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Published bySabrina Samples Modified about 1 year ago

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Pamela Leutwyler

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9 goes into 36 four times with remainder = 9

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9 goes into 99 eleven times with remainder = = 9

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9).

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9). 9 goes into 29 three times with remainder = = 2

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9). 9 goes into 29 three times with remainder = = 2 9 goes into 49 five times with remainder = = 4

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9). 9 goes into 29 three times with remainder = = 2 9 goes into 49 five times with remainder = = 4 9 goes into 253 twenty eight times with remainder = = 1

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9). 9 goes into 29 three times with remainder = = 2 9 goes into 49 five times with remainder = = 4 9 goes into 253 twenty eight times with remainder = = 1 The sum of the digits of any whole number = the remainder when that number is divided by 9. If the sum of the digits is > 9, add the digits again.

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9 goes into 36 four times with remainder = 9 9 goes into 99 eleven times with remainder = = 9 The sum of the digits of a multiple of 9 is 9 (or a multiple of 9). 9 goes into 29 three times with remainder = = 2 9 goes into 49 five times with remainder = = 4 9 goes into 253 twenty eight times with remainder = = 1 The sum of the digits of any whole number = the remainder when that number is divided by = 2x x = 2x(99+1) + 5x(9+1) + 3 = 2x99 + 2x1 + 5x9 + 5x1 + 3

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The sum of the digits of any whole number = the remainder when that number is divided by 9. When dividing by 9, getting a remainder of 9 is the same as getting a remainder of 0.

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The sum of the digits of any whole number = the remainder when that number is divided by 9. When dividing by 9, getting a remainder of 9 is the same as getting a remainder of 0. For example: You could say that 9 goes into 27 two times with a remainder of 9 or You could say that 9 goes into 27 three times with a remainder of 0

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Casting out nines an algorithm for checking computation

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Is the following sum correct?

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In theory, the sum of the remainders should equal the remainder when the sum is divided by =17 and 1+7 = 8

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Is the following sum correct? In theory, the sum of the remainders should equal the remainder when the sum is divided by Shorten the process: All of these numbers are added so there is no need to separate them Also a remainder of 9 is the same as a remainder of 0. Where you see 9, cross it out.

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Is the following sum correct? Cast out NINES

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Is the following sum correct? Cast out NINES

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Is the following sum correct? Cast out NINES

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Is the following sum correct? Cast out NINES

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Is the following sum correct? Cast out NINES The sum is probably correct. There is 1 chance in 9 that the numbers would match by chance. If the numbers do not match then you have found an error.

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