# TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

## Presentation on theme: "TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand."— Presentation transcript:

TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz. CLICK TO CONTINUE

The element sulfur, S(s), contains 6.022 x 10 23 S atoms/mole. The compound carbon dioxide, CO 2 (g), contains 6.022 x 10 23 CO 2 molecules/mole. The compound bromine, Br 2 (l), contains 6.022 x 10 23 Br 2 molecules/mole. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE

S(s) = 32.066 g/mol Br 2 (l) = 159.808 g/mol CO 2 (g) = 44.010 g/mol LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE

S(s)  16 cm 3 /mol Br 2 (l)  51 cm 3 /mol CO 2 (g)  2 x 10 4 cm 3 /mol At room temperature and pressure: LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE

sulfur atoms, S atomic weight = 32.066  32.066 g S/mol S bromine molecules, Br 2 atomic weight = 79.904  molecular weight 159.808  159.808 g Br 2 /mol Br 2 carbon dioxide molecules, CO 2 atomic weights carbon 12.011, oxygen 15.9994 molecular weight 44.010  44.010 g CO 2 /mol CO 2 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE

1.Convert 30 g carbon to moles. C: atomic weight 12.011 12.011 g C/mol C LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE mass (g) carbon  moles carbon (Convert 30 g C to mol.)

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE (Convert 30 g C to mol.) 30 g C 1 12.011 x _________ mole C g C 30 mole C 12.011 = 2.5 mol C

2. Convert 3.5 liters of ammonia at S.T.P. to moles.

volume (L) ammonia  moles ammonia 22.414 L/mole NH 3 (g) (at S.T.P.) CLICK TO CONTINUE (Convert 3.5 L NH 3 at S.T.P. to mol.) LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

___________ LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE (Convert 3.5 L NH 3 at S.T.P. to mol.) 3.5 L NH 3 x 3.5 mol NH 3 22.414 = 0.16 mol NH 3 mol NH 3 L NH 3 1 22.414

M (molar) = mol solute/L solution 0.5 M glucose = 0.5 mol glucose/1 L soln 3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution?

volume (mL) solution  volume (L) solution  moles solvent LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE (# mol glucose in 10 mL 0.5 M soln?)

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 10 mL solutionx 1 1000 or 10 mL solution x 1 L 10 3 mL or 10 mL solution x 10 -3 L 1 mL ______ L mL CLICK TO CONTINUE (# mol glucose in 10 mL 0.5 M soln?)

10 mL solution x 1 L 1000 mL or 10 mL solution x 1 L 10 3 mL or 10 mL solution x 10 -3 L 1 mL x mol glucose L solution LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY x mol glucose L solution 0.5 1 0.5 1 0.5 1 CLICK TO CONTINUE (# mol glucose in 10 mL 0.5 M soln?)

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE 10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution or 10 mL solution x 1 L x 0.5 mol glucose 10 3 mL 1 L solution or 10 mL solution x 10 -3 L x 0.5 mol glucose 1 mL 1 L solution (# mol glucose in 10 mL 0.5 M soln?)

10 x 0.5 mol glucose 1000 or 10 x 0.5 mol glucose 10 3 or 10 x 10 -3 x 0.5 mol glucose = 0.005 or 5 x 10 -3 mol glucose LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) CLICK TO CONTINUE

4. How many atoms are present in 4.0 moles of phosphine, PH 3 ?

4.0 atoms/molecule PH 3 moles phosphine  molecules phosphine  atoms CLICK TO CONTINUE (# atoms in 4.0 mol PH 3 ?)

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 4.0 mol PH 3 x 6.02 x 10 23 1 x atoms molecule PH 3 4141 molecules PH 3 mol PH 3 _____________________ CLICK TO CONTINUE (# atoms in 4.0 mol PH 3 ?)

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 4.0 mol PH 3 x 6.02 x 10 23 molecules PH 3 1 mol PH 3 x 4 atoms 1 molecules PH 3 4.0 x 6.02 x 10 23 x 4 atoms = 9.6 x 10 24 atoms ___________________ CLICK TO CONTINUE (# atoms in 4.0 mol PH 3 ?)

5. How many electrons are lost by ionization of 0.65 moles of calcium?

Ca  2+ + 2e moles calcium  atoms calcium  electrons LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE (# electrons lost by 0.65 mol Ca?)

x electrons atom Ca 0.65 mol Cax __________________ atoms Ca mol Ca 6.02 x 10 23 1 2121 LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY CLICK TO CONTINUE (# electrons lost by 0.65 mol Ca?)

0.65 x 6.02 x 10 23 x 2 electrons = 7.8 x 10 23 electrons END OF TUTORIAL LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY 0.65 mol Ca x 6.02 x 10 23 atoms Ca 1 mol Ca x2 electrons 1 atom Ca (# electrons lost by 0.65 mol Ca?) CLICK TO CONTINUE