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Published byMya Greenland Modified about 1 year ago

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MAGNIFICATIONS & SCALES SI UNITS: 1 meter (m)= 1m 1 millimeter (mm) = m 1 micrometer (µm) = m 1 nanometer (nm) = m

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1. (a) Determine the magnification of the string of Thiomargarita cells in Figure 11, if the scale bar represents 0.2 mm. (b) Determine the width of the string of cells. a)0.2mm = actual size (X) 0.2mm X 50mm size of object= 0.5mm 20mm 50 mm 20mm Magnification = image size 50mm = 100x actual size 0.5mm b) 0.2mm = actual size (X) 0.2mm X 25mm width of object= 0.25mm 20mm 25 mm 20mm a) Magnification = image size (scale) 20mm = 100x actual size (scale) 0.2mm OR b) Magnification = image size 100 = 25mm = 25/100 = 0.25mm actual size X

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2. In Figure 12 the actual length of the mitochondrion is 8µm. (a) Determine the magnification of this electron micrograph. (b) Calculate how long a 5 µ m scale bar would be on this electron micrograph. (c) Determine the width of the mitochondrion. a) Magnification = image size = 63mm 63000µm = 7875x ~ 8000x actual size 8µm 8µm b)8000 = X__ 8000 x 5 = 40,000µm = 40mm 5µm c) Depending on your measurement location the image width is b/w 20mm & 23mm. We will use 20mm. magnification (8000) = 20,000 µm = 20,000 / = 2.5µm X

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3. The magnification of the human cheek cells from a compound microscope (Figure 13) is 2000X. (a)Calculate how long a 20 µm scale bar would be on the image. (b)Determine the average length of the cheek cells a)Magnification (2000) = ___X___ = 40,000µm = 40mm 20µm b)Length ~ 20mm 2000 = 20,000µm 20,000/2000 = 10µm X

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4.(a) Using the width of the hen’s egg as a guide, estimate the actual length of the ostrich egg (Figure 14). (b) Estimate the magnification of the image. Actual hen egg width = 43mm Image hen egg width = 15mm Image ostrich egg = 45mm long a) Ostrich egg length = 43mm x 45mm = 43 x 3 = 129mm 15mm b) Magnification = image = 15mm = 0.33X actual 43mm

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