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Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010)

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Presentation on theme: "Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010)"— Presentation transcript:

1 Total Mixed Ration (TMR) for Dairy Cows Dr. István HULLÁR associate professor (2010)

2 TMR - Mixture of forages, roughages, grains, extr. meals, supplements, etc., - fed according to the total daily requirements of production groups.

3 Control of the TMR TASK Check the following TMR whether it is sufficient for the following dairy cow. STEPS of Solution 1. Data Sheet - TMR, - data regarding the dairy cow; 2. Nutrient Requirements 3. Nutrient Content of the TMR 4. Evaluation (requirements vs. TMR), Corrections.

4 Control of the TMR 1. Data Sheet - TMR meadow hay (average): 5.0 kg, corn silage (predough stage):15.5 kg sunflower meal extr. (average): 2.6 kg, CCM (Corn Cob Mix): 8.4 kg; - Data regarding the dairy cow W: 580 kg, milk production: 25 kg/day, milk protein: 3.2%, milk fat: 3.5%, 2nd lactation.

5 Calculation of the Requirements 2. Nutrient Requirements 2.1. DMI: 2-3% of the W (580 kg) = kg/day, 2.2. CF: 18-23% of the DM content of TMR.

6 Calculation of the Requirements 2. Nutrient Requirements 2.3. Maintenance Energy reqirement NE l = *W 0.75 = * = * = MJ/day; Protein requirement MP = 3.41*W 0.75 = 3.41* = 403 g/day; Ca requirement: 44*0.001*W = g/day; P requirement: 34*0.001*W = g/day.

7 Calculation of the Requirements 2. Nutrient Requirements 2.3. Maintenance Correction 1st lactation: +20% of the total maintenance req.; 2nd lactation: +10% of the total maintenance req. (see later); 2.4. Milk Production Energy reqirement NE l = *milk fat% = *3.5 = 2.88 MJ/kg milk; 25 kg milk: 25*2.88 = MJ/day.

8 Calculation of the Requirements 2. Nutrient Requirements 2.4. Milk Production Protein requirement MP = milk protein (g)/0.65 = 32/0.65 = 49 g/kg milk; 25 kg milk: 25*49 = 1225 g/day Ca requirement: 2.8 g/kg milk; 25 kg milk = 25*2.8 = g/day; P requirement: 1.7 g/kg milk; 25 kg milk: 25*1.7 = g/day.

9 2. Requirements Sum of the Requirements DMCFNE l MPCaP (kg)(g)(MJ) (g)(g) (g) Maintenance % kg milk TOTAL % of DM

10 3. Nutrient Content of the TMR DMCFNE l MPEMPNCaP Feeds(kg)(g)(MJ) (g) (g) (g)(g) 5.0 kg hay kg silage kg sunfl kg CCM TOTAL Which MP value is valid? 

11 4. Evaluation, Corrections RequirementsTMREvaluation DM, kg O.K. CF, g 18-23% of the DM 3.188/17.39*100 = 18.33% O.K. Other Nutrients The tolerable difference between the requirement and the TMR: the rquirement of 2 kg milk (  ).

12 4. Evaluation, Corrections NE l (MJ) Requirement: TMR: Difference: Tolerable level:2.88*2 =  5.76 Evaluation:O.K. MP (g) Requirement:1668 TMR:1583 Difference:- 85 Tolerable level:49*2 =  98 Evaluation:O.K.

13 4. Evaluation, Corrections Ca (g) Requirement:98.07 TMR:49.22 Difference: Tolerable level:2.8*2 =  5.6 Evaluation:insufficient P (g) Requirement:64.19 TMR:56.43 Difference: Tolerable level:1.7*2 =  3.4 Evaluation: insufficient.

14 4. Evaluation, Corrections Corrections Types of Ca and P supplements NameCa (g)P (g) Limestone380 - AP AP Phylafor AP-IV 17170

15 4. Evaluation, Corrections Corrections 1. Correction of the P deficiency by AP-IV: 1000 g AP-IV contains170 g P x g AP-IV contains 7.76 g P x = 7.76/170*1000 = g AP-IV 2. Calculation of the amount of Ca given by AP-IV: 1000 g AP-IV contains17 g Ca g AP-IV contains x g Ca x = 45.65/1000*17 = 0.78 g Ca.

16 4. Evaluation, Corrections Corrections 3. Calculation of the Ca deficiency remained: – 0.78 = g; 4. Correction of the Ca deficiency by limestone: 1000 g limestone contains380 g Ca x g limestone contains g Ca x = 48.07/380*1000 = g limestone.

17 4. Evaluation, Corrections Final Evaluation - DM, CF, NE l, and MP content of the TMR are O.K.; - but g AP-IV and g limestone supplementations are required.


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