Download presentation

Presentation is loading. Please wait.

Published byDamaris Lung Modified about 1 year ago

1
Short Version : 5. Newton's Laws Applications

2
Example 5.3. Restraining a Ski Racer A starting gate acts horizontally to restrain a 60 kg ski racer on a frictionless 30 slope. What horizontal force does the gate apply to the skier? since x y FgFg n FhFh x : y :

3
Alternative Approach x y FgFg n FhFh Net force along slope (x-direction) :

4
5.2. Multiple Objects Example 5.4. Rescuing a Climber A 70 kg climber dangles over the edge of a frictionless ice cliff. He’s roped to a 940 kg rock 51 m from the edge. (a)What’s his acceleration? (b)How much time does he have before the rock goes over the edge? Neglect mass of the rope.

5
Tension T = 1N throughout

6
5.3. Circular Motion 2 nd law: Uniform circular motion centripetal

7
Example 5.6. Engineering a Road At what angle should a road with 200 m curve radius be banked for travel at 90 km/h (25 m/s)? x y n FgFg a x :y :

8
Example 5.7. Looping the Loop Radius at top is 6.3 m. What’s the minimum speed for a roller-coaster car to stay on track there? Minimum speed n = 0

9
Conceptual Example 5.1. Bad Hair Day What’s wrong with this cartoon showing riders of a loop-the-loop roller coaster? From Eg. 5.7: n m g = m a = m v 2 / r ( a g ) Consider hair as mass point connected to head by massless string. Then T m g = m a where T is tension on string. Thus,T = m ( g a ) 0. ( downward ) This means hair points upward ( opposite to that shown in cartoon).

10
Frictional Forces Pushing a trunk: 1.Nothing happens unless force is great enough. 2.Force can be reduced once trunk is going. Static friction s = coefficient of static friction Kinetic friction k = coefficient of kinetic friction k : 1.5 (rough) Rubber on dry concrete : k = 0.8, s = 1.0 Waxed ski on dry snow: k = 0.04 Body-joint fluid: k = 0.003

11
Example 5.11. Dragging a Trunk Mass of trunk is m. Rope is massless. Kinetic friction coefficient is k. What rope tension is required to move trunk at constant speed? x y T FgFg fsfs n x : y :

12
Rolling wheel:

13
Skidding wheel 滑動的輪子 : kinetic friction 動摩擦 k 0.8 Rolling wheel 滾動的輪子 : static friction 靜摩擦 s 1 Rolling friction 滾動摩擦 r 0.01

14
Dynamics of Wheels F fsfs frfr

15
Example 5.8. Stopping a Car k & s of a tire on dry road are 0.61 & 0.89, respectively. If the car is travelling at 90 km/h (25 m/s), (a) determine the minimum stopping distance. (b) the stopping distance with the wheels fully locked (car skidding). (a) = s : (b) = k :

16
Steering Bicycle turning to the left. Car turning to the left. More details

17
Example 5.9. Steering A level road makes a 90 turn with radius 73 m. What’s the maximum speed for a car to negotiate this turn when the road is (a) dry ( s = 0.88 ). (b) covered with snow ( s = 0.21 ). (a) (b)

18
5.5. Drag Forces Terminal speed: max speed of free falling object in fluid. Drag force: frictional force on moving objects in fluid. Depends on fluid density, object’s cross section area, & speed. Parachute: v T ~ 5 m/s. Ping-pong ball: v T ~ 10 m/s. Golf ball: v T ~ 50 m/s. Sky-diver varies falling speed by changing his cross-section. Drag & Projectile Motion

19
Simple Machines

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google