Presentation on theme: "Lecture #6 – Bombay Phenotype & Epistasis Wheeler High School The Center for Advanced Studies in Science, Math & Technology Post-AP DNA/Genetics – Ms."— Presentation transcript:
Lecture #6 – Bombay Phenotype & Epistasis Wheeler High School The Center for Advanced Studies in Science, Math & Technology Post-AP DNA/Genetics – Ms. Kelavkar
The Bombay Phenotype Discovered in 1952 Woman from Bombay who was genetically blood type B but phenotypically O –Homozygous for recessive mutation in gene known as FUT1 Having this mutation meant she could not make any H substance
What type of mutation is this? Bombay Phenotype = Has the genes to make and but has a mutation in the gene that makes
Bombay Phenotype & Epistasis Many traits characterized by a distinct phenotype are affected by more than one gene Epistasis occurs when one gene masks the effect of another gene or when two gene pairs complement each other such that one dominant allele is required at each locus to express a certain phenotype.
Bombay Phenotype & Epistasis The Bombay phenotype for ABO blood groups is an example of epistasis –homozygous recessive condition at one locus masks the expression of a second locus A locus is a position on a chromosome Individuals with the Bombay Phenotype have the genes to make the A or B antigen at one loci but lack the genes that produce the H substance produced at another loci. – No H antigen gives you the O phenotype!
A ratio expressed in 16 parts (e.g., 3:6:3:4) suggests that epistasis is occurring which means genes are ‘interacting’ to give a particular phenotype.
Epistasis in Mice B is the pigment gene! wt coat color in mice is called agouti (A-) Agouti is dominant to black (aa) When a recessive mutation, bb, at a separate locus is homozygous, all pigmentation is eliminated giving albino mice F 1 : AaBb x AaBb F 2 RatioGenotypePhenotypePhenotypic Ratios 9/16A-B-Agouti9/16 agouti 3/16A-bbAlbino4/16 albino 3/16aaB-Black3/16 black 1/16aabbalbino Agouti = A- Black = aa Pigment = B- No pigment = bb Agouti = A- Black = aa Pigment = B- No pigment = bb
Epistasis in Mice Mouse color is dependent on 2 different genes that interact (A- and B-)… B- Black Pigment A- Agouti Gene BGene A Agouti = A- Black = aa Pigment = B- No pigment = bb bb No Pigment A- Albino Mouse B- Black Pigment aa Black So there are 3 possibilities Gene Interaction Diagram
Try One Out!! F 1 : Aabb x AaBb F 2 Aa x AaF 2 bb x Bb F 2 phenotypic proportions ¾ A- ¼ aa ½ B- ½ bb ½ B- 3/8 A-B- (Agouti) 3/8 A-bb (Albino) 1/8 aaB- (Black) 1/8 aabb (Albino) Agouti = A- Black = aa Pigment = B- No pigment = bb
Lethal Mutations A loss of function mutation can sometimes be tolerated in the heterozygous state but may behave as a recessive lethal allele in the homozygous state, in which case homozygous recessive individuals will not survive. –This is a lethal mutation!
Inheritance patterns in 3 crosses involving the normal wt agouti allele (A) and the mutant yellow (A Y ) allele in the mouse. Note that the mutant allele behaves dominantly to the normal allele in controlling coat color, but it also behaves as a homozygous recessive lethal allele. The genotype A Y A Y does not exist.
Any Questions? I am an Agouti mouse I’m an Albino I’m a Black mouse