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Ion Exchange Reactions Different Motivation = Different Results!

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Presentation on theme: "Ion Exchange Reactions Different Motivation = Different Results!"— Presentation transcript:

1 Ion Exchange Reactions Different Motivation = Different Results!

2 HW: see schedule; Type of Reaction cartoon due tomorrow Do Now: 1. HW out for check/answers 2. Complete Work Packet p. 6 A. Be prepared to defend your answers Today: 1. HW answers 2. Redox Check 3. Double Replacement Rxn notes 4. Practice 5. Will They Won’t They U9D4: Double Replacement Rxn

3 Announcements Unit 9 Practice test is online Testwizard.com Class codes were sent home via SchoolTool  Period 1: CCQF-ASIM-S3  Period 2: CCQB-ASIM-R6  Period 3: CCQN-ASIM-WQ Quarterly Topic Sheet was sent home via SchoolTool Chemthink.com is a great website for review  Student code:

4 Hwk #3) REDOX Reactions Homework A) Multiple Choice Questions: Place your answer in the space in front of each question. _____1) In the reaction 2 Na + 2 HCl  2 NaCl + H 2, which species is the spectator ion? a) Na 0 b) H +1 c) Cl -1 d) Na +1 Why is this the spectator ion? Explain, in terms of ion charge. _____2) In the reaction Zn + 2 HNO 3  _________ + H 2, the missing product is a) Zn(NO 3 ) 2 b) (NO 3 ) 2 Znc) ZnNO 3 d) NO 3 Zn _____3) In the reaction 2________  2 Pb + O 2, the missing product is a) PbOb) OPbc) PbO 2 d) O 2 Pb C A A Cl - has the same ion charge as a reactant and product. It is not involved in the reaction.

5 B) Identify the type of reaction shown: Use the key S for synthesis, D for decomposition, SR for single replacement SR S D “May I cut in” 2 reactant 1 product 1 reactant 2 product

6 C) Write the charges of each species, then identify which species are oxidized, reduced and spectator ions in the following reactions: (for polyatomic ions, use the charge on the polyatomic ion) 1)Ag 2 S  2 Ag + S OXIDIZED:________ Reduced:_________ Spectator Ion:____________ 2) KBr + Na  Na Br + K OXIDIZED:___________ Reduced:____________ Spectator Ion:____________ S -2 Ag +1 none Na 0 K +1 Br

7 3) 2 Li NO 3 + Ca  Ca (NO 3 ) Li OXIDIZED:___________ Reduced:____________ Spectator Ion:___________ 4) 2 Fe + 3 Cl 2  2 Fe Cl 3 OXIDIZED:__________ Reduced:____________ Spectator Ion:___________ 5) 2 Li 2 O  4 Li + O 2 OXIDIZED:__________ Reduced:____________ Spectator Ion:__________ Ca 0 Li +1 NO3 -1 Fe 0 Cl2 0 none O -2 Li +1 none

8 D) Complete the following reactions by writing the appropriate formula(s) (Remember BrINClHOF ‘s come in pairs when alone!) NaBr Cl2 O2 N2 Li3N Cu KNO2

9 Check : Write your answers on the white board For your reaction: 1) assign the oxidation #s 2) Determine what is oxidized or reduced 3) Identify the spectator ion (write “none” if no spectator ion) 4) Identify the type of REDOX reaction: ___ A. 4Al + 3 FeO 2  2 Al 2 O Fe ox # __________ red# __________ spectator ion: _______ ___ B. Zn + 2 HCl  ZnCl 2 + H 2 ox # ________ red# _______ spectator ion: _______

10  Soluble: able to be dissolved into a solvent  Insoluble: Dissolves only to a small degree into a solvent  Solute: the material whose IMAF are overcome by and breaks up into a solvent.  Solvent: the material into which a solute may be dissolved  Precipitate: an insoluble product that exits the solution. In terms of today, the precipitate will be a SOLID. Double Replacement Reactions Relevant Vocabulary

