# EE 542 Antennas & Propagation for Wireless Communications

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EE 542 Antennas & Propagation for Wireless Communications
Topic 3 - Basic EM Theory and Plane Waves

Outline EM Theory Concepts Maxwell’s Equations
Notation Differential Form Integral Form Phasor Form Wave Equation and Solution (lossless, unbounded, homogeneous medium) Derivation of Wave Equation Solution to the Wave Equation – Separation of Variables Plane waves O. Kilic EE542

EM Theory Concept The fundamental concept of em theory is that a current at a point in space is capable of inducing potential and hence currents at another point far away. J E, H O. Kilic EE542

Introduction to EM Theory
The existence of propagating em waves can be predicted as a direct consequence of Maxwell’s equations. These equations satisfy the relationship between the vector electric field, E and vector magnetic field, H in time and space in a given medium. Both E and H are vector functions of space and time; i.e. E (x,y,z;t), H (x,y,z;t.) O. Kilic EE542

What is an Electromagnetic Field?
The electric and magnetic fields were originally introduced by means of the force equation. In Coulomb’s experiments forces acting between localized charges were observed. There, it is found useful to introduce E as the force per unit charge. Similarly, in Ampere’s experiments the mutual forces of current carrying loops were studied. B is defined as force per unit current. O. Kilic EE542

Why not use just force? Although E and B appear as convenient replacements for forces produced by distributions of charge and current, they have other important aspects. First, their introduction decouples conceptually the sources from the test bodies experiencing em forces. If the fields E and B from two source distributions are the same at a given point in space, the force acting on a test charge will be the same regardless of how different the sources are. This gives E and B meaning in their own right. Also, em fields can exist in regions of space where there are no sources. O. Kilic EE542

Maxwell’s Equations Maxwell's equations give expressions for electric and magnetic fields everywhere in space provided that all charge and current sources are defined. They represent one of the most elegant and concise ways to state the fundamentals of electricity and magnetism. These set of equations describe the relationship between the electric and magnetic fields and sources in the medium. Because of their concise statement, they embody a high level of mathematical sophistication. O. Kilic EE542

Notation: (Time and Position Dependent Field Vectors)
E (x,y,z;t) Electric field intensity (Volts/m) H (x,y,z;t) Magnetic field intensity (Amperes/m) D (x,y,z;t) Electric flux density (Coulombs/m2) B (x,y,z;t) Magnetic flux density (Webers/m2, Tesla) O. Kilic EE542

Notation: Sources and Medium
J (x,y,z;t) Electric current density (Amperes/m2) Jd (x,y,z;t) Displacement current density (Amperes/m2) re Electric charge density (Coulombs/m3) e er Permittivity of the medium (Farad/m) Relative permittivity (with respect to free space eo) m Permeability of the medium (Henry/m) Relative permittivity (with respect to free space mo) s Conductivity of the medium (Siemens/m) O. Kilic EE542

Maxwell’s Equations – Physical Laws
Faraday’s Law  Changes in magnetic field induce voltage. Ampere’s Law  Allows us to write all the possible ways that electric currents can make magnetic field. Magnetic field in space around an electric current is proportional to the current source. Gauss’ Law for Electricity The electric flux out of any closed surface is proportional to the total charge enclosed within the surface. Gauss’ Law for Magnetism The net magnetic flux out of any closed surface is zero. O. Kilic EE542

Differential Form of Maxwell’s Equations
Faraday’s Law: (1) Ampere’s Law: (2) Gauss’ Law: (3) (4) O. Kilic EE542

Constitutive Relations
Constitutive relations provide information about the environment in which electromagnetic fields occur; e.g. free space, water, etc. permittivity (5) permeability (6) Free space values. O. Kilic EE542

Time Harmonic Representation - Phasor Form
In a source free ( ) and lossless ( ) medium characterized by permeability m and permittivity e, Maxwell’s equations can be written as: O. Kilic EE542

Examples of del Operations
The following examples will show how to take divergence and curl of vector functions O. Kilic EE542

Example 1 O. Kilic EE542

Solution 1 O. Kilic EE542

Example 2 Calculate the magnetic field for the electric field given below. Is this electric field realizable? O. Kilic EE542

Solution O. Kilic EE542

Solution continued O. Kilic EE542

Solution continued To be realizable, the fields must satisfy Maxwell’s equations! O. Kilic EE542

