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Pre-Calculus. Objectives : 1. Identify the relationship of trig functions and positive and negative angles 2. Identify the Pythagorean trig relationships.

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Presentation on theme: "Pre-Calculus. Objectives : 1. Identify the relationship of trig functions and positive and negative angles 2. Identify the Pythagorean trig relationships."— Presentation transcript:

1 Pre-Calculus

2 Objectives : 1. Identify the relationship of trig functions and positive and negative angles 2. Identify the Pythagorean trig relationships 3. Identify the cofunction trig relationships 4. Apply various trig relationships to simplify expressions. Vocabulary : sine, cosine, tangent, cosecant, secant, cotangent, cofunction

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4  Simplify the following Expressions

5  Let’s take a look at the unit circle.  Using the Pythagorean Theorem, how can you relate all three sides of the triangle?  sin 2 θ + cos 2 θ = 1  This is one of the Pythagorean Trig Relationships

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7  Starting with sin 2 θ + cos 2 θ = 1, how can you manipulate it to get other following Pythagorean Trig Relationships?  1 + tan 2 θ = sec 2 θ Divide both sides by cos 2 θ  1 + cot 2 θ = csc 2 θ Divide both sides by sin 2 θ  These are the final 2 of the 3 Pythagorean Trig Relationships

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9  Sine & Cosine, Tangent & Cotangent, Secant & Cosecant are all Cofunctions.  Trig Cofunctions have the following relationship  WHY?

10  Simplify the following  tan (90° – A) =  Cos (π/2 – x) =

11  Let’s take a look at a positive and negative angle on the unit circle

12  Let’s take a look at sin θ. What does this equal according to our picture?  What about sin –θ. What does this equal according to our picture?  What can we say about the relationship between sin θ & sin –θ?

13  We just proved that sin (-θ) = - sin θ  What do you think the relationship between cos (- θ) and cos θ is?  cos (- θ) = cos θ  What about the relationship between tan (- θ) and tan θ?  tan (- θ) = - tan θ

14  Let’s look at csc (- θ) and csc θ. What is the relationship?  csc (- θ) = - csc θ  What about the relationship between sec (- θ) and sec θ?  sec (- θ) = sec θ  What about the relationship between cot (- θ) and cot θ?  cot (- θ) = - cot θ Part 3: Trig Relationships With Negative and Positive Angles

15  Write the equivalent trig function with a positive angle  Sin (-π/2)  Cos (-π/3)  Cot (-3π/4)

16  Start with the more complicated side  Try substituting basic identities (changing all functions to be in terms of sine and cosine may make things easier)  Try algebra: factor, multiply, add, simplify, split up fractions  If you ’ re really stuck make sure to: Change everything on both sides to sine and cosine.  Work with only one side at a time!

17  Every identity is different  Keep trying different approaches  The more you practice, the easier it will be to figure out efficient techniques  If a solution eludes you at first, sleep on it! Try again the next day. Don ’ t give up!  You will succeed!

18  There are 4 different categories of trig relationships which each have different key components to look for  Reciprocal Relationships Most commonly used in some type of format similar to cot y · sin y manipulating a fraction with trig functions  Usually the functions aren’t squared when they are in this format  Negative/Positive Angle Relationships Similar to the example problems previously in this powerpoint tan (-45°)

19  There are 4 different categories of trig relationships which each have different key components to look for  Cofunction Relationships Similar to the example problems previously in this powerpoint cos (90° – A)  Pythagorean Relationships (MOST COMMON/CHALLENGING!) Includes exponents to the second degree Includes expanding two binomials Addition and subtraction of fractions May need to factor out a trig function before simplifying Or some type of variation of the previous

20  Though most of the problems are separated into their respective categories, you may find yourself having to combine multiple relationships to fully simplify an expression.  Maybe you’ll start with Pythagorean relationships, then to fully simplify you may use Reciprocal relationships.  In most cases, fully simplifying an expression will leave the expression with only one term

21  Textbook pg 321: #1, 5, 13, 21, 31


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