Download presentation

Presentation is loading. Please wait.

Published byAlexus Brame Modified over 3 years ago

1
Output - Derived Variables Derived Variables are quantities evaluated from the primitive (or solved) variables by PHOENICS. It means, PHOENICS first solve U1, V1, W1, P1, TEM1 etc. After achieving convergence it evaluates the Derived Variables. Usually they are: Heat Transfer Coefficients Friction Factors Shear Stresses at walls Wall Distances, etc

2
Placing the Skin friction coefficient, Stanton Number, Shear stress (actually friction velocity squared, equivalent to shear stress divided by density), Yplus (non-dimensional distance to the wall) and heat transfer coefficient (in W/m 2 /K) into 3-D storage allows them to be plotted in the Viewer or PHOTON, as well as appearing in the RESULT file. The major difficult to establish these variables in a general purpose code lays on the determination of a reference velocity and temperature. Output - Derived Variables – Usual Definitions

3
Output - Derived Variables PHOENICS DEFINITIONS The phoenics uses as a reference velocity the wall velocity, i.e., the velocity evaluated at the volume adjacent to the wall, here defined as U w wall

4
Output - Derived Variables Note that the friction and heat-transfer coefficients are only calculated for turbulent flow. To make them appear for laminar cases, the turbulent viscosity should be set to a very small value – say 1.0E-10. The Stanton Number must be stored for the heat-transfer coefficients to be calculated.

5
Output - Derived Variables The friction force components SHRX, SHRY and SHRZ are used in the force- integration routines to add the friction force to the pressure force acting on each object. If they are not stored, the integrated force will only contain the pressure component. The Total or Stagnation Pressure (PTOT) is only calculated if the Mach Number is stored. If the Reference Pressure (Main Menu – Properties) is set to zero, the total pressure may go below zero, leading to an error-stop.

6
Workshop #1 Friction factor and heat transfer coefficients for a laminar flow inside a circular section pipe. Pipe radius = 0.005 m, Pipe length = 1 m, = 1rad. Inlet velocity and temperature 1.0m/s and 100 o C (Re = 1000) Wall velocity and temperature = 0 m/s and 0 o C Outlet at atmospheric pressure Grid size: ny = 20 & nz = 60 (Z power 2.0) Model : activate energy (static temp) turbulent with constant T of 1E-10 Set Properties Manually to: RHO = 1; ENUL = 10 -5 ; CP = 1000 & k = 0.02 Re D = 1000 e Pr = 0.5 ( H < T )

7
Workshop #1 Numerics: ITER = 200; automatic relax OFF, use: P1 = 1; V1=0.01; W1=0.01 & TEM1 = 1E+09 OUTPUT – activate storage for: SKIN, SHEAR, HTCO, STAN If every thing went wrong: Upload Q1Upload Q1

8
Check W profiles Parabolic velocity profile, max velocity is twice the mean velocity! (IZ = 58) Axial centerline velocity achieves 2.0 m/s indicating the fully developed flow.

9
Check T profiles Axial temperature distribution at the pipe centerline (Y=1) and at the pipe wall (Y=20)

10
Skin friction Shear stress evaluation at the fully developed region: Please, compare to the analytical solution, C f = 16/Re D

11
HTCO & Heat Transferred Temperature diff. at the wall: T w – T 1 T w = 0 & T 1 = TEM1 TEM1

12
(1) (2) (3) (4) (5) TOTAL HEAT TRANSFER [W] The area under the curve is approximated by three triangles and rectangles. Summing the areas one will find Q ~ 1,12 W. Compare this result with the phoenics evaluation of the total heat transfer for object plate (1.19 W).

13
Forces & Momentum in Objetcs

14
One of the output options is to calculate the forces and moments on blockage objects, and print them to the result file. To activate this feature, open the Main Menu, then click on 'Output'. Turn 'Output of forces and moments' to ON. By default, only the pressure forces are integrated over the surface of each body. To add in the friction components, we must store the Friction Forces. Click on 'Derived variables' and turn ON the 3D storage of the X, Y and Z friction force components.

15
Test case: Drag on a 2D cylinder with square cross section Available q1 i.Fluid: air (0) ii.Flow model: Laminar & Steady State i.Relax: insert the reference vel and length ii.Z length = 0.1 m

16
Activating the object force evaluator function go to OUTPUT box

17
The force on the selected objects are assessed from the RESULT. Else one can go to VR Viewer, select an object, say B3, right click and select 'Show results'. The following dialog will appear: Unfortunately in my 2010 64 bits this function did not work. The forces were assessed through the result file only. The results are not accurate, the grid is very poor.

18
Streamlines for a Re = 6 regime; steady state flow

19
Transient Case Case: vortex shedding of a cylinder in cross flow. The upstream steady flow becomes a periodic flow downstream due to the flow instabilities developed at the cylinder boundary layer. The vortices detach from the cylinder surface periodically inducing longitudinal and transversal forces. This case uses the storage of surface forces for transient case.

20
Transient Case: problem set up Properties: = 1 kg/m 3, = 0.006 m 2 /s Grid: Time = 25s, time steps 1600, LX = 10m, LY = 6m, LZ = 1m, Cylinder = 0.6m, NX = 67, NY = 50, NZ = 1 Numerics: Iter = 20, Relax (manual) P1 = 1.0, U1 = V1 = 5, difference scheme QUICK. U = 3 m/s Available q1 for download Note about q1: a.it uses a coarse grid, better results come with 165x100 volumes grid.it uses a coarse grid, better results come with 165x100 volumes grid. b. it is included inform lines to evaluate the flow vorticity. it is included inform lines to evaluate the flow vorticity.

21
Transient Case: force history Look at d_priv1 phoenics folder for ‘forces-t.csv’:

22
Reference: cylinder drag coefficient for Re = 300, Cd 1,3

23
Cylinder: drag and lift Extracts from ‘forces-t.csv’ F x force in N parallel to the main flow direction F y force in N transversal to the main flow direction F x is a drag force and has a frequency half of the F y F y is periodic, the net F y is null. C D and C L are the drag and lift coefficients C D is close to the experimental data. Only the absolute value of C L is shown.

Similar presentations

Presentation is loading. Please wait....

OK

Experiment #5 Momentum Deficit Behind a Cylinder

Experiment #5 Momentum Deficit Behind a Cylinder

© 2018 SlidePlayer.com Inc.

All rights reserved.

To ensure the functioning of the site, we use **cookies**. We share information about your activities on the site with our partners and Google partners: social networks and companies engaged in advertising and web analytics. For more information, see the Privacy Policy and Google Privacy & Terms.
Your consent to our cookies if you continue to use this website.

Ads by Google

Powerpoint presentations free download ppt on pollution Jit ppt on manufacturing overhead Ppt on shell scripting in sql Ppt on london stock exchange Ppt on economic development Ppt on catenation of carbon Ppt on political parties and electoral process definition Hrm ppt on recruitment companies Ppt on condition based maintenance conference Alternative fuels ppt on automobiles