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Division Mrs. Turner 4 th grade Teacher NDES

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26383

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263831x= 2x= 52 4x=104 8x= 208 26 x 2= 52 52 x 2=104 104 x 2=208 x2 x2 x2 x2 x2 x2

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26 383 1x= 2x= 52 4x=104 8x= 208 I think I should use 8x=208 because it is the highest number I can use without going higher than 383.

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26 383 -208 1x= 2x= 52 4x=104 8x= 208 The 208 will go under my dividend and 8 will go to the right outside of the line. 8

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26 383 -208 175 1x= 2x= 52 4x=104 8x= 208 Now, I should subtract 383 minus 208. Okay, now 175 is my dividend. 8 7 13

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26 383 -208 175 1x= 2x= 52 4x=104 8x= 208 I think I should use 4x=104 because it is the highest number I can use without going higher than 175. 8 7 13

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26 383 -208 175 -104 1x= 2x= 52 4x=104 8x= 208 The 104 will go under my dividend and 4 will go to the right outside of the line. 8484 7 13

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26 383 -208 175 -104 71 1x= 2x= 52 4x=104 8x= 208 Now, I should subtract 175 minus 104. Okay, now 71 is my dividend. 8484 7 13

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26 383 -208 175 -104 71 1x= 2x= 52 4x=104 8x= 208 I think I should use 2x=52 because it is the highest number I can use without going higher than 71. 8484 7 13

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26 383 -208 175 -104 71 -52 1x= 2x= 52 4x=104 8x= 208 The 52 will go under my dividend and 2 will go to the right outside of the line. 842842 7 13

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Now, I should subtract 71 minus 52. Okay, now 19 is my dividend. 26 383 -208 175 -104 71 -52 19 1x= 2x= 52 4x=104 8x= 208 842842 7 13

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Hey! There aren’t any multiples that are less than or equal to 19. Now I can find my answer. 26 383 -208 175 -104 71 -52 19 1x= 2x= 52 4x=104 8x= 208 842842 7 13

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Okay, I had 19 leftover. That is less than my divisor 26. So… I should write my remainder as 19. 26 383 -208 175 -104 71 -52 19 1x= 2x= 52 4x=104 8x= 208 842842 7 13 r19

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I should add 8 + 4 which is 12. Then, 12 + 2 is 14. I should write my quotient as 14. 26 383 -208 175 -104 71 -52 19 1x= 2x= 52 4x=104 8x= 208 8 4 +2 14 7 13 r1914

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