Solution Continued These fields are NOT realizable. They do not form em fields. O. Kilic EE542

Time Harmonic Fields We will now assume time harmonic fields; i.e. fields at a single frequency. We will assume that all field vectors vary sinusoidally with time, at an angular frequency w; i.e. O. Kilic EE542

Time Harmonics and Phasor Notation
Using Euler’s identity The time harmonic fields can be written as Phasor notation O. Kilic EE542

Phasor Form Information on amplitude, direction and phase
Note that the E and H vectors are now complex and are known as phasors O. Kilic EE542

Time Harmonic Fields in Maxwell’s Equations
With the phasor notation, the time derivative in Maxwell’s equations becomes a factor of jw: O. Kilic EE542

Maxwell’s Equations in Phasor Form (1)
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Maxwell’s Equations in Phasor Form (2)
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Phasor Form of Maxwell’s Equations (3)
Maxwell’s equations can thus be written in phasor form as: Phasor form is dependent on position only. Time dependence is removed. O. Kilic EE542

Examples on Phasor Form
Determine the phasor form of the following sinusoidal functions: f(x,t)=(5x+3) cos(wt + 30) g(x,z,t) = (3x+z) sin(wt) h(y,z,t) = (2y+5)4z sin(wt + 45) V(t) = 0.5 cos(kz-wt) O. Kilic EE542

Solutions a) O. Kilic EE542

Solutions b) O. Kilic EE542

Solution c) O. Kilic EE542

Solution d) O. Kilic EE542

Example Find the phasor notation of the following vector:
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Solution O. Kilic EE542

Example Show that the following electric field satisfies Maxwell’s equations. O. Kilic EE542

Solution O. Kilic EE542

The Wave Equation (1) If we take the curl of Maxwell’s first equation:
Using the vector identity: And assuming a source free, i.e. and lossless; i.e. medium: O. Kilic EE542

The Wave Equation (2) Define k, which will be known as wave number:
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Wave Equation in Cartesian Coordinates
where O. Kilic EE542

Laplacian O. Kilic EE542

Scalar Form of Maxwell’s Equations
Let the electric field vary with x only. and consider only one component of the field; i.e. f(x). O. Kilic EE542

Possible Solutions to the Scalar Wave Equation
Energy is transported from one point to the other Standing wave solutions are appropriate for bounded propagation such as wave guides. When waves travel in unbounded medium, traveling wave solution is more appropriate. O. Kilic EE542

The Traveling Wave The phasor form of the fields is a mathematical representation. The measurable fields are represented in the time domain. Let the solution to the a-component of the electric field be: Then Traveling in +x direction O. Kilic EE542

Traveling Wave As time increases, the wave moves along +x direction
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Standing Wave Then, in time domain: O. Kilic EE542

Standing Wave Stationary nulls and peaks in space as time passes.
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To summarize We have shown that Maxwell’s equations describe how electromagnetic energy travels in a medium The E and H fields satisfy the “wave equation”. The solution to the wave equation can be in various forms, depending on the medium characteristics O. Kilic EE542

The Plane Wave Concept Plane waves constitute a special set of E and H field components such that E and H are always perpendicular to each other and to the direction of propagation. A special case of plane waves is uniform plane waves where E and H have a constant magnitude in the plane that contains them. O. Kilic EE542

Plane Wave Characteristics
amplitude Frequency (rad/sec) phase polarization Wave number, depends on the medium characteristics Direction of propagation amplitude phase O. Kilic EE542

Plane Waves in Phasor Form
polarization Complex amplitude Position dependence O. Kilic EE542

Example 1 Assume that the E field lies along the x-axis (i.e. x-polarized) and is traveling along the z-direction. wave number We derive the solution for the H field from the E field using Maxwell’s equation #1: H E Intrinsic impedance; 377 W for free space Note the I = V/R analogy in circuit theory. O. Kilic EE542

Example 1 (2 of 4) direction of propagation z y E, H plane x
E and H fields are not functions of x and y, because they lie on x-y plane O. Kilic EE542

Example 1 (3 of 4) In time domain: phase term
*** The constant phase term j is the angle of the complex number Eo O. Kilic EE542

Example 1 (4 of 4) Wavelength: period in space kl = 2p O. Kilic EE542

Velocity of Propagation (1/3)
We observe that the fields progress with time. Imagine that we ride along with the wave. At what velocity shall we move in order to keep up with the wave??? O. Kilic EE542

