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Statistics Class10 2/29/2012

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Review When playing roulette at the Bellagio casino in Las Vegas, a gambler is trying to decide whether to bet $5 on the number 13 or to bet $5 that the outcome is any one of these five possibilities: 0 or 00 or 1 or 2 or 3. From Example 8, we know that the expected value of the $5 bet for a single number is -26₵. For the $5 bet that the outcome is 0 or 00 or 1 or 2 or 3, there is a probability of 5/38 of making a net profit of $30 and a 33/38 probability of losing $5. a.Find the expected value for the $5 bet that the outcome is 0 or 00 or 1 or 2 or 3. b.Which bet is better: A $5 bet on the number 13 or a $5 bet that the outcome is 0 or 00 or 1 or 2 or 3? Why?

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Binomial Probability Distributions A binomial probability distribution results from a procedure that meets all the following requirements.

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Binomial Probability Distributions A binomial probability distribution results from a procedure that meets all the following requirements. 1.The procedure has a fixed number of trials.

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Binomial Probability Distributions A binomial probability distribution results from a procedure that meets all the following requirements. 1.The procedure has a fixed number of trials. 2.The trials must be independent. (The outcome of any individual trial doesn’t affect the probabilities in the other trials.)

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Binomial Probability Distributions A binomial probability distribution results from a procedure that meets all the following requirements. 1.The procedure has a fixed number of trials. 2.The trials must be independent. (The outcome of any individual trial doesn’t affect the probabilities in the other trials.) 3.Each trial must have all outcomes classified into two categories (commonly referred to as success and failure).

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Binomial Probability Distributions A binomial probability distribution results from a procedure that meets all the following requirements. 1.The procedure has a fixed number of trials. 2.The trials must be independent. (The outcome of any individual trial doesn’t affect the probabilities in the other trials.) 3.Each trial must have all outcomes classified into two categories (commonly referred to as success and failure). 4.The probability of a success remains the same in all trials.

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Binomial Probability Distributions Note on Independence Often when selecting a sample we do so without replacement. This means that our events are dependent, and violate rule 2 of the binomial probability distribution. However we can use the 5% guideline for cumbersome calculations, and treat dependent events independent as long as the sample size is no more than 5% of the population size.

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes.

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure ndenotes the fixed number of trials

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure ndenotes the fixed number of trials xdenotes a specific number of successes in n trials

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure ndenotes the fixed number of trials xdenotes a specific number of successes in n trials pdenotes the probability of success in one of the n trials

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure ndenotes the fixed number of trials xdenotes a specific number of successes in n trials pdenotes the probability of success in one of the n trials qdenotes the probability of failure in one of the n trials

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Binomial Probability Distributions Notation for a Binomial Probability Distribution S and F (success and failure) denote the two possible categories of outcomes. P(S)=pp=probability of success P(F)=qq=probability of failure ndenotes the fixed number of trials xdenotes a specific number of successes in n trials pdenotes the probability of success in one of the n trials qdenotes the probability of failure in one of the n trials P(x)denotes the probability of getting exactly x successes among the n trials

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Binomial Probability Distributions

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Determine whether the given procedure results in a binomial distribution. Surveying 12 jurors and recording whether there is a “no” response when they are asked if they have ever been convicted of a felony

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Surveying 12 jurors and recording whether there is a “no” response when they are asked if they have ever been convicted of a felony Binomial

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Treating 50 smokers with Nicorette and recording whether there is a “yes” response when they are asked if they experience any mouth or throat soreness.

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Treating 50 smokers with Nicorette and recording whether there is a “yes” response when they are asked if they experience any mouth or throat soreness. Binomial

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Recording the number of children in 250 families

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Recording the number of children in 250 families Not binomial, there are more than two outcomes.

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Fifteen different Governors are randomly selected from the 50 Governors currently in office and the sex of each Governor is recorded.

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Fifteen different Governors are randomly selected from the 50 Governors currently in office and the sex of each Governor is recorded. Not binomial, not independent!

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Two hundred statistics students are randomly selected and each is asked if he or she owns a Ti-84 Plus Calculator.

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Binomial Probability Distributions Determine whether the given procedure results in a binomial distribution. Two hundred statistics students are randomly selected and each is asked if he or she owns a Ti-84 Plus Calculator. No, but yes?!?!? We can use the 5% guideline for cumbersome calculations.

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Binomial Probability Distributions Binomial Probability Formula In a binomial Probability distribution, probabilities can be calculated by using the binomial probability formula.

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Binomial Probability Distributions Binomial Probability Formula In a binomial Probability distribution, probabilities can be calculated by using the binomial probability formula. First recall/learn: Factorial symbol (!) denotes the product of decreasing powers of positive whole numbers.

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Binomial Probability Distributions

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The probability of an offspring pea will have a green pod is ¾. That is P(green pod) = 0.75. Let’s use the binomial probability formula to find probability that exactly 3 of the 5 offspring peas have a green pod.

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Binomial Probability Distributions

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Assume that a procedure yields a binomial distribution with a trial repeated 14 times. Use Table A-1 to find the probability of 4 successes given the probability 0.60 of success on a single trial.

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Binomial Probability Distributions Assume that a procedure yields a binomial distribution with a trial repeated 5 times. Using the Binomial Probability formula find the probability of 2 successes given the probability.35 of success on a single trial.

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Binomial Probability Distributions The brand name of McDonald’s has a 95% recognition rate. If a McDonald’s executive wants to verify that rate by beginning with a small sample of 15 randomly selected consumers, find the probability that exactly 13 of the 15 consumers recognize the McDonald’s brand name. Also find the probability that the number who recognize the brand name is not 13.

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Homework!!! 5-3: 1-8,13, 33, 35, and 39.

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Use the given values of n and p to find the mean μ and the standard deviation σ. Also, use the range rule of thumb to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ.

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Given: n = 60, p = 0.25 Mean: μ = np = (60)(.25) = 15 Standard deviation: σ = √(60 *.25 *.75) = 3.354 Min usual value: μ - 2σ = 15 – 2(3.354) = 8.292 Max usual value: μ + 2σ = 15 + 2(3.354) = 21.708

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Several economics students are unprepared for a multiple-choice quiz with 25 questions, and all of their answers are guesses. Each question has five possible answers, and only one of them is correct. Find the mean and standard deviation for the number of correct answers for such students. Mean: μ = (25)(1/5) = 5 Standard deviation: σ = √(25 *.2 *.8) = 2

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232 Mars, Inc., claims that 24% of its M&M plain candies are blue. A sample of 100 M&Ms is randomly selected. Find the mean and standard deviation for the numbers of blue M&Ms in such groups of 100. Mean: μ = np μ = (100)(.24) = 24 Standard deviation: σ = √(100 *.24 *.76) = 4.3

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Data Set 18 in Appendix B consists of a random sample of 100 M&Ms in which 27 are blue. Is this result unusual? Does it seem that the claimed rate of 24% is wrong? μ = 24 σ = 4.3 The max usual values: 24 + 2(4.3) = 32.6 M&Ms The min usual values: 24 – 2(4.3) = 15.4 M&Ms

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Homework!!! 5-3: 1-8,13, 33, 35, and 39. 5-4: 1-12, 17, 19

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