Presentation is loading. Please wait.

Presentation is loading. Please wait.

1 ECE 480 Wireless Systems Lecture 4 Propagation and Modulation of RF Waves.

Similar presentations


Presentation on theme: "1 ECE 480 Wireless Systems Lecture 4 Propagation and Modulation of RF Waves."— Presentation transcript:

1 1 ECE 480 Wireless Systems Lecture 4 Propagation and Modulation of RF Waves

2 2 Antenna Radiation Characteristics Antenna pattern: Describes the far – field directional properties of an antenna when measured at a fixed distance from the antenna 3 – d plot that displays the strength of the radiated field (or power density) as a function of direction (spherical coordinates) specified by the zenith angle  and the azimuth angle  From reciprocity, a receiving antenna has the same directional antenna pattern as the pattern that it exhibits when operated in the transmission mode

3 3 The differential power through an elemental area dA is always in the radial direction in the far – field region

4 4 Define: Solid angle,  for a spherical surface

5 5 The total power radiated by an antenna is given by

6 6 is the normalized radiation intensity

7 7 3 – D Pattern of a Narrow – Beam Antenna

8 8 Antenna Pattern It is convenient to characterize the variation of F ( ,  ) in two dimensions Elevation Plane (  - plane) Corresponds to a single value of  (  = 0 x –z plane) (  = 90 y –z plane) Azimuth Plane (  - plane) Corresponds to  = 90 o (x – y plane) Two principle planes of the spherical coordinate system

9 9 Clearer to express F in db for highly directive patterns  = 0 plane

10 10 Side lobes are undesirable Wasted energy Possible interference

11 11 Beam Dimensions Define: Pattern solid angle  p  p = Equivalent width of the main lobe For an isotropic antenna with F ( ,  ) = 1 in all directions:

12 12 Defines an equivalent cone over which all the radiation of the actual antenna is concentrated with equal intensity signal equal to the maximum of the actual pattern

13 13 The half – power (3 dB) beamwidth, , is defined as the angular width of the main lobe between the two angles at which the magnitude of F ( ,  ) is equal to half its peak value

14 14 F (  ) is max at  = 90 o,  2 = 135 0,  1 = 45 o,  = 135 o – 45 o = 90 o

15 15 Null Beamwidth,  null Beamwidth between the first nulls on either side of the peak

16 16 Antenna Directivity  p = Pattern solid angle For an isotropic antenna,  p = 4  D = 1

17 17 D can also be expressed as S iso = power density radiated by an isotropic antenna D = ratio of the maximum power density radiated by the antenna to the power density radiated by an isotropic antenna

18 18 For an antenna with a single main lobe pointing in the z direction:

19 19 Example – Antenna Radiation Properties Determine: a.The direction of maximum radiation b.Pattern solid angle c.directivity d.half – power beamwidth in the y-z plane for an antenna that radiates into only the upper hemisphere and its normalized radiation intensity is given by

20 20 Solution The statementin the upper hemisphere can be written mathematically as

21 21 a. The function is maximum when  = 0 Polar plot of b. The pattern solid angle is given by

22 22 Polar plot of c. d. The half – power by setting

23 23 Example – Directivity of a Hertzian Dipole For a Hertzian dipole:

24 24 Antenna Gain Define: Radiation Efficiency,  P t = Transmitter power sent to the antenna P rad = Power radiated into space P loss = Power loss due to heat in the antenna = P t – P rad  = 1 for a lossless antenna

25 25 Define: Antenna Gain, G Accounts for the losses in the antenna

26 26 Radiation Resistance P loss = Power loss due to heat in the antenna = P t – P rad

27 27 To find the radiation resistance: Find the far – field power by integrating the far – field power density over a sphere Equate to

28 28 Example – Radiation Resistance and Efficiency of a Hertzian Dipole A 4 – cm long center – fed dipole is used as an antenna at 75 MHz. The antenna wire is made of copper and has a radius a = 0.4 mm. The loss resistance of a circular wire is given by Calculate the radiation resistance and the radiation efficiency of the dipole antenna

29 29 Solution The parameters of copper are

30 30 At 75 MHz:  This is a short dipole From before,

31 31

32 32 Half – Wave Dipole Antenna In phasor form:

33 33 For a short dipole Expand these expressions to obtain similar expressions for the half – wave dipole

34 34 Consider an infinitesimal dipole segment of length dz excited by a current and located a distance from the observation point

35 35 The far field due to radiation by the entire antenna is given by Two assumptions: (length factor)

36 36 Note that "s" appears in the equation twice – once for the distance away and once for the phase factor is not valid for the length factor If Q is located at the top of the dipole, the phase factor is which is not acceptable

