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Crossing Structures Crossing structures are those constructed at intersections of: Crossing structures are those constructed at intersections of: 1. Waterway-road.

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Presentation on theme: "Crossing Structures Crossing structures are those constructed at intersections of: Crossing structures are those constructed at intersections of: 1. Waterway-road."— Presentation transcript:

1 Crossing Structures Crossing structures are those constructed at intersections of: Crossing structures are those constructed at intersections of: 1. Waterway-road (culvert or bridge). 1. Waterway-road (culvert or bridge). 2. Waterway-Waterway (syphon or aqueduct). 2. Waterway-Waterway (syphon or aqueduct). 3. Waterway ending at another waterway (tail escape). 3. Waterway ending at another waterway (tail escape).

2 Syphon or Aqueduct Water way Culvert or Bridge Road Water way Tail escape Water way

3 Culvert

4 The culvert is a closed conduit (pipe or box section) constructed to carry the discharge of a waterway under a road. The selection of the type of the culvert is based on the discharge as follows: For Q ≤ 3.0 m 3 /sec use Pipe culvert. For Q ≤ 3.0 m 3 /sec use Pipe culvert. For Q ≤ 12.0 m 3 /sec use Box section. For Q ≤ 12.0 m 3 /sec use Box section.

5 ≤.15 m d ≥.3 m D H S

6 Hydraulic Design The purpose of the hydraulic design is to select the culvert ’ s dimensions. The dimensions are selected based on: Velocity through culvert between 1.0 to 2.0 m/sec. Velocity through culvert between 1.0 to 2.0 m/sec. Head losses is less then 15 cm. Head losses is less then 15 cm. Entrance submergence is at least 30 cm. Entrance submergence is at least 30 cm.

7 The only equation available is the continuity equation: Q = A. V Q = A. V Where Q is the discharge in m 3 /sec, A is the culvert ’ s cross section area in m 2, and V is the water velocity through the culvert in m/sec. Since the discharge is known, the velocity must be assumed to determine the dimensions of the culvert. The velocity is usually assumed between 1.0 and 2.0 m/sec for practical reasons.

8 Once the dimensions are determined, then head losses must be checked. Head losses are calculated as follows, Where H l is the head losses in m V is the velocity in m/sec V is the velocity in m/sec g is the acceleration of gravity g is the acceleration of gravity

9 C e is the entrance coefficient of C e is the entrance coefficient of loss (= 0.5 ) loss (= 0.5 ) C f is the friction coefficient C f is the friction coefficient Co is the outlet coefficient of losses Co is the outlet coefficient of losses ( = 1.0 ) ( = 1.0 ) Friction coefficient can be calculated as follows,

10 Where f is coefficient depends on the culvert material and dimension, L is the length of the culvert and m is the hydraulic radius. The coefficient a and b are constant and depends on the material of the conduit. For Steel: a = , b = For Concrete: a = , b=

11 Example 1: Example 1: Design a culvert under a road. The discharge is 3 m 3 /sec and the water depth is 1.8 m. The culvert length is 20 m. Sol. Sol. Q = 3 m3/sec * use pipe culvert assume V=1.3 m/sec A = Q/V = 2.31 m 2 A = ∏ D 2 /4 * D = 1.7 m However, D ≤ 1.8 – 0.3 … 1.5 m

12 Then use 2 pipes … one pipe A = m 2 D = 1.3 m …. V = 1.13 m/sec … OK Check of heading up m = D/4 = m f = C f = 0.32 H u = (1.13) 2 /(2*9.81) *( ) = 0.12 m … OK = 0.12 m … OK

13 Example 2: Example 2: design a culvert under a road. The discharge is 5 m 3 /sec and the water depth is 2.2 m. The culvert length is 20 m. Sol. Sol. Q = 5 m 3 /sec … Use Box culvert Assume V = 1.3 m/sec A = Q/V = 3.85 m 2 H = 2.2 – 0.3 = 1.9 m S = 3.85/1.9 = 2.0 m

14 S < 1.5 H … OK V = 5/(1.9*2) = 1.32 m/sec Check for Heading Up m = 2*1.9/(2+1.9)*2= 0.49 m f = C f = 0.14 H u = m … OK


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