicarbon dihydride.

26 2 C 2 H O 2  4 CO H 2 O Write and balance the equation for the combustion of dicarbon dihydride.

27 How many moles of water will be produced if 3.8 moles of oxygen react with excess dicarbon dihydride?

28 2 C 2 H O 2  4 CO H 2 O 3.8 mol O 2 2 moles H 2 O= 1.5 moles H 2 O 5 moles O 2

29 How many molecules of carbon dioxide will be produced if 0.85 moles of water are produced?

30 2 C 2 H O 2  4 CO H 2 O 0.85 mol H 2 O 4 moles CO x m/c CO 2 2 moles O 2 1 mol CO 2 = 1.0 x m/c CO 2

31 If 5.8 grams of dicarbon dihydride react with 4.2 grams of oxygen gas, how many grams of water will be produced? Identify the limiting reactant and what is the excess reactant.

32 2 C 2 H O 2  4 CO H 2 O 5.8g C 2 H 2 1 mole C 2 H 2 2 moles H 2 O 18.0 g H 2 O 26.0g C 2 H 2 2 moles C 2 H 2 1 mole H 2 O = 4.0g H 2 O 4.2g O 2 1 mole O 2 2 moles H 2 O18.0 g H 2 O 32.0g O 2 5 moles O 2 1 mole H 2 O = 0.9 g H 2 O L.R. = O 2 E.R. = C 2 H 2


Download ppt "S TOICHIOMETRY B OARD R ELAY. R OLES : Player 1 : set up problem and work through first conversion factor Player 2 : work through second conversion factor."

Similar presentations


Ads by Google