Presentation on theme: "1 Introduction to soil water relationships. 2 3."— Presentation transcript:
1 Introduction to soil water relationships
5 Particle density ( s ) Definitions Mass of soil particle divided by volume of soil particle Specific gravity, SG = ratio of mass of soil particle to mass of equal volume of water of water at 4°C Particle density in cgs or tonnes m -3 numerically equal to SG mean particle density depends on: ratio of OM to mineral matter constitution of soil minerals constitution of OM
6 Determination SG bottle boiled water to remove dissolved air de-aerate for several hours with vacuum pump to remove air trapped between particles problem of floating OM Typical values organic matter = 1.3 g cm -3 quartz = 2.66 g cm -3 average for clay = 2.65 g cm -3 orthoclase = 2.5 to 2.6 g cm -3 mica = 2.8 to 3.2 g cm -3 limonite = 3.4 to 4.0 cm -3 Fe (OH) 3 = 3.75 cm -3 normally taken as 2.65 cm -3
7 Bulk density ( b ) and related parameters Value is effected by particle density, degree of compaction, organic matter content Bulk density b = mass of solids total volume
8 Typical values: 0.9 for organic soil (peaty) to 1.8 for compacted sand Sand generally has a higher density than clay - why? What do we mean by heavy & light soils? Determination: soil coring devices problems of compaction oven drying at 105°C gamma ray transmission
9 Gamma ray transmission measures density – 2 probes - transmitter & detector
10 Wet v dry bulk density M s + M w V t
11 Coefficient of linear extensibility (COLE) Bulk density changes in swelling - shrinking soils. COLE is a measure of this Compares dry with saturated soil after it comes to equilibrium. Cracks complicate the problem of determining BD of swelling soils. Even allowing for cracks the overall density may be higher on shrinking as the surface becomes lower.
13 Total pore space (T) = volume of (air + water) vol. of (air + soil + water)
14 Volume of (air + water) = total volume (air + soil + water) - volume of soil where V t and V s are the volumes of the total sample and the soil particles respectively V s = M s / s and V t = M s / b where M s is the mass of oven dry soil and s and b are the particle density and bulk density respectively. So:
15 and so: and : b = (1-T)/ s Used in agricultural (soils) research especially for compaction studies. Typical values 0.3 to 0.6. Often expressed as a %.
16 Void ratio (e) Used mainly in engineering applications e = volume of (air + water) volume of soil e = T/(1-T)[void ratio] Typically 0.3 to 2.0 Packing density measure of compaction of particular texture class Air filled porosity = volume of air volume of total
17 Moisture content and related parameters (a) Volumetric basis: volume of water volume of total v = V w /V t (b) Gravimetric basis: mass of water mass of soil m = M w /M s
18 As V w = M w / w and V t = M s / b then and so v = m b / w = m b /1 (not dimensionally correct) in metric measurements - density of water is 1 Often expressed as depth/depth for example mm/m
19 Degree of saturation (s) degree of saturation = volume of water volume of (water + air) s = V /T Liquid ratio Liquid ratio = volume of water volume of solid
20 An example to try A hole 30 cm X 30 cm x 30 cm is dug in a field. The wet soil weighs 50.55 kg. The soil is taken back to the laboratory and oven dried. The final weight is 38.34 kg. (a) What is the bulk density (b) What was the moisture content in the field (i) by volume (ii) by weight (c) If the mean particle density is 2.64, what is the total pore space
