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EXAMPLE 3 COMPACT DISCS You are wrapping a stack of 20 compact discs using a shrink wrap. Each disc is cylindrical with height 1.2 millimeters and radius 60 millimeters. What is the minimum amount of shrink wrap needed to cover the stack of 20 discs? Find the height of a cylinder

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EXAMPLE 3 SOLUTION The 20 discs are stacked, so the height of the stack will be 20(1.2) = 24 mm. The radius is 60 millimeters. The minimum amount of shrink wrap needed will be equal to the surface area of the stack of discs. S = 2πr 2 + 2πrh Surface area of a cylinder. = 2π(60) 2 + 2π(60)(24) Substitute known values. ≈ 31,667 Use a calculator. You will need at least 31,667 square millimeters, or about 317 square centimeters of shrink wrap. ANSWER Find the height of a cylinder

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EXAMPLE 4 SOLUTION Substitute known values in the formula for the surface area of a right cylinder and solve for the height h. Find the height of the right cylinder shown, which has a surface area of 157.08 square meters. S = 2πr 2 + 2πrh Surface area of a cylinder. Find the height of a cylinder

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EXAMPLE 4 157.08 = 2π(2.5) 2 + 2π(2.5)h Substitute known values. 157.08 = 12.5π + 5πh Simplify. 157.08 – 12.5π = 5πh Subtract 12.5π from each side. 117.81 ≈ 5πh Simplify. Use a calculator. 7.5 ≈ h Divide each side by 5π. Find the height of a cylinder The height of the cylinder is about 7.5 meters. ANSWER

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GUIDED PRACTICE for Examples 3 and 4 3. Find the surface area of a right cylinder with height 18 centimeters and radius 10 centimeters. Round your answer to two decimal places. 1759.29 cm 2 ANSWER

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GUIDED PRACTICE for Examples 3 and 4 4. Find the radius of a right cylinder with height 5 feet and surface area 208π square feet. The radius of cylinder is 8 feet. ANSWER

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EXAMPLE 4 Solve a multi-step problem

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