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Elgamal demonstration project on calculators TI-83+ Gerard Tel Utrecht University With results from Jos Roseboom and Meli Samikin.

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Presentation on theme: "Elgamal demonstration project on calculators TI-83+ Gerard Tel Utrecht University With results from Jos Roseboom and Meli Samikin."— Presentation transcript:

1 Elgamal demonstration project on calculators TI-83+ Gerard Tel Utrecht University With results from Jos Roseboom and Meli Samikin

2 Workshop Elgamal 2 Overview of the lecture 1.History and background 2.Elgamal (Diffie Hellman) 3.Discrete Log: Pollard rho 4.Experimentation results 5.Structure of Function Graph: Cycles, Tails, Layers 6.Conclusions

3 Workshop Elgamal 3 1. History and background 1.2003, lecture for school teachers about Elgamal 2.2006, lecture with calculator demo Why Elgamal, not RSA? Functional property easy to show Security: rely on complexity Compare exponentiation and DLog

4 Workshop Elgamal 4 Programming Experiences Nuisances: –typing by selecting symbols –no subroutines: inline exponentiation –no local variables Limitation: arithmetic in 14 digits –Limit modulus to 7 digits

5 Workshop Elgamal 5 Math: Modular arithmetic Compute modulo prime p (95917) with 0, 1, … p-2, p-1 Generator g of order q (prime) (g is 29609, q is 7993) Rules of algebra are valid (g a ) k = (g k ) a Secure application: p has ~309 digits!!

6 Workshop Elgamal 6 Calculator TI-83, 83+, 84+ Grafical, 14 digit Programmable Generally available in VWO (pre- academic school type in the Netherlands) Cost 100 euro (free for me)

7 Workshop Elgamal 7 The Elgamal program Ceasar cipher (symmetric) Elgamal parameter and key generation Elgamal encryption and decryption Discrete Logarithm: Pollard Infeasible problem!! But doable for 7 digit modulus

8 Workshop Elgamal 8 2. Public Key codes The problem of Key Agreement: A and B are on two sides of a river They want to have common z Oscar is in a boat on the river Oscar must not know z Common parameters: p, q, g (Or: group with hard DLog problem)

9 Workshop Elgamal 9 Solution: Diffie-Hellman Alice takes random a, shouts b = g a Bob takes random k, shouts u = g k Alice computes z = u a = (g k ) a Bob computes z = b k = (g a ) k The two numbers are the same The difference in complexity for A&B and O is relevant

10 Workshop Elgamal 10 Parameter generation Hoofdmenu, parameters, Maak p,q,r Input limits on q and p Search for prime q from q-limit down Search for prime p from p-limit down among multiples of 2q + 1 Generator: try 100 (p-1)/q, 101 (p-1)/q, …

11 Workshop Elgamal 11 What does Oscar hear? Seen: 1.Public b = g a 2.Public u = g k Not computable: 1.Secret a, k 2.Common z This needs discrete logarithm Oscar sees the communication, but not the secrets

12 Workshop Elgamal 12 The Elgamal program In class use Program, explanation, slides on website Program extendible Booklet with ideas for experimenting, papers All in Dutch!

13 Workshop Elgamal 13 3. Pollard Rho Algorithm Fixed p (modulus), g, q (order of g); H is set of powers of g Size of H is q Discrete Logarithm problem: –Given y in H –Return x st g x = y Pollard Rho: randomized, √q time

14 Workshop Elgamal 14 Pollard Rho: Representation Representation of z: z = y a.g b Two representations of same number reveil log y: If y a.g b = y c.g d, then y = g (b-d)/(c-a) Goal: find 2 representations of one number z (value does not matter)

15 Workshop Elgamal 15 Strategy: Birthday Theorem All values z = y a.g b are in H Birthday Theorem: In a random sequence, we expect a collision after √q steps Simulate effect of random sequence by pseudorandom function: z i+1 = f (z i ) (Keep representation of each z i )

16 Workshop Elgamal 16 Cycle detection Detect collision by storing previous values: too expensive Floyd cycle detection method: –Develop two sequences: z i and t i –Relation: t i = z 2i –Collision: t i = z i, i.e., z i = z 2i In each round, z “moves” one step and t moves two steps.

