Presentation on theme: "Course Title: Strength of Materials (CVE 202)"— Presentation transcript:
1Course Title: Strength of Materials (CVE 202) Course Lecturer: Engr. F. M. AlayakiCivil Engineering Department, College of Engineering, University of Agriculture Abeokuta, NigeriaCourse Unit: 2 Contact Time: 2 Hours Laboratory Time: 1 Hour
2Course ContentDirect Stress: Hooke’s experiment. Axially loaded bar, Tensile and compressive stresses. Strain; tensile and compressive strains. Stress-stain curves for ductile and brittle materials. Modulus of elasticity. Mechanical properties of materials; elastic limits, proportional limit, yield points, ultimate strength. Modulus of toughness. Percentage reduction in areas. Percentage elongation.
3Principal stress: Definition, deductions from Mohr’s circle Principal stress: Definition, deductions from Mohr’s circle. Mohr’s circle method of determining stress and strain. Working stress, proof stress, Poisson’s ratio, modulus of rigidity. Factors of safety. Lateral stresses and strains. Bars of varying cross sections compound bars under stress and strain. Temperature stresses.
4Torsion: effects of torsion. Twisting moment Torsion: effects of torsion. Twisting moment. Polar second moments of area. Torsional shearing stresses and strain. Modulus of elasticity in shear. Angle of twist. Rupture.Shearing force and bending moments: Simply supported beam. Loading forces and moments in beams. Shear and moment equations. Shear force and bending moment diagrams.
5Typical Questions1. The following data were recorded during a tensile steel test:Diameter of bar = 20mmDistance between gauge points = 200mmElongation due to load of 50KN = 0.18Load at yield point = 79KNFailing or ultimate load = 127KNCalculate in N/mm2the stress at yield point, (b) the ultimate stress, (c) the modulus of elasticity of the steel2. ( a ) Define the following terms:Component of ForcesResultantEquilibrantMoment of ForcesCentroid of a Body( b ) i Define the terms shear force and bending moment.ii What do you understand by the term ‘point of contraflexure’?
6( c ) Using simple sketches show the following types of beams Simply supported beam with a point load.Simply supported beam with Uniformly Distributed Load (UDL).3. Three separate members of steel, copper and brass are of identical dimensions and are equally loaded. Young’s moduli for the materials are: steel, 210,000N/mm2; copper, 100,000N/mm2; brass, 95,000N/mm2. If the steel member stretches 0.13mm, calculate the amount of elongation in the copper and brass members.4. (a) Define the terms shear force and bending moment.(b) What do you understand by the term ‘point of contraflexure’?(c) Using simple sketches show the following types of beamsOverhanging beam with UDL.Cantilever beam with point load at its end.Simply supported beam with uniformly varying load.
75. A cantilever beam AB 1.5m long is loaded with a UDL of 2 KN/m and a point load of 3KN as shown in fig. 1. Draw the shear force and bending moment diagram for the cantilever beam. Indicate the positions and values of the following.Point of zero shear force.Maximum shear force.Maximum bending moment.6 (a) Derive from first principle the formula for the moment of inertia of a rectangular section.(b) Determine the moment of inertia Ixx of the section shown in fig. 2.7. Define stress, strain, and elasticity. Derive a relation between stress and strain of an elastic body.8. Two wires, one of steel and the other of copper, are of the same length and are subjected to the same tension. If the diameter of the copper wire is 2mm, find the diameter of the steel wire, if they are elongated by the same amount. Take E for steel as 200 x 103 N/mm2 and that for copper as 100 x 103 N/mm2.
83 KN 2KN/m A B 0.25m 1.00m 0.25m Fig. 1 24mm 24mm 300mm Fig. 2 200mm