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**MAGNIFICATIONS & SCALES**

SI UNITS: 1 meter (m)= 1m 1 millimeter (mm) = 10-3m 1 micrometer (µm) = 10-6m 1 nanometer (nm) = 10-9m

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**OR OR 1. (a) Determine the magnification of the string of**

Thiomargarita cells in Figure 11, if the scale bar represents 0.2 mm . (b) Determine the width of the string of cells. 0.2mm = actual size (X) mm X 50mm size of object= 0.5mm 20mm mm mm Magnification = image size mm = 100x actual size mm OR a) Magnification = image size (scale) mm = 100x actual size (scale) mm b) mm = actual size (X) mm X 25mm width of object= 0.25mm 20mm mm mm OR b) Magnification = image size = 25mm = 25/ = mm actual size X

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**2. In Figure 12 the actual length of the mitochondrion is 8µm.**

(a) Determine the magnification of this electron micrograph. (b) Calculate how long a 5 µm scale bar would be on this electron micrograph. (c) Determine the width of the mitochondrion. a) Magnification = image size = mm µm = 7875x ~ 8000x actual size µm µm 8000 = X__ x 5 = 40,000µm = 40mm 5µm c) Depending on your measurement location the image width is b/w 20mm & 23mm. We will use 20mm. magnification (8000) = 20,000 µm = ,000 / = 2.5µm X

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**3. The magnification of the human cheek cells from a**

compound microscope (Figure 13) is 2000X. (a) Calculate how long a 20 µm scale bar would be on the image. (b) Determine the average length of the cheek cells Magnification (2000) = ___X___ = ,000µm = 40mm 20µm Length ~ 20mm = ,000µm ,000/ = 10µm X

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**4.(a) Using the width of the hen’s egg as a guide, estimate**

the actual length of the ostrich egg (Figure 14). (b) Estimate the magnification of the image. Actual hen egg width = 43mm Image hen egg width = 15mm Image ostrich egg = 45mm long a) Ostrich egg length = 43mm x 45mm = 43 x 3 = 129mm 15mm b) Magnification = image = 15mm = X actual mm

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