Presentation is loading. Please wait.

# Describing and Dynamics

## Presentation on theme: "Describing and Dynamics"— Presentation transcript:

Describing and Dynamics
Rotational Motion Describing and Dynamics

Rotational Motion Describing Rotational Motion Grad = revolution
Fractions of revolution measured in grads, degrees, or radians Grad = revolution Degree = revolution Radian = revolution

Rotational Motion Angular Displacement
Theta, θ, represents angle of revolution Counterclockwise rotation positive, clockwise negative Change in angle = angular displacement d = rθ Displacement (d) = rotation through angle, θ, at distance, r, from center

Rotational Motion Angular Velocity
Velocity = displacement divided by time Angular velocity is angular displacement divided by time required to make displacement Angular velocity is represented by the Greek letter omega, ω

Rotational Motion Angular Velocity
If velocity changes over time, average velocity not equal to instantaneous velocity at any given instant Angular velocity = average angular velocity over a time interval, t Instantaneous angular velocity = slope of graph of angular position versus time Measured in rad/s So, for Earth, ωE = (2π rad)/[(24.0 h)(3600 s/h)] = 7.27×10─5 rad/s

Rotational Motion Angular Velocity v = rω
Counterclockwise rotation also results in positive angular velocity If angular velocity is ω, then linear velocity of point at distance, r, from axis of rotation given by Speed at which object on Earth’s equator moves due to Earth’s rotation is v = r ω = (6.38×106 m) (7.27×10─5 rad/s) = 464 m/s v = rω

Rotational Motion Angular Acceleration
Change in angular velocity divided by time required to make that change Measured in rad/s2 If △𝑣 positive, then ω also positive Angular acceleration also average angular acceleration over time interval Δt

Rotational Motion Angular Acceleration a = r
Find instantaneous angular acceleration by finding slope of graph of angular velocity as function of time Linear acceleration of point at r from axis of object with angular acceleration, α, given by a = r

Rotational Motion Angular Acceleration
A summary of linear and angular relationships

Rotational Motion Angular Frequency
Number of complete revolutions made by object in 1s called angular frequency Angular frequency, f, is given by the equation:

Rotational Motion Describing Rotational Motion
Jupiter, the largest planet in our solar system, rotates around its own axis in 9.84 h. The diameter of Jupiter is 1.43 x 108 m. What is the angular speed of Jupiter’s rotation in rad/s? What is the linear speed of a point on Jupiter’s equator, due to Jupiter’s rotation? A computer disk drive optimizes the data transfer rate by rotating the disk at a constant angular speed of 34.1 rad/s while being read. When the computer is searching for a file, the disk spins for s. What is the angular displacement of the disk during this time? Through how many revolutions does the disk turn during this time?

Rotational Motion Describing Rotational Motion
A cyclist wants to complete 10.0 laps around a circular track 1.0 km in diameter in exactly 1.0 h. At what linear velocity must this cyclist ride? A 75.0 g mass is attached to a 1.0 m length of string and whirled around in the air at a rate of 4.0 rev/s when the string breaks. What is the breaking force of the string? What was the linear velocity of the mass as soon as the string broke?

Rotational Motion Rotational Dynamics
Change in angular velocity depends on magnitude of force, distance from axis to point where force exerted, and direction of force To open door, you exert force. Doorknob near outer edge of door. Exert force on doorknob at right angles to door, away from hinges To get most effect from least force, exert force as far from axis of rotation as possible

Rotational Motion Rotational Dynamics
Magnitude of force, distance from axis to point where force exerted, and direction of force determine change in angular velocity Change in angular velocity depends on lever arm, perpendicular distance from axis of rotation to point where force exerted

Rotational Motion Rotational Dynamics
For door, distance from the hinges to point where force exerted If force perpendicular to radius of rotation then lever arm is distance from axis, r. If force not exerted perpendicular to radius, lever arm reduced

Rotational Motion Rotational Dynamics
Lever arm, L, calculated by equation, L = r sin θ, θ = angle between force and radius from axis of rotation to point where force applied Torque measures how effectively force causes rotation. Measured in newton-meters (N·m)

Rotational Motion Rotational Dynamics

Rotational Motion Rotational Dynamics
In order for a bolt to be tightened, a torque of 45.0 N•m is needed. You use a m long wrench, and you exert a maximum force of 189 N. What is the smallest angle, with respect to the wrench, at which you can exert this force and still tighten the bolt? Chloe, whose mass is 56 kg, sits 1.2 m from the center of a seesaw. Josh, whose mass is 84 kg, wants to balance Chloe. Where on the seesaw should Josh sit?

