2Composite Figure:a figure that is made by combining triangles, quadrilaterals, semi-circles and other two-dimensional figures.
3Perimeter: Is the distance around a figure 7 cm5 cm3 cm?7 cm4 cmP = 7 cm+ 5 cm+ 4 cm+ 7 cmcmP = cmThe perimeter of a circle has a special name,It is called the ______________, and is found usingeither of these formulas:circumference
4Alice needs to purchase 37 feet of border. Alice is putting a wallpaper border around her bedroom. Shemust find the __________ of her bedroom in order topurchase the correct amount of border.perimeter12 ft3 ft?4 ft6.5 ft?3.5 ft8 ftP = 8 ft+ 6.5 ft+ 12 ft+ 3 ft+ 4 ft+ 3.5 ftAlice needs to purchase 37 feet of border.
5The area of a composite figure can be found by adding or subtracting the areas of the simpler figures that compose the composite figure.Area of Semi-Circle+ Area of Rectangle+ Area of Triangle
6Joe has to mow the lawn of the field below, how many square yards must he mow? 14 yd3 yd10 yd10 yd6 yd6 yd8 yd8 ydArea of Semi-Circle+ Area of Rectangle+ Area of Triangle
7Is there another way of finding this area? Detective LeRue must investigate a crime committed at the localpark. How many square meters of ground must he cover whenlooking for clues?Total area = 28 m m m2= 65 square metersIs there another way of finding this area?Area = 4 m (7 m)Area = 4 m(4 m)4 m3 m3 mArea =3 m(7 m)4 m28 m27 m21 m27 m16 m2
8How can we use subtraction to find the area? Step 1: Find area of big rectangleStep 2: Find area of smaller rectangleStep 3: Subtract the smaller area from the larger areaTotal area= 77 m2 – 12 m2= 65 square metersHow can we use subtraction to find the area?11 m4 m4 m3 m3 mArea= 3 m(4 m)4 m7 m7 mArea =7 m (11 m)=12 m2= 77 m2
9Detective LaRue must isolate the crime scene, how much tape will he need?Perimeter =7m + 4 m + 3 m + 4 m + 3 m + 3 m + 7 m + 11 mDetective LaRue needs 42 meters of crime scene tape.4 m3 m?3 m4 m7 m7 m?
10Area = 74 cm2 Perimeter = 40 cm 1. Find the area and perimeter 6 cm
11Area = 2300 in2 Perimeter = 240 in 2. Find the area and perimeter
12Area = 30 yd2 Perimeter = 29 yd 3. Find the area and perimeter 3 yd
13Area = 88.26 ft2 Perimeter = 38.84 ft 4. Find the area and perimeter. Use 3.14 for πArea = ft Perimeter = ft
14Area = 212.75 km2 Perimeter = 69.7 km 5. Find the area and perimeter
156. Find the area and perimeter Area = 97.5 m2Perimeter= 36 m3 m12.5 m7.5 m13 m