21 Graphical representation.... Q. Why is the moisture content less at depth?)
22 Measurement of soil moisture Laboratory definitive weigh, oven dry at 105°C for 24 hours, reweigh if volume of hole from which sample was taken is known, bulk density can be calculated and hence volumentric moisture content Field methods Include: neutron scattering gamma ray transmission time domain reflectometry all need calibration against laboratory method
23 Neutron scattering
24 H scatters and slows neutrons very effectively - elastic collisions with atomic nuclei called “thermalisation” of fast neutrons - come to same thermal (vibrational) energy as atoms at ambient temperature hydrogen, has nucleus of about same size & mass as neutron and so has much greater thermalising effect on fast neutrons than any other element method detects mostly H atoms not water per se single probe containing radioactive source of high-energy neutrons such as radium-beryllium or americium-beryllium or caesium-137 thermal neutron density easily measured thermal neutron density may be calibrated against water concentration on volume basis of other sources of H are constant
25 Time domain reflectometry measures dielectric constant - ability of soil to transmit electromagnetic (radar) waves - mostly but not entirely dependent on water
26 Theta Probe
27 Simple parameters to characterise H 2 O & O 2 availability Soil water potential matric potential gravitational potential pressure potential
28 Note on units Soil water potential is the energy density - usually per unit volume Since dimensions of energy is ML 2 T -2 (force x distance) dimensions of soil water potential has dimensions of ML -1 T -2 Pressure is force per unit area so has units of MLT -2 /L 2 = ML -1 T -2 Soil water potential thus has same units as pressure. It can this be expressed as bars, cm H 2 O, cm Hg, atmospheres SI unit of Pressure, and so energy density, is the Pascal 1 kPa = 10 mb, 1 bar = 100 kPa
29 Capillarity and adsorbed water combine to produce matric potential
30 Permanent wilting point Usually taken as 15 (1500 kPa) bars, but may be more, e.g. 20 bars (2000 kPa). Water held between 1500 and 2000 kPa negligible in virtually all soils. PWP strongly correlated with clay. In reality, a dynamic property which depends on: potential evapotranspiration, unsaturated hydraulic conductivity of the soil, type of plant.
31 Field capacity the upper limit of available water; traditionally defined as the moisture content of a soil 48 hours after saturation and subsequently being allowed to drain; a high proportion of irrigation water added above field capacity is “wasted”; FC has also been considered to be: 0.33 bars [33 kPa] in USA or 0.1 bars [10 kPa] in the UK FC also sometimes considered as the mean soil moisture content in winter (cold climates) when the potential evapotranspiration is small (and so drainage is main factor governing equilibrium moisture content.
32 The tension equivalent to FC will be at least equal to the air entry potential - see below. FC, PWP and AWC are strongly dependent on texture, OM and BD
33 Air capacity Defined as the air content (%) at field capacity. Used in poaching studies. Low air capacity usually means poor aeration. Available water capacity Difference between FC and PWP (%) often x soil depth to give mm
34 Exercise The moisture content of a soil at field capacity was found to be 27.3% by weight. At wilting point, the moisture content was 19.7%. After oven drying of a volumetric sample, it was found that the bulk density was 1.42 g cm -3. What is the available water capactiy as a percentage of the volume? A crop has a rooting depth of 1.5 m. How much water is potentially available to the crop in mm equivalent. If irrigation is to take place when the AWC is depleted by 40%, how much water would need to be added?
35 Effect of bulk density on air capacity, wilting point & field capacity
37 Dependence of compaction on moisture content
39 Dry year Wet year Any suggestions?
40 Dynamic nature of FC, PWP, AWC It is important to realise that FC, PWP and AWC are commonly conceived as static soil properties but that in reality, the are used as proxies for characteristics of dynamic system. They do not take into account: field conditions such as underlying horizons; rainfall and or irrigation frequency and amount; hydraulic conductivity of the soil; run-off characteristics; roots extension; water infiltration and redistribution; drainage from soil profile; some water may drain at the same time as evapotranspiration takes place; ground cover changes;
41 crop height changes climate, especially evapotranspiration rate effect the values Beware of too simplistic a view. Even so, FC, PWP and AWC are very useful concepts.
42 Measurement of soil potential Tensiometers After Richards, 1965
43 Electrical resistance methods Gypsum blocks Granular Matrix Sensors e.g. WATERMARK sensor from Irrometer Co, USA
44 If vapour between soil particles is in equilibrium with held water, the vapour pressure is influenced by the “pull” of the soil water... Relationship of soil water potential to soil vapour pressure where : t is the sum of matric and osmotic potential is the density of the water at the prevailing temperature, R is the Universal Gas Constant M is the molecular weight of water T is the Temperature (°K) e is the vapour pressure in the soil pores e 0 is the saturated vapour pressure of free water at the particular temperature
45 The phenomenon is used as the basis of: (a) the determination of the potential of a soil in the laboratory (often in order to determine the moisture release characteristics) by allowing a filter paper of known pore size / moisture release characteristics to come into equilibrium with the moist air over the soil which is also in equilibrium with the soil water potential. (b) to determine the soil water potential in the field by determining the humidity of the soil air using a thermocouple psychrometer
47 Moisture release characteristics Determination pressure plate apparatus sand; sand/kaolin bath apparatus filter paper - allow to come into equilibrium and weigh paper solution - mixture so that vapour pressure is known and this can be equated to soil potential, allow soil to come into equilibrium with solution use of pF scale
48 Filter paper method top filter paper not in contact - measures sum of matric and osmotic potential of soil bottom filter paper is in pore contact so measures matric potential
51 Typical curves Near air entry potential
52 Air entry potential ( e ) Also known as air entry value or bubbling pressure = pressure at which largest pores begins to empty Related to structure and field capacity. e corresponds to the largest pore size where and
53 es is the air entry potential when the bulk density is 1.3 g cm -3 is in J/kg d g the geometric mean particle diameter, is in mm, and g is the geometric standard deviation of the particle sizes in mm (ranges from 1 to 30).
