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Usage Guidelines for Jeopardy PowerPoint Game Game Setup Right now, Click File > Save As, and save this template with a different file name. This will keep the template untouched, so you can use it next time! Scroll through the presentation and enter the answers (which are really the questions) and the questions (which are really the answers). Enter in the five category names on the main game board (Slide 4). Game Play Open 2 nd Slide, let the sound play. Click to 3 rd Slide, let the sound play. Click to 4 th Slide and show students the Game Board As you play the game, click on the YELLOW DOLLAR AMOUNT that the contestant calls, not the surrounding box. When the student answers, click anywhere on the screen to see the correct answer. Keep track of which questions have already been picked by printing out the game board screen (Slide 4) and checking off as you go. Click on the “House / Home Icon” box to return to the main scoreboard. Final Jeopardy – Go to Slide 3 and click “Final Jeopardy” button in the bottom right corner, click again for the Question, click again for final jeopardy sound, When that is finished playing click again for the answer slide.

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200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 ???

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200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 200 300 400 500 100 Definitions 1Definitions 2 Limiting Reactants Percent Yield LR/PY Potpourri

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This unit of measurement is equivalent to the number of particles in 12.00 grams of Carbon 12. Definitions 1 Q100

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Mole Definitions 1 A100

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The amount of product that would result if all the limiting reactant was used based on stoichiometry. Definitions 1 Q200

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Theoretical Yield Definitions 1 A200

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Used to calculate how close the theoretical and actual yield are. Definitions 1 Q300

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Percent Yield Definitions 1 A300

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The substance that is not used up completely in the chemical reaction. Definitions 1 Q400

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Excess Reactant Definitions 1 A400

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What is the formula for calculation of percent yield? Definitions 1 Q500

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(actual yield/theoretical yield) x 100. Definitions 1 A500

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The reactant in the chemical equation that caps the amount of product that can form. Definitions 2 Q100

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Limiting Reactant Definitions 2 A100

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Relationships between the relative ratios of substances in balanced chemical equations and using them to calculate mass to moles, moles to mass, and mass to mass. Definitions 2 Q200

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Stoichiometry Definitions 2 A200

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DAILY DOUBLE

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Your results are more ________ if you have a higher percent yield. Definitions 2 Q300

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accurate Definitions 2 A300

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The comparison of the number of moles given by a chemical reaction and used to convert between compounds. Definitions 2 Q400

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Mole Ratio/Relationship Definitions 2 400

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The percentage that indicates how far away an experimental result is from a theoretical (accepted) result. Definitions 2 Q500

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Percent Error Definitions 2 A500

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What is the limiting reactant if 10g Cl 2 reacts with 25g HBr? Cl 2 + 2HBr 2HCl + Br 2 Molar mass of Cl 2 : 70.90 Molar mass of HBr: 80.91 Molar mass of HCl: 36.46 Limiting Reactant Q100

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Cl 2 Limiting Reactant A100

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What is the limiting reactant if 20g C 2 H 6 burns in 60g O 2 ? 2C 2 H 6 + 5O 2 2CO 2 + 6H 2 O Molar mass of C 2 H 6 : 30.08 Molar mass of O 2 : 32.00 Molar mass of CO 2 : 44.02 Limiting Reactant Q200

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C2H6C2H6 Limiting Reactant A200

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What is the limiting reactant if 55g H 2 S reacts with 70g O 2 ? 2H 2 S + 3O 2 2SO 2 + 2H 2 O Molar mass of H 2 S: 34.09 Molar mass of O 2 : 32.00 Molar mass of SO 2 : 64.07 Limiting Reactant Q300

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O2O2 Limiting Reactant A300

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What is the limiting reactant if 536g Fe 2 O 3 reacts with 21g H 2 ? Fe 2 O 3 + 3H 2 2Fe + 3H 2 O Molar mass of Fe 2 O 3 : 159.70 Molar mass of H 2 : 2.02 Molar mass of Fe: 55.85 Limiting Reactant Q400

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Fe 2 O 3 Limiting Reactant A400

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What is the excess reactant if 515g NaCl reacts with 782g AgNO 3 ? 2NaCl + Cu(NO 3 ) 2 2NaNO 3 + CuCl 2 Molar mass of NaCl: 64.44 Molar mass of Cu(NO 3 ) 2 : 187.57 Molar mass of NaNO 3 : 85.00 Limiting Reactant Q500

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Cu(NO 3 ) 2 Limiting Reactant A500

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If the theoretical yield of a reaction is 62.3g and the actual yield is 59.7 grams, find the percent yield and round to two decimal places. Percent Yield Q100

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95.83% Percent Yield A100

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If the theoretical yield of a reaction is 125.75g and the actual yield is 111.23g, find the percent yield and round to two decimal places. Percent Yield Q200

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88.45% Percent Yield A200

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If the percent yield of an equation is 56.54% and the actual yield recorded was 39.73 grams, what was the theoretical yield of the reaction? What is the percent error of the whole reaction? Percent Yield Q300

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Theoretical yield is 70.27g, percent error is 43.46% Percent Yield A300

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If the percent yield of an equation is 97.45% and the theoretical yield is 150.4 grams, what is the actual yield in the reaction? What is the percent error of the whole reaction? Percent Yield Q400

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Actual Yield is 146.7 grams and percent error is 2.55% Percent Yield A400

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Calculate the percent yield of a reaction if 4504 grams of water was produced in reality, and when calculating it based on the limiting reactant, you found that the theoretical yield was 4599 grams of water. Round to two decimal places. Percent Yield Q500

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97.93% Percent Yield A500

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Explain how you would find the percent yield of a reaction. LR/PY Potpourri Q100

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Actual Yield/Theoretical Yield x 100 LR/PY Potpourri A100

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Think of a real life example of limiting reactants. LR/PY Potpourri Q200

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Answers will vary LR/PY Potpourri A200

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How do you calculate the percent error of a reaction if the percent yield is given already? LR/PY Potpourri Q300

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Subtract the percent yield from 100% LR/PY Potpourri A300

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There are 2.62g of Mg and 11.00 grams of O 2. Given the equation: 2Mg + O 2 2MgO, identify the limiting reactant. LR/PY Potpourri Q400

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Molar mass of Mg = 24.31g Molar mass of O 2 = 32.00g. LR/PY Potpourri A400

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List the steps for calculating the limiting reactant. LR/PY Potpourri Q500

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Answers may vary slightly: 1. Balance the chemical equation 2. Pick a reactant and convert into grams of the second reactant. 3. Compare the two amounts from each reactant. *if the number is smaller, the second reactant is in excess *if the number is larger, the second reactant is the limiting reactant. LR/PY Potpourri A500

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Final Jeopardy In a lab experiment, 135 grams of aluminum react with 623 grams of iron (III) oxide to produce 349 grams of aluminum oxide. From the given information, find: 1. Limiting Reactant 2. Excess Reactant 3. Percent Yield 4. Percent Error

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Final Jeopardy Answer Limiting Reactant: Iron (III) Oxide Excess Reactant: Aluminum Percent Yield: 87.65% Percent Error: 12.35%

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