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Geol 491: Spectral Analysis

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1 Geol 491: Spectral Analysis

2 5*sin (2  4t) Amplitude = 5 Frequency = 4 Hz seconds Fourier said that any single valued function could be reproduced as a sum of sines and cosines Introduction to Fourier series and Fourier transforms

3 5*sin(2  4t) Amplitude = 5 Frequency = 4 Hz Sampling rate = 256 samples/second seconds Sampling duration = 1 second We are usually dealing with sampled data

4 Faithful reproduction of the signal requires adequate sampling If our sample rate isn’t high enough, then the output frequency will be lower than the input,

5 The Nyquist Frequency The Nyquist frequency is equal to one-half of the sampling frequency. The Nyquist frequency is the highest frequency that can be measured in a signal. Where  t is the sample rate Frequencies higher than the Nyquist frequencies will be aliased to lower frequency

6 The Nyquist Frequency Where  t is the sample rate Thus if  t = seconds, f Ny =

7 Fourier series: a weighted sum of sines and cosines Periodic functions and signals may be expanded into a series of sine and cosine functions

8 This applet is fun to play with & educational too. Experiment with

9 Try making sounds by combining several harmonics (multiples of the fundamental frequency) An octave represents a doubling of the frequency. 220Hz, 440Hz and 880Hz played together produce a “pleasant sound” Frequencies in the ratio of 3:2 represent a fifth and are also considered pleasant to the ear. 220, 660, 1980etc. Pythagoras (530BC)

10 You can also observe how filtering of a broadband waveform will change audible waveform properties.

11 Fourier series The Fourier series can be expressed more compactly using summation notation You’ve seen from the forgoing example that right angle turns, drops, increases in the value of a function can be simulated using the curvaceous sinusoids.

12 Fourier series Try the excel file step2.xls

13 The Fourier Transform A transform takes one function (or signal) in time and turns it into another function (or signal) in frequency This can be done with continuous functions or discrete functions

14 The Fourier Transform The general problem is to find the coefficients: a 0, a 1, b 1, etc. Take the integral of f(t) from 0 to T (where T is 1/f). Note  =2  /T What do you get? Looks like an average! We’ll work through this on the board.

15 Getting the other Fourier coefficients To get the other coefficients consider what happens when you multiply the terms in the series by terms like cos(i  t) or sin(i  t).

16 Now integrate f(t) cos(i  t) This is just the average of i periods of the cosine

17 Now integrate f(t) cos(i  t) Use the identity If i=2 then the a 1 term =

18 What does this give us? And what about the other terms in the series?

19 In general to find the coefficients we do the following and The a’s and b’s are considered the amplitudes of the real and imaginary terms (cosine and sine) defining individual frequency components in a signal

20 Arbitrary period versus 2  Sometimes you’ll see the Fourier coefficients written as integrals from -  to  and

21 Exponential notation cos  t is considered Re e i  t where

22 The Fourier Transform A transform takes one function (or signal) and turns it into another function (or signal) Continuous Fourier Transform:

23 A transform takes one function (or signal) and turns it into another function (or signal) The Discrete Fourier Transform: The Fourier Transform

24 Some useful links –Fourier series java applet –Collection of demonstrations about digital signal processing –FFT tutorial from National Instruments –Dictionary of DSP terms FT4FreeIndDecay.pdfhttp://jchemed.chem.wisc.edu/JCEWWW/Features/McadInChem/mcad008/ FT4FreeIndDecay.pdf –Mathcad tutorial for exploring Fourier transforms of free-induction decay –This presentation

25 Meeting times?


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