Presentation on theme: "1 Control of Nitrogen Oxides 朱信 Hsin Chu Professor Dept. of Environmental Engineering National Cheng Kung University."— Presentation transcript:
1 Control of Nitrogen Oxides 朱信 Hsin Chu Professor Dept. of Environmental Engineering National Cheng Kung University
2 1.An Overview of the Nitrogen Oxides Problem Most of the world’s nitrogen is in the atmosphere as an inert gas. In crustal rocks it is the 34th most abundant element with an abundance of only ≈ 20 ppm.
3 Although nitrogen forms eight different oxides, our principal air pollution interest is in the two most common oxides, nitric oxide (NO) and nitrogen dioxide (NO 2 ). In addition, we are beginning to be concerned with nitrous oxide (N 2 O). It may be a significant contributor to global warming and to the possible destruction of the ozone layer.
4 1.1 Comparison with Sulfur Oxides Fig (next slide) shows part of how nitrogen moves in the environment, as a result of human activities.
6 Nitrogen oxides are often lumped with sulfur oxides as air pollution control problems because of the similarities between the two: (1)Nitrogen oxides and sulfur oxides react with water and oxygen in the atmosphere to form nitric sulfuric acids, respectively. These two acids are the principal contributors to acid rain.
7 (2)Both undergo atmospheric transformations leading to or contributing to the formation of PM 10 and PM 2.5 in urban areas. (3)Both are released into the atmosphere in large quantities. (4)Both are released to the atmosphere by large combustion sources, particularly coal combustion sources. Table 12.1 (next slide) shows the emission sources of NO X in the U.S. in 1997.
9 We see that vehicles contribute almost half of the total. Natural gas appears in this table, but not in the SO 2 table. The largest contributors to the “All other sources” are nontransportation internal combustion engines and residential combustion.
10 There are also major differences between nitrogen oxides and sulfur oxides: (1)Motor vehicles are the major emitter of nitrogen oxides, but a very minor source of sulfur oxides. (2)Sulfur oxides are formed from the sulfur contaminants in fuels or the unwanted sulfur in sulfide ores. Although some of nitrogen oxides emitted to the atmosphere are due to nitrogen contaminants in fuels, most are not.
11 Most of nitrogen oxides are formed by the reaction of atmospheric nitrogen with oxygen in high-temperature flames. (3)The formation of nitrogen oxides in flames can be greatly reduced by manipulating the time, temperature, and oxygen content of the flames. No such reductions are possible with sulfur oxides.
12 (4)The ultimate fate of sulfur oxides removed in pollution control or fuel-cleaning process is to be turned into CaSO 4 2H 2 O, which is an innocuous, low-solubility solid, and to be placed in landfills. There is no correspondingly cheap, innocuous, and insoluble salt of nitric acid, so landfilling is not a suitable fate for the nitrogen oxides.
13 The ultimate fate of nitrogen oxides that we wish to keep out of the atmosphere is to be converted to gaseous nitrogen and oxygen and be returned to the atmosphere. (5)It is relatively easy to remove SO 2 from combustion gases by dissolving SO 2 in water and reacting it with alkali. Collecting nitrogen oxides is not nearly as easy this way because NO, the principal nitrogen oxide present in combustion gas streams, has a very low solubility in water.
14 NO must undergo a two-step process to form an acid: NO O 2 ↔ NO 2 (1) 3 NO 2 +H 2 O → 2HNO 3 + NO(2) The first reaction is relatively slow. It is fast enough in the atmosphere to lead to the formation of acid precipitation in the several hours or days that the polluted air travels before encountering precipitation, but slow-enough that it does not remove significant quantities of NO in the few seconds that a contaminated gas spends in a wet limestone scrubber used for SO 2 control.
Reactions in the Atmosphere NO is a colorless gas that has some harmful effects on health, but these effects are substantially less than those of an equivalent amount of NO 2. NO 2, a brown gas, is a serious respiratory irritant.
16 Our principal concern with NO X is that nitrogen oxides contribute to the formation of ozone, O 3, which is a strong respiratory irritant and one of the principal constituents of urban summer eye- and nose-irritating smog. The overall reaction is: NO + HC + O 2 + sunlight → NO 2 + O 3
17 NO, emitted during the morning commuter rush, is oxidized in the atmosphere to NO 2 over a period of several hours. The NO 2 thus formed then reacts with HC to form O 3. The O 3 peak occurs after the NO 2 peak.