Velocity of Propagation (2/3)
E field as a function of different times Constant phase points kz O. Kilic EE542

Velocity of Propagation (3/3)
In free space: Note that the velocity is independent of the frequency of the wave, but a function of the medium properties. O. Kilic EE542

Example 2 A uniform em wave is traveling at an angle q with respect to the z-axis as shown below. The E field is in the y-direction. What is the direction of the H field? x z y k q E O. Kilic EE542

Solution: Example 2 The E field is along y x
z y k q The direction of propagation is the unit vector The E field is along y E Because E, H and the direction of propagation are perpendicular to each other, H lies on x-z plane. It should be in the direction parallel to: O. Kilic EE542

Example 3 Write the expression for an x-polarized electric field that propagates in +z direction at a frequency of 3 GHz in free space with unit amplitude and 60o phase. + z-direction W = 2pf = 2p*3*109 =1 x 60o O. Kilic EE542

Solution 3 + z-direction W = 2pf = 2p*3*109 =1 x 60o O. Kilic EE542

Example 4 If the electric field intensity of a uniform plane wave in a dielectric medium where e = eoer and m = mo is given by: Determine: The direction of propagation and frequency The velocity The dielectric constant (i.e. permittivity) The wavelength O. Kilic EE542

Solution: Example 4 (1/2) +y direction; w = 2pf = 109 Velocity:
Permittivity: O. Kilic EE542

Solution: Example 4 (2/2) 4. Wavelength: m O. Kilic EE542

Example 5 Assume that a plane wave propagates along +z-direction in a boundless and a source free, dielectric medium. If the electric field is given by: Calculate the magnetic field, H. O. Kilic EE542

Example 5 - observations
Note that the phasor form is being used in the notation; i.e. time dependence is suppressed. We observe that the direction of propagation is along +z-axis. O. Kilic EE542

Solution: Example 5 (1/2) E k Intrinsic impedance, I = V/R
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Solution: Example 5 (2/2) E, H and the direction of propagation are orthogonal to each other. Amplitudes of E and H are related to each other through the intrinsic impedance of the medium. Note that the free space intrinsic impedance is 377W. O. Kilic EE542

Example 6 Sketch the motion of the tip of the vector A(t) as a function of time. O. Kilic EE542

Solution: Example 6 (1/2) O. Kilic EE542

Solution: Example 6 (2/2) y wt = 90o wt = 180o x wt = 0 wt = 270o
The vector A(t) rotates clockwise wrt z-axis. The tip traces a circle of radius equal to unity with angular frequency w. O. Kilic EE542

Polarization The alignment of the electric field vector of a plane wave relative to the direction of propagation defines the polarization. Three types: Linear Circular Elliptical (most general form) Polarization is the locus of the tip of the electric field at a given point as a function of time. O. Kilic EE542

Linear Polarization y Electric field oscillates along a straight line as a function of time Example: wire antennas E x y E x O. Kilic EE542

Example 7 For z = 0 (any position value is fine) y - Eo Eo x t = p t = 0 Linear Polarization: The tip of the E field always stays on x-axis. It oscillates between ±Eo O. Kilic EE542

Example 8 Linear Polarization Exo=1 Eyo=2
Let z = 0 (any position is fine) y 2 t = 0 Linear Polarization x 1 t = p/2 O. Kilic EE542

Circular Polarization
y RHCP Electric field traces a circle as a function of time. Generated by two linear components that are 90o out of phase. Most satellite antennas are circularly polarized. x y LHCP x O. Kilic EE542

Example 7 Exo=1 Eyo=1 Let z= 0 y RHCP t=p/2w t=p/w x t=0 t=3p/2w
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Elliptical Polarization
y x RH This is the most general form Linear and circular cases are special forms of elliptical polarization Example: log spiral antennas y x LH O. Kilic EE542

Example 8 Ey Ex Linear when Circular when
Elliptical if no special condition is met. O. Kilic EE542

Example 9 Determine the polarization of this wave. O. Kilic EE542

Solution: Example 9 (1/2) Note that the field is given in phasor form. We would like to see the trace of the tip of the E field as a function of time. Therefore we need to convert the phasor form to time domain. O. Kilic EE542

Solution: Example 9 (2/2) Elliptical polarization Let z=0
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Example 10 Find the polarization of the following fields: a) b) c)
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Solution: Example 10 (1/4) a)
Observe that orthogonal components have same amplitude but 90o phase difference. Circular Polarization y t=0 Let kz=0 x z t=p/2w t=3p/2w RHCP t=p/w O. Kilic EE542

