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Published byTerry Lambert Modified over 2 years ago

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Material Handling Material Handling System Design Important calculations

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Outline Returnable containers Space Utilization Dedicated vs. random storage

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Returnable containers Features –Stackability –Nestability Efficiency of returnable containers –Container Space Utilization = usable cube(inside)/container envelope(outside) –Storage Space Efficiency = usable cube(inside)/ storage cube(opening) –Container Nesting Ratio = container height/ nested height –Trailer Return Ratio = empty container capacity(#)/ loaded container capacity(#) usable outside

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Returnable Containers Example Trailer Transports Returnable Containers –Containers are not palletized –No clearance between containers, or between containers and walls Inside Dimensions: 18´´ x 11´´ x 11´´ Outside Dimensions: 20´´ x 12´´ x 12´´ Each Nested Container: 20´´ x 12´´ x 2´´ Inside Trailer Dimensions: 240´´ x 120´´ x 120´´

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Returnable Containers Example Container Space Utilization = usable cube (inside) / container envelope (outside) = (18´´ x 11´´ x 11´´ ) / 20´´ x 12´´ x 12´´ = 0.76 = 76% container efficiency

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Returnable Containers Example Storage Space Efficiency = usable cube (inside) / storage cube opening Assume the storage opening is 24´´ x 16´´ x 14´´ = (18´´ x 11´´ x 11´´ ) / 24´´ x 16´´ x 14´´ = 0.45 = 45% storage efficiency

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Returnable Containers Example Container Nesting Ratio = overall container height / nested height = 12´´ / 2´´ = 6 : 1 ratio Six nested containers use the same space as 1 closed container.

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Returnable Containers Example Trailer Space Utilization = space by max # containers in trailer / inside trailer dimensions –(Containers stacked vertically in one orientation) –How many containers fit in the trailer? 240´´ / 20´´ = 12 containers along the length 120´´ / 12´´ = 10 containers along the width 120´´ / 12´´ = 10 containers stacked vertically Total # of containers = 12x10x10 = 1200 Trailer space utilization = = (18´´ x 11´´ x 11´´ ) (1200) / 240´´ x 120´´ x 120´´ = 0.76 = 76% trailer utilization

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Returnable Containers Example Trailer Return Ration = empty container capacity(#)/ loaded container capacity(#) How many empty containers fit in the trailer? –One stack of empty containers = 1 + (120´´ - 12´´) / 2´´ = 55 –Total # of empty containers per trailer = 55 x (240´´ / 20´´) x (120´´ / 12´´) = 6600 Trailer return ratio = = 6600 / 1200 = 5.5 = 5.5 full trips for every 1 return trip Do we want to increase or decrease the Trailer Return Ratio?

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Storage policies are also used to assign slots to SKUs Dedicated (or Fixed Slot) Storage A fixed number of slots is kept for each SKU How many slots do we assign for each SKU?

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Randomized (Open or Floating Slot) Storage does not assign fixed positions to SKUs SKUs are stored in the closest open slot Total number of slots must be equal to the maximum aggregate inventory More difficult to control

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Class-based storage is a mixture of Fixed-Slots and Randomized storage ? ? Product families (classes) get fixed sections Inside the section, SKUs are treated as randomized Advantages? Which of the three uses less slots?

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Let’s see which policy uses less space Max SKU1: 4 Max SKU2: 5 Max Agg: 6

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Space Utilization - Storage patterns Honeycomb Loss Space you can’t use Storing a different SKU would block access Storing the same SKU would make FIFO difficult Cube Utilization = Load Cubic Volume Storage Area Cubic Volume Higher cube utilizationLower accessibility

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Let’s see an example (Problem 7.30, p. 463) 42” 36” 6” 48”Pallet and Load dimensions

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Front view 48” 6” 42” 4” 42” 4” 3” 4” Four tiers

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Upper View Flue: 15” Aisle: 4.25’ Palletized loads are stored one deep What is the cube utilization of this storage arrangement?

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First, let’s calculate the volume of the load (including pallets) Load Volume = Height x Width x Depth Height = 4 x (6” + 48”) = 216” Width = 3 x 42” = 126” Depth = 1 x 36” = 36” Load Volume = 216 x 126 x 36 = 979,776 inches 3

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Now, let’s find the volume of the storage space Storage Volume = Height x Width x Depth Height = 4 tiers x (pallet + load + clearance + beam) Width = ½ beam + pallets + clearances + ½ beam Depth = ½ flue + pallet + ½ aisle

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Now let’s find the cube utilization Storage Volume = 244” x 145” x 94.5” = 3,343,410 inches 3 Cube Utilization = = 29.3% 979,776 3,343,410

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In the additional handout there are some examples of typical rack configurations

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