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Oct. 30, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation.

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Presentation on theme: "Oct. 30, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation."— Presentation transcript:

1 Oct. 30, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation to apply in each situation Homework 1. Pages 4-6

2 CHAMPS for Bell Ringer C – Conversation – No Talking H – Help – RAISE HAND for questions A – Activity – Solve Bell Ringer on binder paper. Homework out on desk M – Materials and Movement – Pen/Pencil, Notebook or Paper P – Participation – Be in assigned seats, work silently S – Success – Get a stamp! I will collect!

3 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

4 4 MINUTES REMAINING…

5 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

6 3 MINUTES REMAINING…

7 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

8 2 MINUTES REMAINING…

9 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

10 1minute Remaining…

11 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

12 30 Seconds Remaining…

13 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

14 BELL- RINGER TIME IS UP!

15 October 30th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: 1.How many quantities did we underline in each problem? 2.How many known variables are you given in each problem? 3.How many unknown variables are you asked to find in each problem? 4.How do you decide what equation to use? 5.What do the equations mean to you?

16 Shout Outs Period 5 – Chris Period 7 – Latifah, Shawn

17 Oct. 30, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation to apply in each situation Homework 1. Pages 4-6

18 Week 8 Weekly Agenda Monday – Kinematic Equations I Tuesday – Kinematic Equations II Wednesday – Kinematic Equations III Thursday – Review Friday – Review Unit Test next week!

19 What are equations? Equations are relationships. Equations describe our world. Equations have changed the course of history.

20 CHAMPS for Problems p. 4-6 C – Conversation – No Talking unless directed to work in groups H – Help – RAISE HAND for questions A – Activity – Solve Problems on Page 4-6 M – Materials and Movement – Pen/Pencil, Packet Pages 4-6 P – Participation – Complete Page 4-6 S – Success – Understand all Problems

21 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

22 Solving Problems: THE EASY WAY (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds vf = ?

23 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

24 Solving Problems: THE EASY WAY (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsvf = ? v f = v i + a Δ t

25 Solving Problems: THE EASY WAY (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsvf = ? v f = v i + a Δ t v f = 0 m/s + (3 m/s 2 )(10 s) =

26 Solving Problems: THE EASY WAY (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsvf = ? v f = v i + a Δ t v f = 0 m/s + (3)(10) = 30 m/s

27 Solving Problems: THE EASY WAY (p. 4 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsΔx = ? Δx = v i Δt + aΔt 2 2

28 Solving Problems: THE EASY WAY (p. 4 ) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsΔx = ? Δx = v i Δt + aΔt 2 2 Δx = (0)(10) + (3)(10) 2 2

29 Solving Problems: THE EASY WAY (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/sa = 3 m/s 2 Δt = 10 secondsΔx = ? Δx = v i Δt + aΔt 2 2 Δx = (0)(10) + (3)(10) 2 2 Δx = 0 + 150 m = 150 m

30 Solving Problems: THE EASY WAY (p. 4 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/sa = 40,000 m/s 2 Δx = 0.5 mvf = ?

31 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

32 Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/sa = 40,000 m/s 2 Δx = 0.5 mvf = ? v f 2 = v i 2 + 2a Δx

33 Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/sa = 40,000 m/s 2 Δx = 0.5 mvf = ? v f 2 = v i 2 + 2a Δx v f 2 = (0) 2 + 2(40,000)(0.5)

34 Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/sa = 40,000 m/s 2 Δx = 0.5 mvf = ? v f 2 = v i 2 + 2a Δx v f 2 = (0) 2 + 2(40,000)(0.5) v f 2 = 40,000 v f = 200 m/s

35 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ?

36 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

37 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

38 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t

39 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t 0 = 20 + 4a

40 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t 0 = 20 + 4a

41 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t 0 = 20 + 4a -20 + 0 = 20 + 4a + -20 -20 = 4a

42 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t 0 = 20 + 4a -20 + 0 = 20 + 4a + -20 -20/4 = 4a/4

43 Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ? v f = v i + a Δ t 0 = 20 + 4a -20 + 0 = 20 + 4a + -20 -20/4 = 4a/4 a = -5 m/s 2

44 Solving Problems (p. 5) 5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop? vi = 20 m/s vf = 0 m/s Δt = 4sΔx = ?

45 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

46 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

47 Solving Problems (p. 5) 5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop? vi = 20 m/s vf = 0 m/s Δt = 4sΔx = ? Δx = (v f + v i )Δt 2

48 Solving Problems (p. 5) 5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop? vi = 20 m/s vf = 0 m/s Δt = 4sΔx = ? Δx = (v f + v i )Δt = (0 + 20)(4) = 40 m 22

49 Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time?

50 Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time? vi = 0 m/s a = 100,000 m/s 2 Δt = 4s Δx = ?

51 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

52 Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

53 Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time? vi = 0 m/s a = 100,000 m/s 2 Δt = 4s Δx = ? Δx = v i Δt + aΔt 2 = 2

54 Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time? vi = 0 m/s a = 100,000 m/s 2 Δt = 4s Δx = ? Δx = v i Δt + aΔt 2 = (0)(4) + (100,000)(4) 2 2

55 Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time? vi = 0 m/s a = 100,000 m/s 2 Δt = 4s Δx = ? Δx = v i Δt + aΔt 2 = (0)(4) + (100,000)(4) 2 2 Δx = 800,000 m

56 Solving Problems (p. 5) 7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s 2. What can the officer estimate the original speed of the car?

57 Solving Problems (p. 5) 7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s 2. What can the officer estimate the original speed of the car?

58 Solving Problems (p. 5) 7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s 2. What can the officer estimate the original speed of the car? Δx = 10 m a = -45 m/s 2 vf = 0 m/s vi = ?


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