# 1.All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! 2.All students.

## Presentation on theme: "1.All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! 2.All students."— Presentation transcript:

1.All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! 2.All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in). 3.Students will keep score together – winner gets bonus credit. JEOPARDY! Geometry Bench Mark 1 Review

Angle Madhouse Building Blocks It’s Moving Time 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 Straight As An Arrow 100 200 300 400 500 Be Reasonable Go To Final Jeopardy!

Solve for x: M is the midpoint of AB. AM = 4x + 19 BM = 2x + 13 100

What is ? 100 Question: M is the midpoint of AB. AM = 4x + 19 BM = 2x + 13

A, B and C are collinear and B lies between A and C. If AB = 2x + 4, BC = 12, AC = 4x – 6, then find AC. 200

First, 2x + 4 + 12 = 4x – 6 x = 11 Therefore, AC = 38 200 A, B and C are collinear and B lies between A and C. If AB = 2x + 4, BC = 12, AC = 4x – 6, then find AC.

O is the midpoint of FX. If FO = 3x + 6 and FX = 66, then solve for x. 300

3x + 6 = ½  66 x = 9 300

C is the midpoint of AE. If A is located at (7, 1) and C is located at (2, –3), then find the coordinates of E. 400

C is in the middle!!! From A to C, we go left 5 and down 4, so if we do it again, we end up at E = (–3, –7) 400 C is the midpoint of AE. If A is located at (7, 1) and C is located at (2, –3), then find the coordinates of E.

Find the midpoint of AB if A is located at (a + c, d – e) and B is located at (g – h, s + t). 500

Find the midpoint of AB if A is located at (a + c, d – e) and B is located at (g – h, s + t).

Ray OX lies in the interior of  BOD. If m  BOX = 2x + 9, m  DOX = 3x – 2, and m  BOD = 72, find m  BOX. 100

2x + 9 + 3x – 2 = 72 x = 13 m  BOX = 35  100 Ray OX lies in the interior of  BOD. If m  BOX = 2x + 9, m  DOX = 3x – 2, and m  BOD = 72, find m  BOX.

 A and  B are complementary. If m  A = 2x + 4 and m  B = 7x - 22, find m  B. 200

2x + 4 + 7x – 22 = 90 x = 12 m  B = 62  200  A and  B are complementary. If m  A = 2x + 4 and m  B = 7x - 22, find m  B.

 A and  B are a linear pair. If m  A = 70 – 2x and m  B = 8x – 10, find m  B. 300

70 – 2x + 8x – 10 = 180 6x + 60 = 180 x = 20 m  B = 150  300  A and  B are a linear pair. If m  A = 70 – 2x and m  B = 8x – 10, find m  B.

Ray UP bisects  TUX. If m  TUP = 3x + 4 and m  TUX = 104, solve for x. 400

3x + 4 = ½  104 3x = 48 x = 16 400 Ray UP bisects  TUX. If m  TUP = 3x + 4 and m  TUX = 104, solve for x.

Based on the following, find m  DXC. 500 (5x – 40)° (2x + 2)° A X D B C

5x – 40 = 2x + 2 (vertical angles) x = 14 Plugging in… m  AXD = 30  THEREFORE, m  DXC = 180  – 30  = 150  500 (5x – 40)° (2x + 2)° A X D B C

Identify the following construction and the first step used to construct it. 100 A B C A' B' C'

Copy a (congruent) angle. Step 1: Draw a new ray and label the vertex A’. 100

Identify the following construction and the first step used to construct it. 200 AA' C' C

Copy a (congruent) segment. Step 1: Draw a new ray and label the vertex A’. 200

Identify the following construction and the first step used to construct it. 300 AB

Bisect a segment. Step 1: From both A and B, draw large arcs that intersect each other and AB. 300

Identify the following construction and the first step used to construct it. 400 A B C D

Bisect an angle Step 1: From A, draw an arcs that intersects the angle and label points B and C. 400

List all the steps needed to copy a congruent angle. 500

Step 1. Draw a new ray and label the endpoint A’. Step 2. From A, draw an arc through the angle and label the intersections B and C. From A’, draw the same arc and label C’. Step 3. Measure from C to B. Draw a small arc and use the same arc when measuring from C’. Label B’. Step 4. Draw a ray from A’ to B’ – we’re done. 500 A B C A' B' C'

Point A is at (2, 5) and Point B is at (–3, 7). Find the new location of each point when they are translated according to the motion rule: (x, y)  (x – 6, y + 1) 100

A’ is at (–4, 6) B’ is at (–9, 8) 100 Point A is at (2, 5) and Point B is at (–3, 7). Find the new location of each point when they are translated according to the motion rule: (x, y)  (x – 6, y + 1)

Point A is at (3, 4) and Point B is at (–1, –5). Find the new location of each point when they are translated 2 units up and 4 units left. 200

Be careful…read the question… (up 2 = y + 2, left 4 = x – 4) A’ is at (–1, 6) B’ is at (–5, –3) 200 Point A is at (3, 4) and Point B is at (–1, –5). Find the new location of each point when they are translated 2 units up and 4 units left.