NO and NO 2 Equilibrium The most important reactions for producing NO and NO 2 in flames are: N 2 + O 2 ↔ 2NO(3) and Eq. (1). For any chemical reaction at equilibrium, the Gibbs free energy is at a minimum for the reaction’s temperature and pressure.
19 From that condition it follows that where∆G o =standard Gibbs free energy change K=equilibrium constant R=the universal constant T=absolute temperature (K or o R) Using the published G o values for the reactions in Eqs. (1) and (3) we may construct Table 12.2 (next slide).
21 Here we show K p, the equilibrium constant based on taking the standard states as perfect gases at 1 atm pressure, and expressing gas concentrations as partial pressures. Because the number of mols does not change in Eq. (3), its K p is dimensionless. However, in Eq. (1) the number of mols decreases by ½, so that K p has the dimension (atm) -0.5.
22 Example1 Calculate the equilibrium concentrations of NO and NO 2 for air that is held at 2000 K = 3140 o F long enough to reach equilibrium. Assume that the only reactions of interest are Eqs. (1) and (3).
23 Solution: The definitions of the two equilibrium constants are: Solving Eq. (3) for the equilibrium concentration of NO, we find
24 Substituting values, including the value of K 3 from Table 12.2, into this equation, we see Solving Eq. (6) for [NO 2 ], we find
25 Substituting values into this equation, we see Following the same procedure as in Example 1, we may make up Table 12.3 (next slide), which shows the calculated equilibrium concentrations of NO and NO 2 at various temperatures.
27 The starting gas that is 78% nitrogen, 4% oxygen is more representative of combustion gases in which most of the oxygen has been consumed by the combustion. The values from Table 12.3 are shown in Figs (next slide) and 12.3 (second slide).
30 From Table 12.3 and Figs and 12.3 we see: (1)If the atmosphere were at equilibrium (at a temperature near 300 K = 80 o F), it would have less than a part per billion of NO or NO 2. The concentrations of NO and NO 2 observed in cities in the world often exceed these equilibrium values, so that equilibrium alone is not a satisfactory guide to the presence of NO and NO 2 in the atmosphere.
31 (2)The equilibrium concentration of NO increases dramatically with increasing temperature. The rapid increase begins at about 2000~2500 o F ( K). (3)At low temperatures the equilibrium concentration of NO 2 is much higher than that of NO, whereas at high temperatures the reverse is true.
32 (4)We are likely to get to the temperatures where NO and NO 2 are formed from atmospheric N 2 and O 2 only in flames and in lightning strikes. Lightning strikes are a major global source of NO X, but combustion in our vehicles and factories is the main source of NO X in heavily populated areas.
Thermal, Prompt, and Fuel NO X Thermal nitrogen oxides, which are generally the most significant, are formed by the simple heating of oxygen and nitrogen, either in a flame or by some other external heating. Prompt refers to the nitrogen oxides that form very quickly as a result of the interaction of nitrogen and oxygen with some of the active hydrocarbon species derived from the fuel in the fuel-rich parts of flames.
34 Prompt NO X are not observed in flames of fuels with no carbon, e.g., H 2. Fuel nitrogen oxides is formed by conversion of some of the nitrogen originally present in the fuel to NO X.
35 Coal and some high-boiling petroleum fuels contain significant amounts of organic nitrogen; low-boiling petroleum fuels and natural gas contain practically none. Fig (next slide) shows estimates of the contribution of the thermal, fuel, and prompt mechanisms to the NO X emissions from coal combustion.
37 2. Thermal NO From Fig. 12.4, the thermal mechanism is the most important of the three ways of making NO at the highest temperatures. 2.1 The Zeldovich Kinetics of Thermal NO Formation Example 1 showed that a specific equilibrium concentration of NO could be reached at certain temperature. Here we inquire how rapidly the mixture approaches that equilibrium value.