Rotational Motion The Moment of Inertia
Equal to mass of object times square of object’s distance from axis of rotation Resistance to changes in rotational motion Represented by symbol I and has units of mass times square of distance

Rotational Motion Newton’s Second Law for Rotational Motion
Angular acceleration directly proportional to net torque and inversely proportional to moment of inertia Changes in torque, or moment of inertia, affect rate of rotation

Rotational Motion Newton’s Second Law for Rotational Motion
A fisherman starts his outboard motor by pulling on a rope wrapped around the outer rim of a flywheel. The flywheel is a solid cylinder with a mass of 9.5 kg and a diameter of 15 cm. The flywheel starts from rest and after 12 s, it rotates at 51 rad/s. What torque does the fisherman apply to the flywheel (α= τ/I)? How much force does the fisherman need to exert on the rope to apply this torque?

Rotational Motion The Center of Mass
The center of mass of an object is the point on the object that moves in the same way that a point particle would move The path of the center of mass of the object below is a straight line

Rotational Motion The Center of Mass
To locate the center of mass of an object, suspend the object from any point When the object stops swinging, the center of mass is along the vertical line drawn from the suspension point Draw the line, and then suspend the object from another point. Again, the center of mass must be below this point Draw a second vertical line. The center of mass is at the point where the two lines cross A wrench, racket, and all other freely-rotating objects, rotate about an axis that goes through their center of mass

Rotational Motion The Center of Mass

Rotational Motion The Center of Mass of a Human Body
The center of mass of a person varies with posture For a person standing with his or her arms hanging straight down, the center of mass is a few centimeters below the navel, midway between the front and back of the person’s body

Rotational Motion The Center of Mass of a Human Body
When the arms are raised, as in ballet, the center of mass rises by 6 to10 cm By raising her arms and legs while in the air, as shown below, a ballet dancer moves her center of mass closer to her head The path of the center of mass is a parabola, so the dancer’s head stays at almost the same height for a surprisingly long time

Rotational Motion Center of Mass and Stability

Rotational Motion Center of Mass and Stability
An object is said to be stable if an external force is required to tip it The object is stable as long as the direction of the torque due to its weight, τw tends to keep it upright. This occurs as long as the object’s center of mass lies above its base To tip the object over, you must rotate its center of mass around the axis of rotation until it is no longer above the base of the object To rotate the object, you must lift its center of mass. The broader the base, the more stable the object is

Rotational Motion Center of Mass and Stability
If the center of mass is outside the base of an object, it is unstable and will roll over without additional torque If the center of mass is above the base of the object, it is stable If the base of the object is very narrow and the center of mass is high, then the object is stable, but the slightest force will cause it to tip over

Rotational Motion Conditions for Equilibrium
An object is said to be in static equilibrium if both its velocity and angular velocity are zero or constant First, it must be in translational equilibrium; that is, the net force exerted on the object must be zero Second, it must be in rotational equilibrium; that is, the net torque exerted on the object must be zero

Rotational Motion Rotating Frames of Reference
Newton’s laws are valid only in inertial or nonaccelerated frames Newton’s laws would not apply in rotating frames of reference, as they are accelerated frames Motion in a rotating reference frame is important to us because Earth rotates The effects of the rotation of Earth are too small to be noticed in the classroom or lab, but they are significant influences on the motion of the atmosphere and therefore on climate and weather

Rotational Motion Centrifugal “Force”
An observer on a rotating frame, sees an object attached to a spring on the platform He thinks that some force toward the outside of the platform is pulling on the object Centrifugal “force” is an apparent force that seems to be acting on an object when that object is kept on a rotating platform

Rotational Motion Centrifugal “Force”
As the platform rotates, an observer on the ground sees things differently This observer sees the object moving in a circle The object accelerates toward the center because of the force of the spring The acceleration is centripetal acceleration and is given by

Rotational Motion Centrifugal “Force”
It also can be written in terms of angular velocity, as: Centripetal acceleration is proportional to the distance from the axis of rotation and depends on the square of the angular velocity

Rotational Motion The Coriolis “Force”
A person standing at the center of a rotating disk throws a ball toward the edge of the disk. An observer standing outside the disk sees the ball travel in a straight line at a constant speed toward the edge of the disk

Rotational Motion The Coriolis “Force”
An observer stationed on the disk and rotating with it sees the ball follow a curved path at a constant speed A force seems to be acting to deflect the ball

Rotational Motion The Coriolis “Force”
An apparent force that seems to cause deflection to an object in a horizontal motion when the observer is in a rotating frame of reference is known as the Coriolis “force” It seems to exist because we observe a deflection in horizontal motion when we are in a rotating frame of reference

Rotational Motion The Coriolis “Force”
An observer on Earth, sees the Coriolis “force” cause a projectile fired due north to deflect to the right of the intended target The direction of winds around high- and low-pressure areas results from the Coriolis “force.” Winds flow from areas of high to low pressure

Rotational Motion The Coriolis “Force”
Due to the Coriolis “force” in the northern hemisphere, winds from the south blow east of low-pressure areas Winds from the north, however, end up west of low-pressure areas Therefore, winds rotate counterclockwise around low-pressure areas in the northern hemisphere In the southern hemisphere however, winds rotate clockwise around low-pressure areas

Download ppt "Describing and Dynamics"

Similar presentations

Ads by Google