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Topic: Oxidation States and Criss Cross Method Do Now: Ionic, Covalent or Metallic 1.Mg 2.MgO 3.NaCl 4.CO 2 5.H 2 O 1.Metallic 2.Ionic 3.Ionic 4.Covalent.

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Presentation on theme: "Topic: Oxidation States and Criss Cross Method Do Now: Ionic, Covalent or Metallic 1.Mg 2.MgO 3.NaCl 4.CO 2 5.H 2 O 1.Metallic 2.Ionic 3.Ionic 4.Covalent."— Presentation transcript:

1 Topic: Oxidation States and Criss Cross Method Do Now: Ionic, Covalent or Metallic 1.Mg 2.MgO 3.NaCl 4.CO 2 5.H 2 O 1.Metallic 2.Ionic 3.Ionic 4.Covalent 5.Covalent

2 positive ion and negative ion Ionic bond is a bond between: positive ion and negative ion Metals: lose valence electrons – form cation – form cation (+ ion) Nonmetals: gain electrons anion – form anion (- ion)

3 Metals lose their valence electrons and nonmetals gain

4 IONIC BONDING Ionic compounds are electrically neutral overall Ionic compounds are electrically neutral overall 1 Ca = +2 x 1 = +2 2 Cl = -1 x 2 = -2 2 K = +1 x 2 = +2 1 S = -2 x 1 = -2 2 Cr = +3 x 2 = +6 3 O = -2 x 3 = -6

5 Assigning Oxidation States You can look at your periodic table. It’s listed in the topic right corner. What do you do if there is more then one?!

6 What to do if more then 1 oxidation state V 2 S 5 – Nonmetal = top number – So S would be -2 –V2S5–V2S5 -2 x 5 = Then determine the oxidation state of the metal that will give you the same number but positive ____ x 2 = +10+5

7 You try… FeO Fe=____ O= ____ Fe 2 O 3 Fe=____ O= ____

8 Criss-Cross Method Mg +2 and Cl -1 Mg 1 Cl 2 but if subscript is 1, forget it! MgCl 2 means 1 Mg +2 and 2 Cl -1 Crisscross and Drop

9 NOTE: The formula has to be in the simplest whole number ratio (this is called the empirical formular Be 2 O 2 = BeO Al 3 N 3 = AlN

10 Try a few formulas: Ca +2 + Cl -1 Na +1 + O -2 Cs +1 + S -2 Al +3 + Cl -1 Al +3 + Se -2 Mg +2 + F -1 Ca +2 + S -2 CaCl 2 Na 2 O Cs 2 S AlCl 3 Al 2 Se 3 MgF 2 CaS


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