Download presentation

Presentation is loading. Please wait.

Published byWillie Heath Modified over 3 years ago

1
Lecture 211 Phasor Diagrams and Impedance

2
Lecture 212 Set Phasors on Stun 1.Sinusoids-amplitude, frequency and phase (Section 8.1) 2.Phasors-amplitude and phase (Section 8.3 [sort of]) 2a. Complex numbers (Appendix B).

3
Lecture 213 Set Phasors on Kill 3.Complex exponentials-amplitude and phase 4.Relationship between phasors, complex exponentials, and sinusoids 5.Phasor relationships for circuit elements (Section 8.4) 5a. Arithmetic with complex numbers (Appendix B).

4
Lecture 214 Set Phasors on Vaporize 6.Fundamentals of impedance and admittance (some of Section 8.5) 7.Phasor diagrams (some of Section 8.6)

5
Lecture 215 Phasor Diagrams A phasor diagram is just a graph of several phasors on the complex plane (using real and imaginary axes). A phasor diagram helps to visualize the relationships between currents and voltages.

6
Lecture 216 An Example - 1F1F VCVC + - 2mA 40 1k VRVR + + - V

7
Lecture 217 An Example (cont.) I = 2mA 40 V R = 2V 40 V C = 5.31V -50 V = 5.67V -29.37

8
Lecture 218 Phasor Diagram Real Axis Imaginary Axis VRVR VCVC V

9
Lecture 219 Impedance AC steady-state analysis using phasors allows us to express the relationship between current and voltage using a formula that looks likes Ohm’s law: V = I Z Z is called impedance.

10
Lecture 2110 Impedance Resistor: –The impedance is R Inductor: –The impedance is j L

11
Lecture 2111 Impedance Capacitor: –The impedance is 1/j L

12
Lecture 2112 Some Thoughts on Impedance Impedance depends on the frequency . Impedance is (often) a complex number. Impedance is not a phasor (why?). Impedance allows us to use the same solution techniques for AC steady state as we use for DC steady state.

13
Lecture 2113 Impedance Example: Single Loop Circuit 20k + - 1F1F10V 0 VCVC + - = 377 Find V C

14
Lecture 2114 Impedance Example How do we find V C ? First compute impedances for resistor and capacitor: Z R = 20k = 20k 0 Z C = 1/j (377 1 F) = 2.65k -90

15
Lecture 2115 Impedance Example 20k 0 + - 2.65k -90 10V 0 VCVC + -

16
Lecture 2116 Impedance Example Now use the voltage divider to find V C :

17
Lecture 2117 What happens when changes? 20k + - 1F1F10V 0 VCVC + - = 10 Find V C

18
Lecture 2118 Low Pass Filter: A Single Node-pair Circuit Find v(t) for =2 3000 1k 0.1 F 5mA 0 + - V

19
Lecture 2119 Find Impedances 1k -j530k 5mA 0 + - V

20
Lecture 2120 Find the Equivalent Impedance 5mA 0 + - VZ eq

21
Lecture 2121 Parallel Impedances

22
Lecture 2122 Computing V

23
Lecture 2123 Change the Frequency Find v(t) for =2 455000 1k 0.1 F 5mA 0 + - V

24
Lecture 2124 Find Impedances 1k -j3.5 5mA 0 + - V

25
Lecture 2125 Find an Equivalent Impedance 5mA 0 + - VZ eq

26
Lecture 2126 Parallel Impedances

27
Lecture 2127 Computing V

Similar presentations

OK

Lecture 26 Review Steady state sinusoidal response Phasor representation of sinusoids Phasor diagrams Phasor representation of circuit elements Related.

Lecture 26 Review Steady state sinusoidal response Phasor representation of sinusoids Phasor diagrams Phasor representation of circuit elements Related.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To ensure the functioning of the site, we use **cookies**. We share information about your activities on the site with our partners and Google partners: social networks and companies engaged in advertising and web analytics. For more information, see the Privacy Policy and Google Privacy & Terms.
Your consent to our cookies if you continue to use this website.

Ads by Google

Ppt on modernization in indian railways Ppt on embedded web technology Export pdf to ppt online Ppt on solar power satellites sps Ppt on natural resources management Ppt on 2nd world war pictures Ppt on maths tricks and tips Download ppt on diwali Download ppt on web designing Ppt on flowers for kindergarten