38 The reactions shown in Eqs. (1) and (3) do not proceed as written in those equations. Rather, they proceed by means of intermediate steps involving highly energetic particles called free radicals. The free radicals most often involved in combustion reactions are O, N, OH, H, and hydrocarbons that have lost one or more hydrogens, e. g., CH 3 or CH 2.
39 These materials are very reactive and energetic and can exist in significant concentrations only at high temperatures. In principle they can be formed by equilibrium reactions like the following: N 2 ↔ 2N O 2 ↔ 2O H 2 O ↔ H + OH
40 However, the reactions are conventionally written with an M on both sides of the equation to indicate that another molecule, which is not chemically changed in the reaction, must collide with the N 2 or O 2 molecule to supply or remove energy for the reaction to occur, e.g., N 2 + M ↔ 2N +M
41 The concentration of M, which can be any other gas molecule (e.g., O 2 or N 2 or H 2 O) does not influence the equilibrium but does influence the rate of the reactions. The most widely quoted mechanism for the thermal NO formation reaction is that of Zeldovich. It assumes that O radicals attack N 2 molecules by O + N 2 ↔ NO + N and that N radicals can form NO by N + O 2 ↔ NO + O
42 If one assumes that the O radicals are in equilibrium with O 2, that the concentration of N radicals is not changing significantly with time, and that one term is small compared with the others, one can simplify the resulting kinetic equations to: where k f and k b are the forward and backward reaction rate constants.
43 Then one can observe that the equilibrium value of the NO concentration, [NO] e, is given by Eq. (5), and that the equilibrium constant is related to the two rate constants by One may show this by setting the rate of change of concentration in Eq. (7) to zero and comparing the result to Eq. (5).
44 Making this substitution and rearranging in Eq. (7), one finds: which may be integrated and rearranged (with an assumption of zero NO at time zero) to where
45 Example 2 Estimate the concentration of NO in a sample containing 78% N 2 and 4% O 2 that is hold for one second at 2000 K = 3140 o F, according to the Zeldovich thermal mechanism. Solution: From Table 12.3, we know the equilibrium concentration, [NO] e, is 3530 ppm.
46 Seinfeld suggests a value for k b of 4.1 exp ( /RT), for T in K, R in cal/mol/K, t in seconds, and concentrations in (mol/cm 3 ). At 1.0 atm and 2000 K, the molar density of any perfect gas is 6.1 mol/cm 3, so that
47 and Therefore,
48 This is a simplified version of the Zelodvich simplification of the kinetics of the thermal NO formation reaction. Using this simple relation, one may readily make up plot like Fig (next slide), which show the expected time-temperature relation for one specific starting gas composition.
50 More complex versions of the Zeldovich mechanism add another equation to the reaction list, N + OH ↔ NO + H with a resulting increase in mathematical complexity. The result cannot be reduced to any simple plot like Fig
51 The Zeldovich mechanism shown here makes reasonably accurate predictions of the rate of formation of NO from N 2 and O 2 in the highest temperatures observed in flames, and in other high-temperature situations. It predicts much lower NO concentrations than those observed in low-temperature flames.
52 Before we discuss the prompt and fuel NO mechanisms that predominate at low temperatures, we explore the temperature and times in flames, to help understand what kinds of flames produce significant thermal NO and what kinds do not.
Heating and Cooling Times How much thermal NO is formed in a flame as well as how much is then converted back to N 2 and O 2 as the gases cool is a strong function of how fast the gases heat and cool in the flames. Fig (next slide) shows some possible heating and cooling patterns for flames.
55 The square wave of Fig. 12.6a leads to the easiest calculations, as shown in Example 2. That example implicitly assumed that cooling after the flame is instantaneous, so that none of the NO formed in the flame is converted back to N 2 and O 2. Nothing in this world is truly instantaneous!
56 Example 3 Estimate the heating and cooling rates in the flame of an ordinary gas stove. The peak flame temperature is about 2400 o F and the combustion time about s. Solution: If we assume that the temperature-time pattern is the triangle wave shown in Fig. 12.6b, we can say that the heating and cooling rates should be about the same, and
57 The assumption of a symmetrical triangle temperature-time pattern is closer to reality than the square wave and still leads to relatively simple calculations. If we take the viewpoint of a person riding with a parcel of gas through the flame (The Lagrangian view), we can say that: where r is the rate of combustion and UA the product of the overall heat transfer coefficient and the applicable surface area.