17 Workshop Elgamal 17 4. Experimentation results pqxm12345Ave 97197438168 811,2 39899971141030 60156039 39869996743117 53104,2 3986999671144151926519265192141,2 9996119996143335 99961199961116683 99961199961114415680340 680476 Spring 2006, by Barbara ten Tusscher, Jesse Krijthe, Brigitte Sprenger

18 Workshop Elgamal 18 Barbara, Jesse, Brigitte Verify Pollard rho analysis Use various values of p, q, y Clear dependence of time on q Ignoring 80, cor- relation to √q is overly exact. pqav. it 9996839719 99700199768 957409997380 99961199961683

19 Workshop Elgamal 19 Dependence on y Run same p, q combination with different inputs y = g x Correspondence to √q again Not to x: the log of small power of g is no easier pqxtime 3989997444 39899971116 398999711439 999611999614335 99961199961114297 9996119996111144266

20 Workshop Elgamal 20 Surprise: individual numbers pqx12345 99961199961 4335 99961199961 11683 99961199961 114103392206392 99961199961 1144680340 680 99961199961 11144158120300390360 Iterations: equal or have high common factor!

21 Workshop Elgamal 21 Observations Average number of iterations coincides well with √q Almost no variation within one row Is this a bug in the program?? –Bad randomization in calculator? –Or general property of Pollard Rho?

22 Workshop Elgamal 22 5. Function graph Function f: z i -> z i+1 defines graph Out-degree 1, cycles with in-trees Length, component, size Graph is the same when algorithm is repeated with the same input Starting point differs As z i = z 2i, i must be multiple of cycle length

23 Workshop Elgamal 23 Layers in a component Layer of node: measure distance to cycle in terms of its length l: –Point z in cycle has layer 0 –Point z is in layer 1 if f (l) (z) in cycle –Point z is in layer c if f (c.l) (z) in cycle Lemma: z 0 in layer c gives c.l iter. Is there a dominant component or layer?

24 Workshop Elgamal 24 Layers 0 and 1 dominate Probability theory analysis by Meli Samikin Lemma: Pr(layer ≤ 1) = ½ Proof: Assume collision after k steps: z 0 -> z 1 -> … -> … -> z k-1 -> ?? Layer of z 0 is 0 if z k = z 0, Pr = 1/k Layer of z 0 is 1 if z k = z j < k/2, Pr ≈ 1/2

25 Workshop Elgamal 25 Dominant Component Lemma: Random z 0 and w 0, Pr(same component) > ½. Proof: First collision after k steps: z 0 -> z 1 -> … -> … -> z k-1 -> ?? w 0 -> w 1 -> … -> … -> w k-1 -> ?? Pr ( z meets other sequence ) = ½. Then, w-sequence may collide into z.

26 Workshop Elgamal 26 Experiments: dominance Jos Roseboom: count points in layers of each component ACS Experimentation Project, Fall 2007 Explicitly construct and measure function graphs

27 Workshop Elgamal 27 Size of largest component

28 Workshop Elgamal 28 Conclusions Elgamal + handcalculators = fun Functional requirements easier to explain than for RSA Security: experiment with DLog Pollard, only randomizes at start Iterations: random variable, but takes only limited values Most often: size of heaviest cycle

29 Workshop Elgamal 29 Rabbit Formula Ontsleutelen is: v delen door u a u (a1+a2) is: u a1.u a2 Deel eerst door u a1 en dan door u a2 Team 1: bereken v’ = Dec a1 (u, v) Team 2: bereken x = Dec a2 (u, v’)

30 Workshop Elgamal 30 Overzicht van formules Constanten: Priemgetal p, grondtal g Sleutelpaar: Secret a en Public b = g a Encryptie: (u, v) = (g k, x.b k )met b Decryptie: x = v/u a met a Prijsvraag: b = b 1 b 2. Ontsleutelen?

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