37 37

38 38

39 39 is max when

40 40 Directivity of Half – Wave Dipole Need P rad and S (R,  )

41 41 Radiation Resistance of Half – Wave Dipole Recall: for the short dipole ( l = 4 cm) at 75 MHz R rad = 0.08  R loss =  For the half – wave dipole ( l = 4 m) at 75 MHz R loss = 1.8 

42 42 Effective Area of a Receiving Antenna Assume an incident wave with a power density of S i The effective area of the antenna, A e, is P int = Power intercepted by the antenna It can be shown: = Magnitude of the open – circuit voltage developed across the antenna

43 43 The power density carried by the wave is For the short dipole

44 44 In terms of D: Valid for any antenna Example: Antenna Area The effective area of an antenna is 9 m 2. What is its directivity in db at 3 GHz?

45 45 Friis Transmission Formula Assumptions: Each antenna is in the far – field region of the other Peak of the radiation pattern of each antenna is aligned with the other Transmission is lossless

46 46 For an isotropic antenna:(ideal) In the practical case, In terms of the effective area A t of the transmitting antenna

47 47 On the receiving side, Friis transmission formula

48 48 When the antennas are not aligned (More general expression)

49 49 Homework 1. Determine the following: a. The direction of maximum radiation b. Directivity c. Beam solid angle d. Half – power beamwidth in the x – z plane for an antenna whose normalized radiation intensity is given by: Hint: Sketch the pattern first

50 50 2. An antenna with a pattern solid angle of 1.5 (sr) radiates 30 W of power. At a range of 1 km, what is the maximum power density radiated by the antenna? 3. The radiation pattern of a circular parabolic – reflector antenna consists of a circular major lobe with a half – power beamwidth of 2 o and a few minor lobes. Ignoring the minor lobes, obtain an estimate for the antenna directivity in dB.

51 51 Analog Modulation Several basic types Amplitude modulation (AM) Frequency modulation (FM) Pulse code modulation (PCM) Pulse width modulation (PWM) High frequencies require smaller antennas Modulation impresses a lower frequency onto a higher frequency for easier transmission The signal is modulated at the transmission end and demodulated at the receiving end

52 52 Amplitude Modulation Carrier wave – High frequency signal that transports the intelligence Signal wave – Low frequency signal that contains the intelligence

53 53 AM transmitter DC shifts the modulating signal Multiplies it with the carrier wave using a frequency mixer Mixer must be nonlinear Output is a signal with the same frequency as the carrier with peaks and valleys that vary in proportion to the strength of the modulating signal Signal is amplified and sent to the antenna

54 54 The mixer is usually a "square law" device, such as a diode or B – E junction of a transistor Suppose that we apply the following signals to a square law device The output will be

55 55 Homework Determine all possible output frequencies

56 56 Advantages Simplicity Cost Disadvantages Susceptible to atmospheric interference (static) Narrow bandwidth (550 – 1500 KHz)

57 57 AM Receiver Tunable filter Envelope detector (diode) Capacitor is used to eliminate the carrier and to undo the DC shift Will generally include some form of automatic gain control (AGC)

58 58 Forms of Amplitude Modulation In the most basic form, an AM signal in the frequency domain consists of The carrier signal Information at f c + f m (upper sideband) Information at f c - f m (lower sideband) (US and LS are mirror images) This wastes transmission power Carrier contains no information Information is all contained in only one of the sidebands

59 59 Frequently, in communications systems, the carrier and/or one of the sidebands is suppressed or reduced If only the carrier is reduced or suppressed, the process is called "Double – Sideband Suppressed (Reduced) Carrier" (DSSC or DSRC) If the carrier and one of the sidebands is suppressed or reduced, the process is called "Single – Sideband Suppressed (Reduced) Carrier" (SSSC or SSRC) Often, the carrier and one of the sidebands is totally suppressed. This process is simply called "Single Sideband" The carrier must be regenerated at the receiver end

60 60 Example Consider a carrier with a frequency  c Suppose we want to modulate the carrier with a signal The signal is amplitude – modulated by adding m(t) to C The expression for this signal is Expanding this expression

61 61 Convert to frequency domain by taking the Fourier Transform Take Fourier Transform = Unit impulse function

62 62 Eff = 33 %Eff = 100 %

63 63 Modulation Index Measure of the modulating signal wrt the carrier signal

64 64

65 65


Download ppt "1 ECE 480 Wireless Systems Lecture 4 Propagation and Modulation of RF Waves."

Similar presentations


Ads by Google