58 For the rising part of T-t pattern on Fig. 12.6c, the observed behavior is that the rate starts slowly, increases as the the temperature rises, and then slows to a stop as the last of the fuel is consumed. After the peak is reached, the decline must be steeper than the rise was because the rise was proportional to the difference between the two terms on the right of Eq. (11) but the decline is proportional to the cooling term alone.
59 Example 4 Repeat Example 2 for the strong simplifying assumptions that (1)the gas heats from 293 to 2000 K in 0.5 s with a linear temperature increase, then cools from 2000 to 293 K in 0.5 s with a linear temperature decrease (Fig. 12.6b) and (2)the initial NO concentration is zero.
60 Solution: Here we use the simple zeldovich mechanism and Eq. (8), which we know to be only approximate.
61 If we consider the time interval 0.0 ≤ t ≤ 0.01 s, we see that the initial temperature is 293 K and the final temperature is = 327 K. For this time interval the average temperature is 310 K. Using that value, we may estimate the equilibrium constant as
62 For simplicity we will proceed as if the oxygen content were the 4% in that example, independent of time. Substituting this value of K p in Eq. (5) and solving, we find At this temperature and one atmosphere pressure, the molar density is (4.46 ) (273 / 310) = 3.93 mol/cm 3, so that in concentration units [NO] e = 4 (3.93 ) = 1.6 mol/cm 3.
63 At this temperature, using the equation from Example 2, we have
64 Multiplying this by ∆t = 0.01 s, we conclude that during the first 0.01 s the concentration of NO went from zero to 2 mol/cm 3. This value is negligible, but we now proceed for the remaining 99 time steps, each of the same size, using a spread-sheet (e.g., Excel), and find the results shown in Fig (next slide). The final calculated NO concentration is 20 ppm. #
66 From Fig. 12.7, we see that the calculated equilibrium concentration goes from 5.5 ppm (≈ 0) to the 3530 ppm in Table 12.3, as the temperature rises, and then back to zero as the temperature falls. The reaction rate is practically zero, and hence the amount of NO actually formed is practically zero until about 0.44 s (T ≈ 1780 K), after which the rate of NO formation becomes significant.
67 By the time the Equilibrium and calculated curves cross, the temperature is low enough that the reaction rate is practically zero, so that the NO concentration remains practically constant during the further cooling. One speaks of the concentration being “frozen” at its higher temperature value.
68 3. Prompt NO During the first part of combustion, the carbon- bearing radicals from the fuel react with nitrogen by: CH + N 2 ↔ HCN + N and several similar reactions involving the CH 2 and C radicals. The N thus produced attacks O 2 to increase the amount of NO formed; and the HCN partly reacts with O 2, producing NO, partly with NO, producing N 2.
69 There does not appear to be any simple theoretical treatment like the Zeldovich mechanism. But it appears certain that the amounts of NO found in low-temperature flames, which are much larger than one would predict from the Zeldovich thermal mechanism, are actually mostly prompt NO.
70 4. Fuel NO Some coals as well as the hydrocarbons derived from oil shale can contain up to 2% N. Most of the fuel nitrogen is converted in the flame to HCN, which then converts to NH or NH 2. The NH and NH 2 can react with oxygen to produce NO +H 2 O, or they can react with NO to produce N 2 and H 2 O.
71 Thus, the fraction of the fuel nitrogen that leaves the flame as NO is dependent on the NO/O 2 ratio in the flame zone. Keeping the oxygen content of the gases in the high temperature part of the flame low significantly lowers the fraction of the fuel nitrogen converted to NO.
72 The fraction of the fuel nitrogen that appears as NO X in the exhaust gas is estimated to be typically 20% to 50%, depending on furnace conditions and, to some extent, the chemical nature of the N in the fuel. Fig (next slide) shows one schematic view of the interactions of the there mechanisms of NO formation.
74 5.Noncombustion Sources of Nitrogen Oxides The production and utilization of nitric acid lead to emissions of NO and NO 2, as do some other industrial and agricultural processes, e.g., silage production. Table 12.1 shows that such sources account for about 3% of NO X emissions in the U.S.