11  Reactions in which two aqueous solutions are mixed resulting in a solid precipitate.  The cation of one solution and the anion of the other solution attract so strongly that water cannot break the ionic bond and the ionic compound formed “falls out” of solution as a solid precipitate.  AB (aq) + CD (aq)  AD (s) + CB (aq) Ion Exchange (Double Replacement) Reactions

12  Use Reference Table F to determine solubility  Soluble: can be used as a reactant in the reaction  Insoluble: is the precipitate product of the reaction Solubility

13 A) Use TABLE F to determine if the following ionic compounds are soluble or insoluble 1. Determine the cation and the anion in the compound given 2. Look up the anion on Reference Table F: it should fall in the soluble or insoluble column 3. Determine if there are any exceptions to the rule that apply a) Al(OH) 3 _______c) CaCl 2 _______ b) (NH 4 )(NO 3 ) _______ d) Mg(CO 3 ) _______ Do Now Work packet p. 6A

14 Dissolving

15 Example Double Replacement Reaction AgNO 3 (aq) + NaCl (aq)  AB + C+D AgCl+NaNO 3 (s)(aq) +1 +1

16 Example Double Replacement Reaction Ca(NO 3 ) 2 (aq) + K 3 PO 4 (aq)  AB + C+D KNO 3 +CaPO 4 (aq)(s) 3 2 ( )

17 Animation Pb(NO 3 ) 2 (aq) + 2 KI (aq)  2 KNO 3 (aq) + PbI 2 (s)

18 Making A Desired Precipitate CaCO 3 (s)  Ca CO ( ) 2 (aq) K 2 (aq) +1 NO 3 K (aq) +2NO 3 1) The reactants are two solutions, one containing the Ca +2 ion, the other containing the CO 3 -2 ion. 2) Find a – ion that will be soluble with Ca +2. 3) Find a + ion that will be soluble with CO ) Write the formula of the product (made from the spectator ions). 5) Balance the reaction.

19 Differences Between Redox Reactions and Ion Exchange Reactions REDOXION EXCHANGE Charges of species changes from one side to the other Charges of species do not change from one side to the other Spectator ion is the species that does not change charge from one side to the other Spectator ion is the species that remains in solution from one side to the other Both take reactants and turn them into products Both require writing formulas based on the charges found on the Periodic Table

20 B) With Reference Table F, predict the products and determine which is the soluble (aq) and which is the insoluble (s) product. a)CuCl 2 (aq) + Na 2 (CO 3 ) (aq)  __________ (___) + __________ (___) b) 3 K 2 (CrO 4 ) (aq) + 2 Fe(NO 3 ) 3 (aq)  _________ (____) + _________ (____) c) Na 2 (CO 3 ) (aq) + 2 Ag(NO 3 ) (aq)  _________ (____) + _________ (____) d) KCl (aq) + Ag(NO 3 ) (aq)  _________ (____) + _________ (____) Your turn…work packet p. 6B CuCO3 2 NaCl 6 KNO3 Fe2(CrO4)3 2 NaNO3 Ag2CO3 KNO3 AgCl s aq s s s

21 Up for More? Demo: Use solubility Reference Table F to predict if a ppt. will form or not?

22 1.Each of you has an ion card. (Blue : Cations. Yellow: Anions) 2.Pair up with a person with a card to form an ionic compound. (one blue/one yellow) 3.Determine if new compound is soluble or insoluble. 4. Write your new compound on the appropriate board (remember to write chemical formula correctly) 5.Return to your seat and await further instructions. You have 2.5 minutes GO! New Challenge…

23 1.Choose one compound from the insoluble column and one from the soluble column. 2.Write these compound on your white board. Be sure to write in the phase for each compound. Answer: What were the reactants for your reaction? What are the spectator ions in the reaction? Challenge Part 2

24  You will work alone on this sheet  You are to do only the questions circled on your WS.  Turn over when complete.  If time begin HW. Will They Won’t They


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