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Electrical ENgg. Department Simulation of elevator using Simulink.

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Presentation on theme: "Electrical ENgg. Department Simulation of elevator using Simulink."— Presentation transcript:

1 Electrical ENgg. Department Simulation of elevator using Simulink

2 Any drive system consists of: - Power Source - Electronic Converter - Motor - Mechanical Load - Controller - Feedback loops

3 The scheme of elevator structure is shown in Fig. A drive belt is looped over a drive pulley with the ends anchored to the top of the elevator shaft. The electric drive is rigidly attached to the drive pulley with the use of gearing. The car and counterweight, which ride on pulleys, provide belt tension ensuring the toothed belt and drive pulley do not slip. The elevator car and counter-weight are of different weight. GOAL: IS TO HAVE CONSTANT SPEED AND RESPONSE TIME REGARDLESS OF THE LOAD TORQUE

4 Mathematical Model of Elevator Electric Drive.  equations that control operation of the elevator can be divided two systems :  - Mechanical system.  - Electrical System.

5 Mathematical Model of Mechanical System’s

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11 Mathematical Model of Electrical System’s :  Why to choose series motor ?  1- Highest starting torque.   2 - Draws less current and power from the  source compared to a shunt or compound motor.

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13  Closed loop control is when the firing angle of the power processing unit is varied automatically by a controller to achieve a reference speed or torque  This requires the use of sensors to feed back the actual motor speed and torque to be compared with the reference values.

14  Actual motor speed measured using the tachogenerator (Tach) is filtered to produce feedback signal  The reference speed is compared to motor obtain a speed error signal  The speed (PI) controller processes the speed error and produces the torque command Te Ia is compared to actual current Ia to obtain a current error signal  The current (PI) controller processes the error to alter the control signal vc  vc modifies the firing angle to be sent to the converter to obtained the motor armature voltage for the desired motor operation speed

15 We Built The Drive System with: Dc Series Motor ( The parameters of Motor were taken from the library ) Max passenger weight = 600 Kg Cabinet weight = 100 Kg Counter weight = 400 Kg Pully Diameter = 30 cm Vf consat = 300 V Flux assumed to be =.2

16 Matlab Blocks:

17 UpWard Case 1 : Max : 600 Kg passenger weight ( Total Of 700 Kg with Cabinet )

18 UpWard  Case 2 : 300 Kg Passenger weight ( total Of 400 Kg = Same as Counter weight )

19 UpWard  Case 3 : 0 Kg passenger weigh (Total of 100 Kg less than Counter weight )

20 Downward  Case 4 : Max : 600 Kg passenger weight ( Total Of 700 Kg with Cabinet )

21 Downward  Case 5 : 300 Kg Passenger weight ( total Of 400 Kg = Same as Counter weigh )

22 Downward  Case 6 : 0 Kg Passenger weight ( total Of 100 Kg = less than Counter weight

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