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Physics 1D03 - Lecture 71 Newton’s Laws (II) Free-body diagrams Normal Force Friction, ropes and pulleys Serway and Jewett : 5.7, 5.8.

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Presentation on theme: "Physics 1D03 - Lecture 71 Newton’s Laws (II) Free-body diagrams Normal Force Friction, ropes and pulleys Serway and Jewett : 5.7, 5.8."— Presentation transcript:

1 Physics 1D03 - Lecture 71 Newton’s Laws (II) Free-body diagrams Normal Force Friction, ropes and pulleys Serway and Jewett : 5.7, 5.8

2 Physics 1D03 - Lecture 72 Free-Body Diagrams Pick one object (the “body”). Draw all external forces which act directly on that body (gravity, contact, electromagnetic). Imagine cutting around the body to separate it from its surroundings. Replace each external object with a force applied at the point of contact. Indicate the direction of the acceleration of the object beside the diagram; but remember, ma is not a force on the diagram.

3 Physics 1D03 - Lecture 73 Example: free-body diagram A block is pulled up a frictionless ramp: m Note : title, to indicate the chosen object (use m or m A etc) contact forces, to replace the rope and the ramp gravity doesn’t require contact a may be indicated for reference, but is not a force Forces on Block

4 Physics 1D03 - Lecture 74 Ropes and Pulleys Tension is uniform in a rope of negligible mass The tension is not changed if the rope passes over an ideal pulley (frictionless and massless) Tension has units of force (newtons) A rope attached to something exerts a force parallel to the rope The magnitude of the force is called the tension in the rope rope Force

5 Physics 1D03 - Lecture 75 Quiz Since the elevator is broken, a student rigs up a bucket-and-pulley system to avoid climbing stairs. The student weighs 750 N, and the bucket weighs 250 N. How hard (with what force) must the student pull on the rope to go up with the bucket?

6 Physics 1D03 - Lecture 76 - normal force, perpendicular to the surfaces - friction, parallel to the surface FAFA Contact Forces Example: We try to push a block across a table; the table pushes back. Divide the contact force from the table into two components: F A = applied force

7 Physics 1D03 - Lecture 77 This is really an elastic force; the table behaves like a spring. At the atomic level, contact forces are due to electromagnetic interactions. If we look closely, the normal force arises from the table being bent : as the table tries to straighten, it pushes back.

8 Physics 1D03 - Lecture 78 Friction Friction is the force which resists sliding of two surfaces across each other. We distinguish between static and kinetic friction: Static Friction : - there is NO relative motion - f s prevents sliding Kinetic Friction : - the block is sliding - f k is opposite to v FAFA v

9 Physics 1D03 - Lecture 79 Friction is complicated. A useful empirical model was presented by Charles Coulomb in 1781: 1.The force of static friction has a maximum value; if you push too hard, the block moves. This maximum value is proportional to the normal force the surfaces exert on each other. 2.Once the object is sliding, kinetic friction is approximately independent of velocity, and usually smaller than the maximum static friction force. The force of kinetic friction is also proportional to the normal force.

10 Physics 1D03 - Lecture 710 Define two pure numbers (no units):  s (“coefficient of static friction”)  k (“coefficient of kinetic friction”) (“  ” is a Greek letter, pronounced “mu”) Then Coulomb’s rules are: Question : would it be correct to write these as vector equations, ?

11 Physics 1D03 - Lecture 711 Copper on steel0.530.36 Aluminum on aluminum1.51.1 Teflon on Teflon0.040.04 Values depend on smoothness, temperature, etc. and are approximate Usually  < 1, but not always Usually,  k is less than  s, and never larger The coefficients depend on the materials, but not on the surface areas, contact pressure, etc.

12 Physics 1D03 - Lecture 712 Each block weighs 100 N, and the coefficient of static friction between each pair of surfaces is 0.50. What minimum force F is needed to pull the lower block out? 100 N Concept Quiz a)50 N b)100 N c)150 N F

13 Physics 1D03 - Lecture 713 Equilibrium A special case : (object doesn’t move, or moves at constant velocity) Newton’s second law gives This is equivalent to three independent component equations: We can solve for 3 unknowns (or 2, in 2-D problems) The vector sum of forces acting on a body in equilibrium is zero

14 Physics 1D03 - Lecture 714 Example A block is in equilibrium on a frictionless ramp. What is the tension in the rope? m 

15 Physics 1D03 - Lecture 715 Quiz m The block has weight mg and is in equilibrium on the ramp. If  s = 0.9, what is the frictional force? 37 o A)0.90 mg B)0.72 mg C)0.60 mg D)0.54 mg

16 Physics 1D03 - Lecture 716 A Heavy Rope A B Find the tension in the rope at A and at B. Should we assume T A = T B ?

17 Physics 1D03 - Lecture 717 mg TATA TBTB Free-body diagram of rope TBTB TATA mg weight should be applied at the “center of mass”, which we will discuss later. For summing forces, the force locations don’t matter, only directions. Example 3 (solutions)

18 Physics 1D03 - Lecture 718 Example For what angle θ is the system in equilibrium? (assume frictionless surfaces, ideal pulleys, etc.) M m 

19 Physics 1D03 - Lecture 719 Summary Free-body diagrams (Text section 5.7) Equilibrium: if Force Laws: - ropes and pulleys - normal force Static and kinetic friction, f=μN

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