Download presentation

Presentation is loading. Please wait.

Published byJoy Blake Modified about 1 year ago

1
Page 1 Adaptive Optics in the VLT and ELT era Atmospheric Turbulence François Wildi Observatoire de Genève Credit for most slides : Claire Max (UC Santa Cruz)

2
Atmospheric Turbulence Essentials We, in astronomy, are essentially interested in the effect of the turbulence on the images that we take from the sky. This effect is to mix air masses of different index of refraction in a random fashion The dominant locations for index of refraction fluctuations that affect astronomers are the atmospheric boundary layer, the tropopause and for most sites a layer in between (3-8km) where a shearing between layers occurs. Atmospheric turbulence (mostly) obeys Kolmogorov statistics Kolmogorov turbulence is derived from dimensional analysis (heat flux in = heat flux in turbulence) Structure functions derived from Kolmogorov turbulence are r 2/3

3
Fluctuations in index of refraction are due to temperature fluctuations Refractivity of air where P = pressure in millibars, T = temp. in K, in microns n = index of refraction. Note VERY weak dependence on Temperature fluctuations index fluctuations (pressure is constant, because velocities are highly sub-sonic. Pressure differences are rapidly smoothed out by sound wave propagation)

4
Turbulence arises in several places stratosphere Heat sources w/in dome boundary layer ~ 1 km tropopause km wind flow around dome

5
Within dome: “mirror seeing” When a mirror is warmer than dome air, convective equilibrium is reached. Remedies: Cool mirror itself, or blow air over it, improve mount To control mirror temperature: dome air conditioning (day), blow air on back (night) credit: M. Sarazin convective cells are bad

6
Local “Seeing” - Flow pattern around a telescope dome Cartoon (M. Sarazin): wind is from left, strongest turbulence on right side of dome Computational fluid dynamics simulation (D. de Young) reproduces features of cartoon

7

8
Boundary layers: day and night Wind speed must be zero at ground, must equal v wind several hundred meters up (in the “free” atmosphere) Boundary layer is where the adjustment takes place, where the atmosphere feels strong influence of surface Quite different between day and night –Daytime: boundary layer is thick (up to a km), dominated by convective plumes –Night-time: boundary layer collapses to a few hundred meters, is stably stratified. Perturbed if winds are high. Night-time: Less total turbulence, but still the single largest contribution to “seeing”

9
Real shear generated turbulence (aka Kelvin- Helmholtz instability) measured by radar Colors show intensity of radar return signal. Radio waves are backscattered by the turbulence.

10
Kolmogorov turbulence, cartoon Outer scale L 0 ground Inner scale l 0 h convection solar h Wind shear

11
Kolmogorov turbulence, in words Assume energy is added to system at largest scales - “outer scale” L 0 Then energy cascades from larger to smaller scales (turbulent eddies “break down” into smaller and smaller structures). Size scales where this takes place: “Inertial range”. Finally, eddy size becomes so small that it is subject to dissipation from viscosity. “Inner scale” l 0 L 0 ranges from 10’s to 100’s of meters; l 0 is a few mm

12
Assumptions of Kolmogorov turbulence theory Medium is incompressible External energy is input on largest scales (only), dissipated on smallest scales (only) –Smooth cascade Valid only in inertial range L 0 Turbulence is –Homogeneous –Isotropic In practice, Kolmogorov model works surprisingly well! Questionable

13
Concept Question What do you think really determines the outer scale in the boundary layer? At the tropopause? Hints:

14
Outer Scale ~ m, from Generalized Seeing Monitor measurements F. Martin et al., Astron. Astrophys. Supp. v.144, p.39, June 2000

15
Atmospheric structure functions A structure function is measure of intensity of fluctuations of a random variable f (t) over a scale D f ( ) = With the assumption that temperature fluctuations are carried around passively by the velocity field (for incompressible fluids), T and N have structure functions like D T ( r ) = = C T 2 r 2/3 D N ( r ) = = C N 2 r 2/3 C N 2 is a “constant” that characterizes the strength of the variability of N. It varies with time and location. In particular, for a static location (i.e. a telescope) C N 2 will vary with time and altitude

16
Typical values of C N 2 Index of refraction structure function D N ( r ) = = C N 2 r 2/3 Night-time boundary layer: C N 2 ~ m -2/ Paranal, Chile, VLT

17
Turbulence profiles from SCIDAR Eight minute time period (C. Dainty, Imperial College) Siding Spring, Australia Starfire Optical Range, Albuquerque NM

18
Atmospheric Turbulence: Main Points The dominant locations for index of refraction fluctuations that affect astronomers are the atmospheric boundary layer and the tropopause Atmospheric turbulence (mostly) obeys Kolmogorov statistics Kolmogorov turbulence is derived from dimensional analysis (heat flux in = heat flux in turbulence) Structure functions derived from Kolmogorov turbulence are r 2/3 All else will follow from these points!

