#  Translational ….. Circular…..now rotational  Difference between Circular & Rotational motion  CAUSES…. F net F C, and now  NET  Vector – direction.

## Presentation on theme: " Translational ….. Circular…..now rotational  Difference between Circular & Rotational motion  CAUSES…. F net F C, and now  NET  Vector – direction."— Presentation transcript:

 Translational ….. Circular…..now rotational  Difference between Circular & Rotational motion  CAUSES…. F net F C, and now  NET  Vector – direction & units

REQUIREMENT: F and d must be 

10 N 6 N  = 10(1.5)  = 15 N-m CCW

10 N 6 N  = 10(1.5)  = 10(3)  = 15 N-m  = 30 N-m CCWCW

10 N 6 N  = 10(1.5)  = 10(3)  = 6(4.5)  = 15 N-m  = 30 N-m  = 27 N-m CCWCW  NET = 42 N-m CW

20 N 32 N 12 N 20 N 12 N  = 20(7)  = 140 Nm CW  = 32(5)  = 160 Nm CCW  = 12(2.5)  = 30 Nm CW  = 20(2)  = 40 Nm CCW  = 12(5)  = 60 Nm CCW  NET = 90 N-m CCW

20 N 28 N 20 N 40º 20º 40º  = sin40(20)(2)  = 25.7 Nm CW  = sin20(28)(1)  = 9.57 Nm CW  = sin40(20)(3)  = 38.6 Nm CCW  NET = 3.33 N-m CCW

53 

545 315 T 53° ROTATIONAL CW = CCW 545 (1.5)+ 315 (2.5)= sin53 T (5) T = 402 N

545 315 T 53° TRANSLATIONAL NEED: 539 UP 321 242 242 RIGHT 539 242 591 N 66° above the hor

FNFN W bridge W bear ROTATIONAL CW = CCW F N (12) = 250(9.8)(6) + 900(9.8)(4) F N = 4165 N

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