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A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses.

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Presentation on theme: "A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses."— Presentation transcript:

1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it. Compared to the electric flux through surface #1, the flux through surface #2 is A. greater.B. the same. C. less, but not zero.D. zero. E. not enough information given to decide Q22.1 +q+q Gaussian surface #1 Gaussian surface #2

2 Two point charges, +q (in red) and –q (in blue), are arranged as shown. Through which closed surface(s) is the net electric flux equal to zero? Q22.2 A. surface AB. surface B C. surface CD. surface D E. Both surfaces C and D

3 A conducting spherical shell with inner radius a and outer radius b has a positive point charge Q located at its center. The total charge on the shell is – 3Q, and it is insulated from its surroundings. In the region a < r < b, A. the electric field points radially outward. B. the electric field points radially inward. C. is zero. D. not enough information given to decide Q22.3

4 A solid spherical conductor has a spherical cavity in its interior. The cavity is not centered on the center of the conductor. If a positive charge is placed on the conductor, the electric field in the cavity A. points generally toward the outer surface of the conductor. B. points generally away from the outer surface of the conductor. C. is zero. D. not enough information given to decide Q22.4 Conductor Cavity

5 There is a negative surface charge density in a certain region on the surface of a solid conductor. Just beneath the surface of this region, the electric field A. points outward, toward the surface of the conductor. B. points inward, away from the surface of the conductor. C. points parallel to the surface. D. is zero. E. not enough information given to decide Q22.5

6 For which of the following charge distributions would Gauss’s law not be useful for calculating the electric field? A. a uniformly charged sphere of radius R B. a spherical shell of radius R with charge uniformly distributed over its surface C. a right circular cylinder of radius R and height h with charge uniformly distributed over its surface D. an infinitely long circular cylinder of radius R with charge uniformly distributed over its surface E. Gauss’s law would be useful for finding the electric field in all of these cases. Q22.6


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