# Digital to Analogue Conversion

## Presentation on theme: "Digital to Analogue Conversion"— Presentation transcript:

Digital to Analogue Conversion

Analogue  Digital Conversion
Analog and digital data were briefly mentioned at the start A digital signal is an approximation of an analog one Levels of signal are sampled and converted to a discrete bit pattern. Digital signal processing is used, for example, to enhance and compress images, to process sounds to generate speech, etc, etc.

Step (discrete) Approximation
“stair-step” approximation of original signal sample level more samples give greater accuracy time hold time for sample

Objectives To understand how a digital value can be converted to an analogue value To draw circuits and explain the operation of two digital to analogue converters: the binary weighted resistor network and the R-2R ladder network To draw the block diagram and explain the operation of three analogue to digital converters: flash, counter ramp and successive approximation To be able to calculate the conversion time for an analogue to digital converter To be able to explain the sampling rule To be able to describe the basic design of a sample and hold circuit and explain how it works

The binary weighted resistor network
Comprises of a register and resistor network Output of each bit of the register will depend on whether a 1 or a 0 is stored in that position e.g. for a 0 then 0V output for a 1 then 5V output Resistance R is inversely proportional to binary weight of each digit R MSB 4-bit register 2R RL VL 4R 8R LSB

Buffering the resistor network
Best solution is to follow the resistor network with a buffer amplifier Has high impedance, practically no current flows All input currents sum at S and go through Rf Vo = -IfRf V = - I R = - ( I + I + I + I ) R o f f 1 2 3 4 f

Digital-to-Analogue Example
Calculate the output voltage for an input code word 0110 if a logic 1 is 10V and a logic 0 is 0V, and R = RF=1k I1 = I4 = 0 I2 = 10v / 2R = 10 / 2k = 5 mA I3 = 10v / 4R = 10 / 4k = 0.25 mA Vo = -If x Rf = -(0.0075) x 1000 = -7.5 volts V = - I R = - ( I + I + I + I ) R o f f 1 2 3 4 f

The binary weighted resistor network
Seldom used when more than 6 bits in the code word to illustrate the problem consider the design of an 8-bit DAC if the smallest resistor has resistance R what would be the value of the largest resistor? what would be the tolerance of the smallest resistor? Very difficult to manufacture very accurate resistors over this range

Has a resistor network which requires resistance values that differ 2:1 for any sized code word The principle of the network is based on Kirchhoff's current rule The current entering N must leave by way of the two resistors R1 and R2

Works on a current dividing network Resistance to right of B = 1/(1/2R + 1/2R) Resistance to right of A = R +2R/2 = 2R Current divides I1 = I/ I2 = I/4 divides again

The network of resistors to the right of A have an equivalent resistance of 2R, and so the right hand resistance can be replaced by a copy of the network Bit Current 3 I/2 2 I/4 1 I/8 0 I/16 bit bit bit bit 0

The state of the bits is used to switch a voltage source V = -R ( b I 2 + b I 4 + b I 8 + b I 16 ) 1 o f 3 2

Example V = -R ( b I 2 + b I 4 + b I 8 + b I 16 ) 1 o f 3 2 For the circuit shown above with I = 10 mA and Rf = 2k, calculate the output voltage V0 for an input code word 1110.

Example I = 10mA Rf = 2k input code word 1110
Vo = -2000( 0.01/ / /8 + (0 x 0.1)/8 ) = * ( ) / 8 = 17.5 volts

Quantisation Suppose we want to use a D-A converter to generate the sawtooth waveform (graph shown on the left) End up with stair-case waveform (graph shown on the right) The 16 possible values of the D-A converter output are called the quantisation levels The difference between two adjacent quantisation levels is termed a quantisation interval

Quantisation Error Difference between the two waveforms is the quantisation error Maximum quantisation error is equal to half the quantisation interval One way to reduce the quantisation error (noise) is to increase the number of bits used by the D-A converter quantisation interval 111 110 101 100 011 010 001 000 bands or quanta 1001 1000 0111 0110 0101 0100 0011 0010 0001 0000 samples

Quantisation Noise The voltage produced by the DA convertor can be regarded as the original signal plus noise: This is the quantisation noise.

Summary We have looked at techniques for converting a digital codeword into an analogue voltage using a weighted resistor network. In particular: the binary weighted network (not suitable for large resolution D-A converters) the R-2R ladder The addition of an amplifier minimises the loading effects on the weighted network The conversion from digital to analogue involves a quantisation process that limits the resolution and introduces the quantisation noise. This quantisation error can be reduced by increasing the number of bits in the converter.