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**Section 3.6 Quadratic Equations Objectives**

1. Find the vertex and standard equation of a parabola 2. Sketch the graph of a parabola 3. Solve applied problem involving maximum or minimum Best way to view this presentation is thru power point XP

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**Definition of a quadratic Function: A function f is a quadratic function if**

f(x) = ax2 + bx + c Where a, b and c are constants with a ≠ 0 Example 1. Sketch the graph of f if f( x ) = x2 Note: b = c = 0 Solution: Table of variation (x,y) y x (-2, -2) -2 (-1, - ½ ) - ½ -1 (0, 0 ) (1, -1/2 ) -1/2 1 (2, - 2 ) - 2 2

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Note: Only b = 0 Solution: It is enough to shift the previous graph by 4 units upward as we can see below

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**Expressing a Quadratic Equation as f(x) = a ( x – h )2 + k**

Method By completing the square of the right hand side of the quadratic equation and it will be explained in class. Method 2. ( Zalzali’s Method ) Step 1. Let h = Step 2. Let k = Step 3. Insert the values of h and k in f ( x ) = a( x – h )2 + k

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**Then f(x) = 3 ( x + 4 )2 +2 Class Work 1**

Example 3. Write the following quadratic function in the standard form f(x) = a ( x –h )2 + k Solution: Then f(x) = 3 ( x + 4 )2 +2 Class Work 1 Write the following quadratic function f(x) = -x2 -2x +8 in the standard form f(x) = a ( x –h )2 + k Answer: f(x) = - ( x + 1 )2 +9

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**Standard Equation of a parabola with vertical Axis**

The graph of the equation f(x) = a ( x –h )2 + k For a ≠ 0 is a parabola with vertex V(h, k ) and it has a vertical axis x = h. The parabola opens upward if a > and The parabola opens downward if a < 0. Notes about Vertex V ( h , k ) Note 1. If a < 0, then the vertex V ( h, k ) is a maximum point of the parabola Note 2. If a > 0, then the vertex V ( h, k ) is a minimum point of the parabola

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**Graphing Parabolas Solution: Strategy: 1. Find the vertex V ( h, k )**

2. Identify if the vertex is maximum or minimum 3. Find x and y intercepts if they exist 4. Plot the vertex and the intercepts 5. Plot the vertical axis ( it is also called axis of symmetry of a parabola ) 6. Connect the points of the parabola and extend the graph Example 4: Graph the parabola Solution: 1. Vertex V ( -1, 9) Check class practice f(x) = - x2 – 2x + 9 2. a = -1 < 0 ( Parabola is open downward ) and has a maximum at the vertex 3. x-intercept(s): Set y = 0, then x =-4 and 2 Therefore, points are ( -4, 0 ) and ( 2, 0 ) y-intercept : Set x = 0 , then y = 8. Point ( 0, 8 ) x = -1

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Class Work 2 Graph the parabola

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Word Problem Height of a projectile: An object is projected vertically upward from the top of a building with an initial velocity of 144 ft / sec. Its distance s( t ) = - 16t t + 100 (a) Find its maximum distance above the ground (b) Find the height of the building. Solution: Height =s(0)

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**Do all homework problems in the syllabus**

Homework of section 3.6 Do all homework problems in the syllabus

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Solving Quadratic Equations by Graphing Quadratic Equation y = ax 2 + bx + c ax 2 is the quadratic term. bx is the linear term. c is the constant term.

Solving Quadratic Equations by Graphing Quadratic Equation y = ax 2 + bx + c ax 2 is the quadratic term. bx is the linear term. c is the constant term.

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