75 6. Control of Nitrogen Oxide Emissions There are two possible approaches to controlling NO X in combustion gases: (1)Modify the combustion processes to prevent the formation of NO X. (2)Treat the combustion gas chemically, after the flame, to convert the NO X to N 2.
76 For smaller industrial sources, like nitric acid plants, other control techniques are used, e.g., scrubbing with solutions of NaOH and KMnO 4. The strongly oxidizing KMnO 4 quickly converts NO to NO 2, allowing it to be captured by the alkaline NaOH. This process requires an expensive electrochemical regeneration of the KMnO 4 ; it is not suitable for large-scale combustion sources.
77 6.1Nitrogen Oxide Control by Combustion Modification The formation of thermal NO is increased by increasing any of the following three variables: peak temperature, time at high temperature, oxygen content at the high temperature. Two-stage combustion or reburning as shown in Fig. 12.6d is a good way for combustion modification.
78 In the first stage, the maximum temperature is lowered because not all the fuel is burned, and the maximum temperature is reached when all the oxygen has been used up, so that there is not enough oxygen to form NO. In the second stage, enough of the heat released in the first stage has been removed that the maximum temperature reached-in the presence of excess oxygen-is low enough that the formation of NO is small.
79 The advantage of this approach is that it is cheap. The disadvantages are that it requires a larger fire box for the same combustion rate and that it is difficult to get complete burning of the fuel in the second stage. Fig (next slide) shows an alternative approach to designing a low-NO X burner.
81 In normal operation the incoming gas is thoroughly mixed with air and recycled combustion products (Flue Gas Recirculation, FGR), with about 15% excess air. This thorough mixing, together with excess air, prevents there ever being any fuel-rich part of the flame, in which prompt NO can form. Fig (next slide) show some test results for this burner, burning natural gas with 15% excess air and varing degrees of air preheat and FGR.
83 The dilution with recycled flue gas simply lowers the temperature at every part of the flame. As the figure shows, it is possible to reduce the NO X to 10 ppm if one is willing to bear the extra cost of pumping 20 to 40% of the flue gas back into the burner. However, compared to other methods of achieving 10 ppm–i.e., catalytic treatment of the flue gas-the cost of FGR is very reasonable.
84 This burner is a moderately low-NO X burner when it is burning fuel oil. Ultra-low NO X levels are not achieved since most fuel oils contain bound nitrogen that is oxidized in the flames to NO X. Also, because there will be a fuel-rich region at the surface of evaporating oil droplets, there will be prompt NO formation.
85 6.2Nitrogen Oxide Control by Postflame Treatment Most post flame treatment processes add a reducing agent to the combustion gas stream to take oxygen away from NO. Almost any gaseous reducing agent can be used, e.g., CO, CH 4, other HCs, NH 3, various derivatives of NH 3.
86 In modern auto engines the reaction is For power plants and other large furnaces a variety of reducing agents are used, of which the most popular is ammonia. The desired reaction is: 6 NO + 4 NH 3 → 5 N H 2 O (12)
87 However, there is always some oxygen present, which can lead to reactions like: 4 NO + 4 NH 3 + O 2 → 4 N H 2 O (13) is which one ammonia molecule is required for each molecule of NO. The NO 2 is reduced by: 2 NO NH 3 + O 2 → 3 N H 2 O (14)
88 Reactions (12) – (14) can be carried out over a variety of catalysts, of which zeolites and supported TiO 2 are the most popular, at about 700 o F (370 o C), or simply in the gas stream in the part of the furnace where the temperature is between 1600 o and 1800 o F (870 o – 980 o C). Below 1600 o F the reaction rate is too slow. Above 1800 o F the dominant reaction becomes NH 3 + O 2 → NO + 3/2 H 2 O which increases rather than decreases the NO content of the gas.
89 The catalytic processes are called selective Catalytic Reduction, or SCR. The high-temperature ones, without catalysts, are called Selective Noncatalytic Reduction, SNCR. There are experimental processes under development that adsorb both SO 2 and NO onto an activated carbon adsorbent. They are then stripped off one at a time and treated, making S and N 2 the final products.