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Published byFatima Trees Modified about 1 year ago

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E W Work and Energy Work Done By a Constant Force Work is defined as the product of the constant force and the distance through which the point of application moves in the direction of the force. s metre F Work done = F s joules (J) s F Work done = s×Fcos J

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E W Work and Energy Work Done Against Gravity If a body of mass m is to raised vertically at a constant speed, then a force of mg N must be applied to the body. If the body is raised a distance h metres, then the work done against gravity = mgh J. m F = mg mg constant speed h

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E W Work and Energy Energy The energy of a body is its capacity for doing work. The Kinetic energy (KE) of a body is the energy it possesses by virtue of its motion. It is measured by the amount of work that the body does in coming to rest. The Potential energy (PE) of a body is the energy it possesses by virtue of its position. It is measured by the amount of work that the body would do in moving from its actual position to some standard position.

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E W Work and Energy The work – energy principle If a constant force acts on an object over a certain distance, the work done by the force is equal to the gain in the kinetic energy of the object. Work Done Against a Resistance = R Distance moved Work Done by a force perpendicular to the direction of motion is zero.

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E W Work and Energy Example 1 A car and driver have total mass of 1200 kg. The gains speed from 5 ms -1 to 10 ms -1 with constant acceleration over a horizontal distance 200 m. Calculate the driving force. Therefore F = 225 N

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E W Work and Energy Example 2 A Force 20 N pushes a body of mass 8 kg in a straight line across a horizontal smooth surface from A to B, increasing its speed from 4 ms -1 to 10 ms -1. Find (i) the gain in KE (ii) the work done by the force (iii) the distance from A to B. (iii) F s = 20 s = 336 s = 16.8 m

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E W Work and Energy Example 4 A car of mass 800 kg accelerates from 8 ms -1 to 20 ms -1 over a distance of 100 metres. Calculate the work done by the car if the road is (i) rising at 6 0 to the horizontal (ii) dropping at 5 0 = 216 kJ = 66.1 kJ

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E W Work and Energy Example 5 A tractor of mass 600 kg pulls a trailer of mass 200 kg up a rough road inclined 10 0 to the horizontal. The resistance to the motion is 5 N per kg. Calculate the work done by the tractor engine, given that the vehicle travels at a constant speed of 1.5 ms -1 for 3 minutes. F = N WD = F.s = 1448 kJ

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