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1 3. Relational Algebra and SQL Example: Let the following relations describe point sets: A(x, y), B(x, y), J(x, y) 2D points in the plane H(x, y, z), I(x, y, z) 3D points in space F(z) line on the z-axis K(y,z) 2D points in (y, z) plane

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2 3.1 Relation algebra operators A B A B A \ B A and B

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3 A F J K

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4 x,y H y,z H 2x+z = 0 I

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5 Example: Find the SSN and tax for each person. π SSN,Tax σ wages+interest+capital_gain = income Taxrecord × Taxtable Example: Find the area of Lincoln reached by a radio station. ( π X,Y ( σ Name=“Lincoln” Town ) ) ( π X,Y Broadcast )

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6 3.2 SQL SELECT a 1,..., a n FROM R 1, R 2, …, R m WHERE Con 1, …,Con k This means: π a 1,..., a n ( σ Con 1 ( … (σ Con k ( R 1 × R 2 × … × R m ))…))

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7 Example: Find the SSN and tax for each person. SELECT SSN, Tax FROM Taxrecord, Taxtable WHERE wages + interest + capital_gain = income

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8 AS – keyword used to rename relations Two SQL expressions can be combined by: INTERSECT UNION MINUS – set difference

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9 Example: Find the names of the streets that intersect. SELECT S.NAME, T.NAME FROM Streets AS S, Streets AS T WHERE S.X = T.X and S.Y = T.Y

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10 Example: Assume we have the relations: Broadcast ( Radio, X, Y ) Town ( Name, X, Y ) Find the parts of Lincoln, NE that can be reached by at least one Radio station. (SELECT X, Y FROM Town WHERE Name = “Lincoln”) INTERSECT (SELECT X, Y FROM Broadcast)

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11 Another way of connecting SQL expressions is using the IN keyword. SELECT …….. FROM …….. WHERE a IN ( SELECT b FROM ….. WHERE ….. )

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12 SQL with aggregation – SELECT aggregate_function FROM ……. WHERE …… aggregate_function – Max (c 1 a 1 + ……..+ c n a n ) where a i are attributes Min (c 1 a 1 + ……..+ c n a n ) and c i are constants Sum(a) where a is an attribute that is Avg(a) constant in each constraint tuple Count(a)

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13 Example: Package(Serial_No, From, Destination, Weight) Postage (Weight, Fee) Find the total postage of all packages sent from Omaha. SELECT Sum(Fee) FROM Package, Postage WHERE Package.Weight = Postage.Weight AND Package.From = “ Omaha “

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14 GROUP BY – SELECT a 1, …, a n, aggregate_function FROM ….. WHERE …… GROUP BY a 1,..., a k Evaluates basic SQL query Groups the tuples according to different values of a 1,..,a k Applies the aggregate function to each group separately {a 1, …, a k } {a 1, …, a n }

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15 Example: Find the total postage sent out from each city. SELECT Package.From, Sum(Postage.Fee) FROM Package, Postage WHERE Package.Weight = Postage.Weight GROUP BY Package.From

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Copyright © 2007 Ramez Elmasri and Shamkant B. Navathe Chapter 6 (Continued) The Relational Algebra and Calculus.

Copyright © 2007 Ramez Elmasri and Shamkant B. Navathe Chapter 6 (Continued) The Relational Algebra and Calculus.

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