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**Regression Inferential Methods**

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Height Weight Suppose you took many samples of the same size from this population & calculated the LSRL for each. Using the slope from each of these LSRLs – we can create a sampling distribution for the slope of the true LSRL. What is the standard deviation of the sampling distribution? What is the mean of the sampling distribution equal? What shape will this distribution have? b b b b b b b mb = b

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**What would you expect for other heights?**

Weight What would you expect for other heights? How much would an adult female weigh if she were 5 feet tall? This distribution is normally distributed. (we hope) She could weigh varying amounts – in other words, there is a distribution of weights for adult females who are 5 feet tall. What about the standard deviations of all these normal distributions? We want the standard deviations of all these normal distributions to be the same. Where would you expect the TRUE LSRL to be?

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Regression Model The mean response my has a straight-line relationship with x: Where: slope b and intercept a are unknown parameters For any fixed value of x, the response y varies according to a normal distribution. Repeated responses of y are independent of each other. The standard deviation of y (sy) is the same for all values of x. (sy is also an unknown parameter)

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**What distribution does their weight have?**

Person # Ht Wt 1 64 130 10 175 15 150 19 125 21 145 40 186 47 121 60 137 63 143 68 120 70 112 78 108 83 160 Suppose we look at part of a population of adult women. These women are all 64 inches tall. What distribution does their weight have?

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**The slope b of the LSRL is an unbiased estimator of the true slope b. **

We use to estimate The slope b of the LSRL is an unbiased estimator of the true slope b. The intercept a of the LSRL is an unbiased estimator of the true intercept a. The standard error s is an unbiased estimator of the true standard deviation of y (sy). Note: df = n-2

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**Let’s review the regression model!**

x & y have a linear relationship with the true LSRL going through the my sy is the same for each x-value. For a given x-value, the responses (y) are normally distributed

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**What is the slope of a horizontal line?**

Height Weight Suppose the LSRL has a horizontal line –would height be useful in predicting weight? A slope of zero – means that there is NO relationship between x & y!

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**Assumptions for inference on slope**

The true relationship is Linear Check the scatter plot & residual plot The observations are Independent and random Check that you have an SRS For any fixed value of x, the response y varies Normally about the true regression line. Check a histogram or boxplot of residuals Equal variance about regression line. The standard deviation of the response is constant. L I N E

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**Hypotheses Be sure to define b! H0: b = 0 1 Ha: b > 0 Ha: b < 0**

This implies that there is no relationship between x & y Or that x should not be used to predict y What would the slope equal if there were a perfect relationship between x & y? H0: b = 0 Ha: b > 0 Ha: b < 0 Ha: b ≠ 0 1 Be sure to define b!

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**Because there are two unknowns a & b**

Formulas: Confidence Interval: Hypothesis test: df = n -2 Because there are two unknowns a & b

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**Body fat = -27.376 + 0.250 weight r = 0.697 r2 = 0.485**

Example: It is difficult to accurately determine a person’s body fat percentage without immersing him or her in water. Researchers hoping to find ways to make a good estimate immersed 20 male subjects, and then measured their weights. Find the LSRL, correlation coefficient, and coefficient of determination. Body fat = weight r = 0.697 r2 = 0.485

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**b) Explain the meaning of slope in the context of the problem.**

For each increase of 1 pound in weight, there is an approximate increase in .25 percent body fat. c) Explain the meaning of the coefficient of determination in context. Approximately 48.5% of the variation in body fat can be explained by the regression of body fat on weight.

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**a = -27.376 b = 0.25 s = 7.049 d) Estimate a, b, and s.**

e) Create a scatter plot and residual plot for the data. Weight Body fat Weight Residuals

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**f) Is there sufficient evidence that weight can be used to predict body fat?**

Assumptions: Scatterplot and residual plot shows Linear association. Have an Independent SRS of male subjects Since the boxplot of residual is approximately symmetrical, the responses are approximately Normally distributed. Since the points are evenly spaced across the LSRL on the scatterplot, sy is approximately Equal for all values of weight H0: b = 0 Where b is the true slope of the LSRL of weight Ha: b ≠ 0 & body fat Since the p-value < a, I reject H0. There is sufficient evidence to suggest that weight can be used to predict body fat.

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**Be sure to show all graphs!**

g) Give a 95% confidence interval for the true slope of the LSRL. Assumptions: Scatter plot and residual plot show LINEAR association Have an INDEPENDENT SRS of male subjects Since the boxplot of residualS is approximately symmetrical, the responses are approximately NORMALLY distributed. Since the points are evenly spaced across the LSRL on the scatterplot, sy is approximately EQUAL for all values of weight We are 95% confident that the true slope of the LSRL of weight & body fat is between 0.12 and 0.38. Be sure to show all graphs!

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**What does “s” represent (in context)?**

h) Here is the computer-generated result from the data: Sample size: 20 R-square = 48.5% s = df? What does “s” represent (in context)? Parameter Estimate Std. Err. Intercept Weight Correlation coeficient? Be sure to write as decimal first! What does this number represent? What do these numbers represent?

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Chapter 13 Lesson 13.2a Simple Linear Regression and Correlation: Inferential Methods 13.2: Inferences About the Slope of the Population Regression Line.

Chapter 13 Lesson 13.2a Simple Linear Regression and Correlation: Inferential Methods 13.2: Inferences About the Slope of the Population Regression Line.

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