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Division Mrs. Turner 4 th grade Teacher NDES. 26383.

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Presentation on theme: "Division Mrs. Turner 4 th grade Teacher NDES. 26383."— Presentation transcript:

1 Division Mrs. Turner 4 th grade Teacher NDES

2 26383

3 263831x= 2x= 52 4x=104 8x= x 2= x 2= x 2=208 x2 x2 x2 x2 x2 x2

4 x= 2x= 52 4x=104 8x= 208 I think I should use 8x=208 because it is the highest number I can use without going higher than 383.

5 x= 2x= 52 4x=104 8x= 208 The 208 will go under my dividend and 8 will go to the right outside of the line. 8

6 x= 2x= 52 4x=104 8x= 208 Now, I should subtract 383 minus 208. Okay, now 175 is my dividend

7 x= 2x= 52 4x=104 8x= 208 I think I should use 4x=104 because it is the highest number I can use without going higher than

8 x= 2x= 52 4x=104 8x= 208 The 104 will go under my dividend and 4 will go to the right outside of the line

9 x= 2x= 52 4x=104 8x= 208 Now, I should subtract 175 minus 104. Okay, now 71 is my dividend

10 x= 2x= 52 4x=104 8x= 208 I think I should use 2x=52 because it is the highest number I can use without going higher than

11 x= 2x= 52 4x=104 8x= 208 The 52 will go under my dividend and 2 will go to the right outside of the line

12 Now, I should subtract 71 minus 52. Okay, now 19 is my dividend x= 2x= 52 4x=104 8x=

13 Hey! There aren’t any multiples that are less than or equal to 19. Now I can find my answer x= 2x= 52 4x=104 8x=

14 Okay, I had 19 leftover. That is less than my divisor 26. So… I should write my remainder as x= 2x= 52 4x=104 8x= r19

15 I should add which is 12. Then, is 14. I should write my quotient as x= 2x= 52 4x=104 8x= r1914

16


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