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Today in Precalculus Go over homework Notes: Simulating Projectile Motion Day 2 Homework.

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Presentation on theme: "Today in Precalculus Go over homework Notes: Simulating Projectile Motion Day 2 Homework."— Presentation transcript:

1 Today in Precalculus Go over homework Notes: Simulating Projectile Motion Day 2 Homework

2 Objects going straight up or down A baseball is hit straight up from a height of 3ft with an initial velocity of 40ft/sec. The parametric equations that model the height of the ball as a function of time t is: x = t y = -16t t + 3 What is the height of the ball after 0.5 seconds? y=-16(.5) (.5) + 3=19ft What is the maximum height of the ball and how long does it take to reach that height? using trace, at 1.25seconds the ball reaches 28ft.

3 Hitting objects on the ground Lucy and Ethel are playing yards darts. They are launching the dart 12 ft from the front edge of a circular target of radius 18in on the ground. If Lucy throws the dart directly at the target, and releases it 2.5ft above the ground with an initial velocity of 25ft/sec at a 75° angle, will the dart hit the target? x = (25cos75°)t y = -16t 2 + (25sin75°)t Use Quadratic formula, find when y=0 At about 1.607sec the dart is feet from Lucy, which is = 1.602ft short of the target. How far can the dart travel and be inside the target? 12 to 15 feet.

4 Hitting Moving Objects The path of the dart is: x=(125cos15°)t y= -16t 2 + (125sin15°)t +3.5 The path of the monkey is: x = 150 (stays a constant 150 ft from vet) y=-16t (no initial velocity, since the monkey just lets go of the branch) t:0, 2 x:0, 200 (greater than the distance between vet and monkey) y:0, 40 (greater than the height of the monkey)

5 Hitting Moving Objects By how much does the dart miss the monkey? 150=(125cos15°)t t=1.242sec Dart:y= -16(1.242) 2 + (125sin15°)(1.242) +3.5 y = ft Monkey:y = -16(1.242) y= ft So the dart misses the monkey by =13.682ft.

6 Homework Pg 531: 39,40, 47,48


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