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Monkey-drop demo

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. 120 m Question: How high is the table?

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. Consider the rabbit. 30 m/s

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. When will the rabbit be 120 m from the table? 30 m/s

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. When will the billiard ball hit the ground? 30 m/s

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. Now, consider a blue ball that is dropped as the billiard ball leaves the table. 0 m/s

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. When will the blue ball hit the ground? 0 m/s

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. How high is the table?

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An ugly giant rolls a billiard ball with uniform velocity 30 m/s across the top of his desk. The ball rolls off the edge of the desk and lands on the floor 120 m from the edge of the desk. At what velocity will it hit the ground?

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Sample problem: A diver springs upward from a board that is three meters above the water. At the instant she contacts the water her speed is 9 m/s and her body makes an angle of 75 with respect to the horizontal surface of the water. Determine her initial velocity, magnitude and direction.

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+y +x x - party - part x = a x = v xo = v xf = t = y = a y = v yo = v yf = t = 3 m - 3 m 10 m/s/s - 10 m/s/s0 - 9 m/s sin 75 + 9 m/s cos 75 = + 2.3 m/s= - 8.7 m/s + 2.3 m/s v yf 2 = v yo 2 + 2 a y y (8.7) 2 = v yo 2 + 2 (-10)(-3) v yo 2 = 15.7 v yo = 4 m/s Who cares? ?? + 4 m/s 9 m/s ? 75

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