When A (–5, 2) and B (–3, 6) are reflected about the y-axis, the new coordinates of B’ are: 300

(3, 6) 300 When A (–5, 2) and B (–3, 6) are reflected about the y-axis, the new coordinates of B’ are:

Point A (6, –4) is first reflected about the origin, then reflected about the x-axis. The new coordinates of A’ are: 400

It first moves to (–6, 4), then it moves to (–6, –4). 400 Point A (6, –4) is first reflected about the origin, then reflected about the x-axis. The new coordinates of A’ are:

Daily Double 500

A (–7, 2) is rotated 90  counterclockwise. Find the location of A’. 500

The x-dimension and y- dimension switch every 90  and one sign changes. Since we rotated “left”, both the x and y became negative. (–2, –7) 500

Define inductive and deductive reasoning. Identify key phrases to help identify each type. 100

Inductive = INFERRING GENERAL TRUTHS based upon SPECIFIC EXAMPLES or a PATTERN Deductive = USING LOGIC to DRAW CONCLUSIONS based upon ACCEPTED STATEMENTS.

“If Noah studies well, then Noah earns 100% on the test.” Write the converse and the contrapositive statements. 200

Converse: (Switch the If and then parts) “If Noah earns 100% on the test, then Noah studied well.” Contrapositive (switch AND negate it) “If Noah does NOT earn 100% on the test, then Noah did NOT study well.” “If Noah studies well, then Noah earns 100% on the test.”

“Two lines in a plane always intersect to form right angles.” Find one or more counterexamples. 300

1.Non-perpendicular, intersecting lines in the same planeNon-perpendicular, intersecting lines in the same plane 2.Parallel lines in the same plane.Parallel lines in the same plane. They have to be lines that LIE IN THE SAME PLANE. “Two lines in a plane always intersect to form right angles.” Find one or more counterexamples.

Complete the proof reasons: Statements Reasons 1.3x + 6 = 391. Given3x + 6 = 391. Given 2.3x = 332. ___________3x = 332. ___________ 3.x = 113. ___________x = 113. ___________ 400

2.Subtraction Property of =Subtraction Property of = 3.Division Property of =Division Property of = Complete the proof reasons: Statements Reasons 1.3x + 6 = 391. Given 2.3x = 332. ___________ 3.x = 113. ___________

Carefully, identify the three properties below: 1.a + b + 7 = a + b + 7a + b + 7 = a + b + 7 2.If r = s and s = t, then r = tIf r = s and s = t, then r = t 3.If a = 90 and b = 90, then a = bIf a = 90 and b = 90, then a = b 500

1.REFLEXIVE Property of = …. exactly the same!REFLEXIVE Property of = …. exactly the same! 2.TRANSITIVE Property of =.… follow the pathTRANSITIVE Property of =.… follow the path 3.SUBSTITUION Property of = …. Plug in for “90”SUBSTITUION Property of = …. Plug in for “90” 500 Carefully, identify the three properties below: 1.a + b + 7 = a + b + 7 2.If r = s and s = t, then r = t 3.If a = 90 and b = 90, then a = b

Final

Where’s Waldo??? Determine your final wagers now.

Waldo is hiding at (–9, –7). If Waldo goes through the following transformations, where is his new hideout? 1.Reflected about y = xReflected about y = x 2.Rotated 90  clockwiseRotated 90  clockwise 3.Reflected about the originReflected about the origin 4.Translated 3 down and 2 right.Translated 3 down and 2 right.

Waldo is hiding at (–9, –3). If Waldo goes through the following transformations, where is his new hideout? 1.Reflected about y = x… (–3, –9)Reflected about y = x… (–3, –9) 2.Rotated 90  clockwise … (–9, 3)Rotated 90  clockwise … (–9, 3) 3.Reflected about the origin … (9, –3)Reflected about the origin … (9, –3) 4.Translated 3 down and 2 right. … (11, –6)Translated 3 down and 2 right. … (11, –6)

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