2 Composite Figure:a figure that is made by combining triangles, quadrilaterals, semi-circles and other two-dimensional figures.
3 Perimeter: Is the distance around a figure 7 cm5 cm3 cm?7 cm4 cmP = 7 cm+ 5 cm+ 4 cm+ 7 cmcmP = cmThe perimeter of a circle has a special name,It is called the ______________, and is found usingeither of these formulas:circumference
4 Alice needs to purchase 37 feet of border. Alice is putting a wallpaper border around her bedroom. Shemust find the __________ of her bedroom in order topurchase the correct amount of border.perimeter12 ft3 ft?4 ft6.5 ft?3.5 ft8 ftP = 8 ft+ 6.5 ft+ 12 ft+ 3 ft+ 4 ft+ 3.5 ftAlice needs to purchase 37 feet of border.
5 The area of a composite figure can be found by adding or subtracting the areas of the simpler figures that compose the composite figure.Area of Semi-Circle+ Area of Rectangle+ Area of Triangle
6 Joe has to mow the lawn of the field below, how many square yards must he mow? 14 yd3 yd10 yd10 yd6 yd6 yd8 yd8 ydArea of Semi-Circle+ Area of Rectangle+ Area of Triangle
7 Is there another way of finding this area? Detective LeRue must investigate a crime committed at the localpark. How many square meters of ground must he cover whenlooking for clues?Total area = 28 m m m2= 65 square metersIs there another way of finding this area?Area = 4 m (7 m)Area = 4 m(4 m)4 m3 m3 mArea =3 m(7 m)4 m28 m27 m21 m27 m16 m2
8 How can we use subtraction to find the area? Step 1: Find area of big rectangleStep 2: Find area of smaller rectangleStep 3: Subtract the smaller area from the larger areaTotal area= 77 m2 – 12 m2= 65 square metersHow can we use subtraction to find the area?11 m4 m4 m3 m3 mArea= 3 m(4 m)4 m7 m7 mArea =7 m (11 m)=12 m2= 77 m2
9 Detective LaRue must isolate the crime scene, how much tape will he need?Perimeter =7m + 4 m + 3 m + 4 m + 3 m + 3 m + 7 m + 11 mDetective LaRue needs 42 meters of crime scene tape.4 m3 m?3 m4 m7 m7 m?
10 Area = 74 cm2 Perimeter = 40 cm 1. Find the area and perimeter 6 cm
11 Area = 2300 in2 Perimeter = 240 in 2. Find the area and perimeter
12 Area = 30 yd2 Perimeter = 29 yd 3. Find the area and perimeter 3 yd
13 Area = 88.26 ft2 Perimeter = 38.84 ft 4. Find the area and perimeter. Use 3.14 for πArea = ft Perimeter = ft
14 Area = 212.75 km2 Perimeter = 69.7 km 5. Find the area and perimeter
15 6. Find the area and perimeter Area = 97.5 m2Perimeter= 36 m3 m12.5 m7.5 m13 m