54 Example calculation of d g and g (based on Campbell, p.9) It is assumed that clay has d < 0.002 mm silt has 0.002 < d < 0.05 mm sand has 0.05 < d < 2 mm The predictor equations assumes that particle size distribution is log normal Logarithm of geometrical mean is given by: ln d g = m i ln d i where the d i are the textural class sizes and m i are the amounts in each class The d i for the size classes are calculated from (lower limit + upper limit)/2
55 thus: d clay = 0.001 mm; ln(d clay ) = - 6.91 d silt = 0.026 mm; ln(d silt ) = -3.65 d sand = 1.025 mm; ln(d sand ) = 0.025 If a soil is 0.6 clay, 0.25 silt and 0.15 sand, then ln d g = (0.6 x - 6.91) + (0.25 x - 3.65) + (0.15 x 0.025) = - 4.146 - 0.9125 + 0.00375 = - 5.05475 = 0.00638 mm
56 Substituting this in the above equation, the standard air entry potential is - 12 J kg -1 To make allowances for bulk density, we need first to calculate g. The normal standard deviation is given by: In a similar way, the logarithmic standard deviation is given by: (ln g ) 2 = f 1 (ln d 1 ) 2 + f 2 (ln d 2 ) 2 + f 3 (ln d 3 ) 2 - (ln d g ) 2 The geometric SD is the antilog of the SD of the log transformed values. Thus: ln g = 2.42 and so g = e 2.42 = 11.24 and b = 2 x 12 + 0.2 x 11.24 = 24 + 2.25 = 26.25
57 Thus for this soil, For bulk densities of 1.1, 1.3 and 1.5, the air entry potentials would be: - 0.84, - 12 - 148.9 J kg -1 respectively
58 Sand tension table (0 to 100 cm potential)
59 Kaolin table (100 cm to 400 cm potential) H should be added to difference between atmospheric pressure and pressure in aspirator bottle
60 Pressure plate method for potentials from 1 bar to 15 bars
61 Prediction of matric potential Not reliable but some workers use equations of the form: where s = saturation % (vol) and F e, the air entry potential is calculated as before from:
62 Clays Treated here because flocculation in the field is an essential part of reclamation of sodic soils. Flocculation occurs when clay particles “stick” together because of electrical forces to form larger particles and hence improves the hydraulic properties of the clay Flocculation changes the hydraulic conductivities and the moisture holding properties of clay soils. Clay = 0.2 Colloidal clay: = < 0.2 m Adsorption: concentration of one material at surface of another Absorption: uptake of one material into another
63 Colloidal material is surrounded by thin layer of solution which is different in composition from the solution (relatively) far away from the particles. Layer moves with the particle. Micelle: colloidal particle + hydration shell Intermicellar fluid : solution between micelles
65 Micelles usually negatively charged because of: isomorphic substitution: Si++++ in the clay may be substituted by Fe+++ or Al+++ which makes the clay short of + charge and so negatively charged - smectite or illite type materials Fe++ or Mg++ may replace Fe+++ or Al+++ in alumina or gibbsite sheets ionisation at the surface: e.g. appearance of OH - at the surface and edges of micelle H 2 O adsorption and subsequent ionisation & diffusion of H+ leaving a net negative charge because of the OH – preferential adsorption of anions from solution for example the adsorption of CO3- onto calcium carbonate leaving an associated ion in solution
66 Some mutual attraction occurs between particles because of edge effects
67 Double layer Double layer is name given to accumulation of positively charged ions around negatively charged micelles – some attached, some in solution controls flocculation and dispersion dependent on –cation type –cation concentration –pH the thicker the double layer, the greater the net repulsion and the more dispersed a soil becomes important in structure and aggregation and reclamation of saline and sodic soils
68 negatively charged soil particle + + + + + + + + + + + + + a layer of cations directly satisfies some of the negative charge diffuse second layer eventually reaches same concentration as surrounding bulk solution + + + + + + + + + + + + + + + + + + + + + + + + + + + + + Negative ion concentration in solution increases with distance & positive ion concentration decreases
69 Different models: Helmholtz model - assumes the charge concentration decreases linearly with distance Gouy-Chapman model - assumes charge concentration decreases exponentially with distance Stern model - assumes linear decrease in the Stern layer near the surface and then an exponential decrease - thickness of Stern layer normally taken as equal to the ionic radius of the adsorbed species.