Solution: Example 10 (2/4) b)
Observe that orthogonal components have same amplitude but 90o phase difference. Circular Polarization z t=+p/4w Let kx=0 t=3p/4w y x t=-p/4w RHCP t=5p/4w O. Kilic EE542

Solution: Example 10 (3/4) c)
Observe that orthogonal components have different amplitudes and are out of phase. Elliptical Polarization x t=-a/w Left Hand Let ky=0 z y t=+b/w O. Kilic EE542

Solution: Example 10 (4/4) d)
Observe that orthogonal components are in phase. Linear Polarization y x z O. Kilic EE542

Coherence and Polarization
In the definition of linear, circular and elliptical polarization, we considered only completely polarized plane waves. Natural radiation received by an anatenna operating at a frequency w, with a narrow bandwidth, Dw would be quasi-monochromatic plane wave. The received signal can be treated as a single frequency plane wave whose amplitude and phase are slowly varying functions of time. O. Kilic EE542

Quasi-Monochromatic Waves
amplitude and phase are slowly varying functions of time O. Kilic EE542

Degree of Coherence where <….> denotes the time average.
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Degree of Coherence – Plane Waves
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Unpolarized Waves An em wave can be unpolarized. For example sunlight or lamp light. Other terminology: randomly polarized, incoherent. A wave containing many linearly polarized waves with the polarization randomly oriented in space. A wave can also be partially polarized; such as sky light or light reflected from the surface of an object; i.e. glare. O. Kilic EE542

Poynting Vector As we have seen, a uniform plane wave carries em power. The power density is obtained from the Poynting vector. The direction of the Poynting vector is in the direction of wave propagation. O. Kilic EE542

Poynting Vector O. Kilic EE542

Example 11 Calculate the time average power density for the em wave if the electric field is given by: O. Kilic EE542

Solution: Example 11 (1/2) O. Kilic EE542

Solution: Example 11 (2/2) O. Kilic EE542

Plane Waves in Lossy Media
Finite conductivity, s results in loss Ohm’s Law applies: Conduction current Conductivity, Siemens/m O. Kilic EE542

Complex Permittivity From Ampere’s Law in phasor form: O. Kilic EE542

Wave Equation for Lossy Media
Wave number: Loss tangent, d Attenuation constant Phase constant O. Kilic EE542

Example 12 (1/2) Plane wave propagation in lossy media: complex number
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Example 12 (2/2) attenuation propagation
Plane wave is traveling along +z-direction and dissipating as it moves. O. Kilic EE542

Field Attenuation in Lossy Medium
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Attenuation and Skin Depth
Attenuation coefficient, a, depends on the conductivity, permittivity and frequency. Skin depth, d is a measure of how far em wave can penetrate a lossy medium O. Kilic EE542

Lossy Media O. Kilic EE542

Example 13 Calculate the attenuation rate and skin depth of earth for a uniform plane wave of 10 MHz. Assume the following properties for earth: m = mo e = 4eo s = 10-4 O. Kilic EE542

Solution: Example 13 First we check if we can use approximate relations. Slightly conducting O. Kilic EE542

References Applied Electromagnetism, Liang Chi Shen, Jin Au Kong, PWS O. Kilic EE542

Homework Assignments Due 9/25/08 O. Kilic EE542

Homework 3.1 The magnetic field of a uniform plane wave traveling in free space is given by What is the direction of propagation? What is the wave number, k in terms of permittivity, eo and permeability, mo? Determine the electric field, E. O. Kilic EE542

Homework 3.2 Find the polarization state of the following plane wave:
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Homework 3.3 How far must a plane wave of frequency 60 GHz propagate in order for the phase of the wave to be retarded by 180o in a lossless medium with mr =1 and er = 3.5? O. Kilic EE542

Solution Homework 3.1 What is the direction of propagation? Ans: -z
What is the wave number, k in terms of permittivity, eo and permeability, mo? Ans: free space  Determine the electric field, E. E H k O. Kilic EE542

Solution: Homework 3.2 Observe that orthogonal components are in phase. Linear Polarization y x z O. Kilic EE542

Solution 3.3 (1/2) Wavelength: period in space kl = 2p O. Kilic EE542

Solution 3.3 (2/2) O. Kilic EE542