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**Ideal Gas Law & Gas Stoichiometry**

PV = nRT R = Latm/molK = dm3kPa/molK Ideal Gas Law & Gas Stoichiometry 1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem. CLICK TO START

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QUESTION #1 How many grams of CO2 are produced from 75 L of CO at 35°C and 96.2 kPa? 2CO + O2 2CO2 ANSWER

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**V = 26.6 dm3/mol ANSWER #1 Find the new molar volume: n = 1 mol V = ?**

P = 96.2 kPa T = 35°C = 308 K R = dm3kPa/molK PV = nRT V = 26.6 dm3/mol BACK TO PROBLEM CONTINUE...

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**= 120 g CO2 ANSWER #1 (con’t) 2CO + O2 2CO2 75 L CO 1 mol CO 26.6 L**

44.01 g CO2 1 mol CO2 = 120 g CO2 BACK TO PROBLEM NEXT

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QUESTION #2 How many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25°C? ANSWER

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**n = 0.12 mol ANSWER #2 n = ? V = 2.5 L P = 1.2 atm T = 25°C = 298 K**

R = Latm/molK PV = nRT n = 0.12 mol BACK TO PROBLEM NEXT

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QUESTION #3 What volume will 56.0 grams of nitrogen (N2) occupy at 96.0 kPa and 21°C? ANSWER

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**V = 50.9 dm3 ANSWER #3 V = ? n = 56.0 g = 2.00 mol P = 96.0 kPa**

T = 21°C = 294 K R = dm3kPa/molK PV = nRT V = 50.9 dm3 BACK TO PROBLEM NEXT

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QUESTION #4 What volume of NH3 at STP is produced if 25.0 g of N2 is reacted with excess H2? N2 + 3H2 2NH3 ANSWER

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**= 40.0 L NH3 ANSWER #4 N2 + 3H2 NH3 25.0 g N2 1 mol N2 28.02 g 2 mol**

BACK TO PROBLEM NEXT

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QUESTION #5 What volume of hydrogen is produced from 25.0 g of water at 27°C and 1.16 atm? 2H2O 2H2 + O2 ANSWER

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**V = 21.2 L/mol ANSWER #5 Find the new molar volume: n = 1 mol V = ?**

P = 1.16 atm T = 27°C = 300. K R = Latm/molK PV = nRT V = 21.2 L/mol BACK TO PROBLEM CONTINUE...

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**H2 ANSWER #5 (con’t) 2H2O 2H2 + O2 25.0 g H2O 1 mol H2O 18.02 g**

BACK TO PROBLEM NEXT

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QUESTION #6 How many atmospheres of pressure will be exerted by 25 g of CO2 at 25°C and L? ANSWER

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**P = 28 atm ANSWER #6 P = ? n = 25 g = 0.57 mol T = 25°C = 298 K**

V = L R = Latm/molK PV = nRT P = 28 atm BACK TO PROBLEM NEXT

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QUESTION #7 How many grams of CaCO3 are required to produce 45.0 dm3 of CO2 at 25°C and 2.3 atm? CaCO3 + 2HCl CO2 + H2O + CaCl2 ANSWER

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**V = 11 L/mol ANSWER #7 Find the new molar volume: n = 1 mol V = ?**

P = 2.3 atm T = 25°C = 298 K R = Latm/molK PV = nRT V = 11 L/mol BACK TO PROBLEM CONTINUE...

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**= 410 g CaCO3 ANSWER #7 CaCO3 + 2HCl CO2 + H2O + CaCl2 45.0dm3 CO2**

1 mol CO2 11 dm3 1 mol CaCO3 CO2 g CaCO3 1 mol = 410 g CaCO3 BACK TO PROBLEM NEXT

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QUESTION #8 Find the number of grams of CO2 that exert a pressure of 785 torr at 32.5 L and 32°C. ANSWER

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**n = 1.34 mol 59.0 g CO2 ANSWER #8 n = ? P = 785 torr = 1.03 atm**

V = 32.5 L T = 32°C = 305 K R = Latm/molK PV = nRT n = 1.34 mol 59.0 g CO2 BACK TO PROBLEM NEXT

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Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.

Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.

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