70 The double layer is depressed by increasing the valency of the ions in the intermicellar solution and hence the packing of the charge near the micelle surface. This is known as the depression of the double layer.
74 pH OH Si Al (+1/2) OH Si Al (+1/2) (-1/2) OH O O Si Al (-1/2) (-1) Kaolinite edge lower pH higher pH neutral pH
75 London - van der Vaals forces In addition to repulsive forces caused by accumulated positive charges, there is also an attractive force between clay particles caused by London - van der Vaals forces. These forces, which occur even between electrically neutral atoms, are due to the fact that, although the average electrical field of a neutral spherical atom is zero, the instantaneous field is not zero but fluctuates with the movements of the electrons in the atom (or ion). When 2 atoms (or ions) approach, they can synchronise their electronic motions so that the electrical charge in one surges towards the other when the fluctuations in this second atom happen to leave its nuclear field somewhat exposed in this particular direction.
77 Depending on relative strength of forces of attraction and forces of repulsion, attractive van der Waals forces may predominate in which case flocculation takes place.
79 The thickness of the double layer is altered by both the concentration and the ratio of divalent to monovalent ions (and the ratio of tri-valent ions to mono-valent ions). If the constitution and concentration of the soil solution is changed, the constitution of the ions in the double layer will change. Replacement of monovalent ions by divalent ions in the double layer makes it thinner and so more easy for Van der Waals forces to take over and make the particles stick together Langmuir equation Relates the amount of adsorption onto clay particles to the concentration of the solution. Look it up.
80 Specific surface Important effect on: cation exchange retention and release of various chemicals (nutrients and pollutants) swelling of clays retention of water engineering properties (e.g. plasticity, cohesion, strength )
81 a m = A s /M s a v = A s /V s a b = A s /V t where a is the specific surface, A s is the total surface area in the sample, M s is the mass of solids, V s is the volume of the solids, V t is the total volume of the sample. Suffixes m, v and b refer to whether specific surface is on a mass basis, volume of solids basis or volume of total soil basis.
82 Measured from amount of gas absorbed at certain T and P. Can also be estimated from particle size distribution & distribution of minerals NB. surface area/volume for sphere = 6/d = a v Typical values
83 Texture and particle size distribution Definitions of sand, silt, clay 1 = 10 -6 m = 10 -3 mm sand: 50 - 2000 silt: 2 - 50 clay : < 2
84 Texture triangles (using above definitions)
86 Mechanical analysis Separation of particles OM removed by H 2 O 2 sometimes CaCO 3 cementing agent removed by HCl deflocculation by adding Calgon (sodium hexametaphosphate) mechanical agitation (shaking, stirring, ultrasound) Sieving Use sieves down to 0.05 mm (very fine sand)
87 SedimentationTheory Falling particle in a fluid experiences a downward force and resistance force (drag) in opposite direction. Stokes (1851) found that the drag was given by: F d = 6 ru u is terminal velocity, is the viscosity, r is the radius of the sphere
88 When the two forces are in equilibrium, particle reaches a “terminal velocity”. In that condition, downward force on the particle = gravity - upthrust due to fluid density Upthrust = weight of particle - weight of fluid displaced weight of particle = 4/3 r 3 s g where s is the particle density weight of water displaced = 4/3 r 3 f g where w is the density of fluid So upthrust is 4/3 r 3 ( s - f ) g At terminal velocity, 6 ru =4/3 r 3 g( s - f )
89 which can be rearranged as: where d is the diameter of the particle. Since u = h/t where h is height dropped and t is the time elapsed t = h/u and so and
90 Pipette method All particles > d(h, t) will have settled out by time t Proportion of original can be determined by taking a sample After 8 hours only clay is left in suspension Hydrometer Measures density of remaining soil suspension instead of taking a sample X-ray transmission methods Transmission related to density. Gives continuous distribution