19
Phase structure function, spatial coherence and r 0

20
Definitions - Structure Function and Correlation Function Structure functionStructure function: Mean square difference Covariance functionCovariance function: Spatial correlation of a random variable with itself

21
Relation between structure function and covariance function To derive this relationship, expand the product in the definition of D ( r ) and assume homogeneity to take the averages

22
Definitions - Spatial Coherence Function Spatial coherence function of field is defined as Covariance for complex fn’s C (r) measures how “related” the field is at one position x to its values at neighboring positions x + r. Do not confuse the complex field with its phase

23
Now evaluate spatial coherence function C (r) For a Gaussian random variable with zero mean, So So finding spatial coherence function C (r) amounts to evaluating the structure function for phase D ( r ) !

24
Next solve for D ( r ) in terms of the turbulence strength C N 2 We want to evaluate Remember that

25
Solve for D ( r ) in terms of the turbulence strength C N 2, continued But for a wave propagating vertically (in z direction) from height h to height h + h. This means that the phase is the product of the wave vector k (k= [radian/m]) x the Optical path Here n(x, z) is the index of refraction. Hence

26
Solve for D ( r ) in terms of the turbulence strength C N 2, continued Change variables: Then Algebra…

27
Solve for D ( r ) in terms of the turbulence strength C N 2, continued Now we can evaluate D ( r ) Algebra…

28
Solve for D ( r ) in terms of the turbulence strength C N 2, completed But

29
Finally we can evaluate the spatial coherence function C (r) For a slant path you can add factor ( sec ) 5/3 to account for dependence on zenith angle Concept Question: Note the scaling of the coherence function with separation, wavelength, turbulence strength. Think of a physical reason for each.

30
Given the spatial coherence function, calculate effect on telescope resolution Define optical transfer functions of telescope, atmosphere Define r 0 as the telescope diameter where the two optical transfer functions are equal Calculate expression for r 0

31
Define optical transfer function (OTF) Imaging in the presence of imperfect optics (or aberrations in atmosphere): in intensity units Image = Object Point Spread Function I = O PSF dx O(r - x) PSF ( x ) Take Fourier Transform: F ( I ) = F (O ) F ( PSF ) Optical Transfer Function is Fourier Transform of PSF: OTF = F ( PSF ) convolved with

32
Examples of PSF’s and their Optical Transfer Functions Seeing limited PSF Diffraction limited PSF Intensity Seeing limited OTF Diffraction limited OTF / r 0 / D r 0 / D / r 0 / D / -1

33
Now describe optical transfer function of the telescope in the presence of turbulence OTF for the whole imaging system (telescope plus atmosphere) S ( f ) = B ( f ) T ( f ) Here B ( f ) is the optical transfer fn. of the atmosphere and T ( f) is the optical transfer fn. of the telescope (units of f are cycles per meter). f is often normalized to cycles per diffraction-limit angle ( / D). Measure the resolving power of the imaging system by R = df S ( f ) = df B ( f ) T ( f )

34
Derivation of r 0 R of a perfect telescope with a purely circular aperture of (small) diameter d is R = df T ( f ) = ( / 4 ) ( d / ) 2 (uses solution for diffraction from a circular aperture) Define a circular aperture r 0 such that the R of the telescope (without any turbulence) is equal to the R of the atmosphere alone: df B ( f ) = df T ( f ) ( / 4 ) ( r 0 / ) 2

35
Derivation of r 0, continued Now we have to evaluate the contribution of the atmosphere’s OTF: df B ( f ) B ( f ) = C ( f ) (to go from cycles per meter to cycles per wavelength) Algebra…

36
Derivation of r 0, continued Now we need to do the integral in order to solve for r 0 : ( / 4 ) ( r 0 / ) 2 = df B ( f ) = df exp (- K f 5/3 ) Now solve for K: K = 3.44 (r 0 / ) -5/3 B ( f ) = exp ( f / r 0 ) 5/3 = exp ( / r 0 ) 5/3 (6 / 5) (6/5) K -6/5 Replace by r Algebra…

37
Derivation of r 0, concluded

38
Scaling of r 0 r 0 is size of subaperture, sets scale of all AO correction r 0 gets smaller when turbulence is strong (C N 2 large) r 0 gets bigger at longer wavelengths: AO is easier in the IR than with visible light r 0 gets smaller quickly as telescope looks toward the horizon (larger zenith angles )

39
Typical values of r 0 Usually r 0 is given at a 0.5 micron wavelength for reference purposes. It’s up to you to scale it by -1.2 to evaluate r 0 at your favorite wavelength. At excellent sites such as Paranal, r 0 at 0.5 micron is cm. But there is a big range from night to night, and at times also within a night. r 0 changes its value with a typical time constant of 5-10 minutes

40
Phase PSD, another important parameter Using the Kolmogorov turbulence hypothesis, the atmospheric phase PSD can be derived and is This expression can be used to compute the amount of phase error over an uncorrected pupil

41
Units: Radians of phase / (D / r 0 ) 5/6 Reference: Noll76 Tip-tilt is single biggest contributor Focus, astigmatism, coma also big High-order terms go on and on….

42

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google