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Published byEden Issac Modified about 1 year ago

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Perimeter and Area of Composite Figures

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Composite Figure: a figure that is made by combining triangles, quadrilaterals, semi-circles and other two- dimensional figures.

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Perimeter: Is the distance around a figure 7 cm 5 cm 4 cm 3 cm 7 cm The perimeter of a circle has a special name, It is called the ______________, and is found using either of these formulas: circumference P = 7 cm+ 5 cm + 4 cm + 7 cm + 4.71 cm P = 27.71 cm ?

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12 ft 6.5 ft 3 ft 8 ft Alice is putting a wallpaper border around her bedroom. She must find the __________ of her bedroom in order to purchase the correct amount of border. perimeter P = 8 ft+ 6.5 ft+ 12 ft+ 3 ft ? ? 4 ft 3.5 ft + 4 ft+ 3.5 ft Alice needs to purchase 37 feet of border.

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The area of a composite figure can be found by adding or subtracting the areas of the simpler figures that compose the composite figure. Area of Semi-Circle + Area of Rectangle + Area of Triangle

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Area of Semi-Circle + Area of Rectangle + Area of Triangle 14 yd 10 yd 6 yd 8 yd 3 yd Joe has to mow the lawn of the field below, how many square yards must he mow? 10 yd 8 yd 6 yd

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7 m 4 m 3 m 7 m Total area = 28 m 2 + 16 m 2 + 21 m 2 = 65 square meters Area = 4 m (7 m) Area = 4 m(4 m) 4 m Area =3 m(7 m) 21 m 2 28 m 2 16 m 2 Is there another way of finding this area? Detective LeRue must investigate a crime committed at the local park. How many square meters of ground must he cover when looking for clues?

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7 m 4 m 3 m 7 m Total area = 77 m 2 – 12 m 2 = 65 square meters Area =7 m (11 m) Area = 3 m(4 m) 4 m = 77 m 2 =12 m 2 How can we use subtraction to find the area? Step 1: Find area of big rectangle Step 2: Find area of smaller rectangle Step 3: Subtract the smaller area from the larger area 4 m 11 m

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7 m 4 m 3 m 7 m 4 m Detective LaRue must isolate the crime scene, how much tape will he need? ? ? Detective LaRue needs 42 meters of crime scene tape. Perimeter = 7m + 4 m + 3 m + 4 m + 3 m + 3 m + 7 m + 11 m

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9 cm 5 cm 2 cm 6 cm 1. Find the area and perimeter Area = 74 cm 2 Perimeter = 40 cm

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70 in 20 in 30 in 2. Find the area and perimeter Area = 2300 in 2 Perimeter = 240 in

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8 yd 4.5 yd 3 yd 2 yd 3 yd 3. Find the area and perimeter Area = 30 yd 2 Perimeter = 29 yd

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4. Find the area and perimeter. Use 3.14 for π Area = 88.26 ft 2 Perimeter = 38.84 ft

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5. Find the area and perimeter 18 km 14 km 4 km Area = 212.75 km 2 Perimeter = 69.7 km

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3 m 7.5 m 13 m 12.5 m 6. Find the area and perimeter Area = 97.5 m 2 Perimeter= 36 m

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7. Find the area of the arrow. Area = 90 ft 2

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8. Find the Area of the Shaded Region. Use 3.14 for π. Area = 437.5 mm 2

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